Finding the master of the liquid pressure problem. Liquid pressure problems?

If it's a cylinder or a cube, it's fine, but if it's a round table or some other irregular, it's fine.

Because the liquid produces the pressure on the bottom of the container, the wall of the container itself will also participate, and the pressure of the container on the table can generally be regarded as the pressure generated by the solid, which is divided by gravity by the bottom area, but gravity is the sum of the gravity of the container itself and the gravity of the liquid in the container.

It can't be calculated that way.

To divide the total weight by the contact area.

Total weight: The total weight of the container and water.

That p= gh is the internal pressure of the liquid, and it cannot be used here, from a general point of view.

Calculate the weight of the container including the liquid, and divide it by the area.

No need for a second part! The pressure on the stressed area of the desktop is the pressure of the desktop!

Yes, no matter what shape of container you have, you can find the liquid pressure in this way, and the container pressure depends on the shape of the container, which is a cylinder.

That's what our teacher said anyway.

Personally, I think it is: (container gravity + liquid gravity) divided by the contact area.

Move to the left because the bottom pressure is equal. For the left side of the piston, the pressure of the water is equal to the pressure of the water multiplied by the area of the piston rod. The right side is equal to the pressure of the water multiplied by the area of the piston and the pressure of the gas multiplied by (area of the piston - area of the piston rod).

As the pressure of the water increases, the gas is compressed, and the piston moves to the left.

If the far right is connected to water, the piston will move to the left.

Considering the change in the state of the confined air, when the device is placed in deep water, the pressure on the right side of the piston increases, and the left side is the original pressure, so the piston will move to the left under the action of the pressure difference. Then the air on the left side is compressed, the internal pressure increases, and the force of the straight piston is balanced until the pressure on the left and right sides is equal.

Because the air on the left is confined to the air, PV=NRT shows that the pressure P increases gradually as the volume decreases. That's why when you put it in deep water, the piston moves to the left and ends up in an equilibrium position.

Definitely, the displacement varies with different depths.

This is basically the principle of a hydraulic press. Great question.

First of all, it must be understood: the pressure of water (liquid) is directly proportional to the depth; Due to the transfer of pressure by water, any contact surface with water is subjected to the pressure of the water, and the magnitude of the pressure is equal to the pressure multiplied by the area of the contact surface.

Analyze the water pressure in the vertical direction of the container, and the vertical thin pipe is not subject to the water pressure in the vertical direction, leaving the following **.

**The inside of the plate is filled with water, observe the inside of the plate, the top (pressure direction vertical upward) and the bottom (pressure direction vertical downward) are subject to water pressure (note f1 and f2), the specific number you can calculate by yourself.

Then consider gravity and other forces to do a balance analysis of the forces of the whole container in the vertical direction. You will find that f2-f1 is equal to the gravitational force of water.

This question is not good to judge based on p= gh.

It can be judged according to the angle of force balance.

In container A, the force of the liquid on the wall of the container is:

The support force of the bottom surface, the support force of the side wall to the liquid diagonally upward, therefore, the support force of the bottom surface to the liquid must be less than the gravity of A, that is, the pressure of liquid A on the bottom of the container is less than the gravity of A.

In container B, the force exerted by the liquid on the wall of the container is:

The support force of the bottom surface, the pressure of the side wall on the liquid obliquely downward, therefore, the support force of the bottom on the liquid must be greater than the gravity of B, that is, the pressure of liquid B on the bottom of the container is greater than the gravity of B.

Since the two liquids are of the same mass, so.

Because the bottom area is the same, F A is based on the pressure p=f s

Platoon< pB.

You swap the film for a board and take it down, it's no problem at all, it's just that the force is very high. You can analyze the force of the water in the cup and the film separately (because the cup mouth area is fixed, direct pressure analysis is also possible).

First of all, the unit is unified, that is, 500 square centimeters are converted into cubic meters, because v s (volume divided by the bottom area) is equal to 5m, that is, the height of the container. Then you set the weight of the liquid to be m kilograms (10m newtons), and because p = f s, the equation is: 10m + 15n square meters = 1800p, calculate m = , and then because the volume of the bottle is cubic meters, the bottle is filled, so the volume of the liquid is cubic meters, and because the density = m v, so the final density of the liquid is cubic meters.