Physical liquid pressure, the pressure of a physical liquid

You're very thoughtful.

A certain point is the point at which you are preparing to measure in your experiment.

"One point" is an ideal concept with no size and no quality. However, the actual object cannot be made into a "point", but only a "body", which has a size and area. It is also impossible to make a metal box into a "point", so it can't be placed on a point. It can only be placed within one face.

So strictly speaking. The metal box measures the average pressure of the liquid on the surface of the metal box, and the average pressure of this surface is equal to the pressure of the "point" in the center of the metal box.

So, a point in the experiment is the point where the center of the metal box is located.

A point is not the highest point nor the lowest point. This point is the same point to the liquid level, as long as the distance is the same.

The distance to the liquid surface is the same, this can be done in **, the formula of liquid pressure is not gh, you can also see from the formula, the density and g are the same, only in h the same situation.

Besides, the pressure is equal, and the same h is not the same depth!

The liquid is fluid, so the pressure is equal in all directions at the same depth.

It can be thought of as having a small liquid sheet at the same depth as the liquid surface that is thin enough, as long as the pressure on it is equal in all directions.

"A point" is any point in the liquid. It refers to the point you measure during the experiment, and you can measure any point during the experiment.

As for the metal box, I know what you are talking about, why do you have to have a metal box?

If you are looking for the pressure at the highest point of the metal box, then the point is the metal and the highest point.

The center of the circle is not in direct contact with water, so the center of the circle is not affected by water pressure.

Center. The points of the sphere are superimposed at the center of the sphere.

I think so.

The pressure at the highest and central points of the box is different.

If the pressure of the box as a whole is required, the pressure on the upper and lower surfaces should be subtracted.

Isn't there a film on the metal box? \"Somewhere"Refers to the research point, which is the center of the film.

1. Idea: Through p= hg, it can be concluded that the pressure of the liquid on the bottom of the glass is 1500pa, and the pressure of the water is all applied to the table through the glass.

So the pressure of the empty glass on the table top is 1200pa

From p=f s, the gravitational force on the glass can be obtained.

Therefore, the quality of the glass is.

Step: Liquid HG 1500Pa

P cup P-P liquid 1200pa

f(g)=ps=

m=g/g＝

2. Ideas: The water pressure on the top surface of the B end is because the height of the water is the distance between A and the bottom and the distance between B and the bottom, and the water pressure generated by P Hg can be obtained from P Hg p=2000pa

By p=f s, f 4n can be obtained

Step :p = hg=2000pa

f=p/s=4n

1. Pressure Vertical Pressure Magnitude Force Area Unit Area Pressure p Pressure per unit area of the object p=f s Pascal pa 1 Pressure Force Area Pressure Force Area Pressure.

2. The gravitational force of the liquid Each depth is equal p=rgh (r should be a Greek letter, which cannot be typed, i.e. liquid density) Liquid density depth.

3. The opening is not connected, connected, not flowing, and the same height.

First of all, the question asks you about the pressure of the water on the bottom of the container, which has nothing to do with what is in the water.

As long as it is the pressure of the liquid, the formula p=density xgxh is tried, where the density refers to the density of the liquid, and h refers to the vertical height from the position to the free surface of the liquid.

After putting an object into the water, it will inevitably cause the water surface to rise, so how big h must be, from the formula p = density xgxh can be obtained that the pressure of water on the bottom of the container must increase. Note that for liquids, the formula p=f s is applicable, where f refers to pressure, but for liquids pressure f is not necessarily equal to gravity g, so general liquids can not be judged by p=g s, it is best to use p=density xgxh, your second sentence is a typical mistake made. But if the liquid is packed in a container straight up and straight down (i.e. in a cylinder container), the formula p=f s=g s is true.

The pressure increases.

When a block is placed in water, no matter whether the density of the block is greater or smaller than water, a part of the water must be discharged, and in this case, the water surface in the container will rise, so the pressure will increase.

Regardless of the density of the block, the pressure will increase according to your formula due to the rise in liquid level. Here the pressure of the water on the container is the main aspect of the contradiction.

Just use the above method to judge.

Please grasp the essence of the problem. o(∩_o~

The pressure formula is p=pgh, p is the density, it has nothing to do with the bottom area, but it has to do with the height, so the stone goes in, h is high, the pressure is strong, and p is just the density of water. As for how to calculate the stone in it, it is the volume of the stone plus the volume of water, we record it as v, let h=v s, and then use p=pgh to calculate, you know?

I don't understand.

Problem 1: If the object floats and does not sink to the bottom, the bottom pressure is related to the total weight, and if it sinks to the bottom, the contact surface is large, and the other positions are related to the height of the water. The pressure of the side wall of the container is related to the height.

Problem 2: Because objects have volume, the height of the water changes in smaller containers.

Problem 3: Liquid pressure p = density xgxh is used to calculate the hydraulic pressure of the stationary fluid. It's just the density of the water.

Question four is the same as one.

1. Key topic: The pressure of water, that is, the pressure of the liquid, p= gh The pressure of the liquid has nothing to do with the mass and volume of the liquid, and has nothing to do with the shape of the container, but only with the density and depth of the liquid.

2. "There is water in a container, and "Water" has a pressure on the container", the key question is cleared and solved with the corresponding knowledge analysis.

The depth has changed. Multiply the density of the liquid by g and then by the depth after placing the object.

Grow bigger and deeper. Don't think about anything else.