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1. a=-2 b=-3/4 c= calculate the value of (a+c) (4)+(a+c) b.

Original = (-2+

2、= -x/2+10+x/2-3+3y-3+4y-127y-8！98 out of 1! =（98×97×96。。。1）÷（100×99×98。。×1）

a+1|is 0, (b-1) to the power of 0.

The sum of the two parts is 0, and each part is 0

A=-1, b=1 and 2(a-b)-a's quadratic + b get -4

The first question is to look at a=-2 , b=-3/4 , c=? Or a = -2 b = -3/4 c =

If a=-2 , b=-3/4 , c=, then the three values can be substituted into the original formula =(-2+;

If a=-2 b=-3/4 c=, then from a=-2 b=-3/4 c=a=3 2,b=-3 4,c=-2, substitute these three values into (3 2-2) (4)+(3 2-2) (3 4)=8 3.

Question 2, -5 (1x-2 out of 10) + 1/2 (x-6) + 3 (y-1) -2 (-2y + 6) = -5 * (x 10-2) + (x-6) 2 + 3 * (y 1) -2 * (-2y + 6) = -x 2 + 10 + x 2-3 + 3y - 3 + 4y - 12 = 7y-8.

Question 3, 98! /100！=98/（100*99*98！）=1/9900。

Question 4, |a+1|+(b-1) quadratic = 0, so |a+1|=0, (b-1) quadratic = 0, so a = -1, b = quadratic + b = 2 (-1-1) - (1) quadratic + 1

Dizzy, you have this time to ask questions, and you have made it yourself.

x-4y=10 gives x=4y+10 and substituting x-my=5 gives 4y+5-my=0 (1).

Substituting 2x+my=1 gives 8y+19+my=0 (2) Add the equations obtained by (1) and (2) to get 12y+24=0, so y=-2 is substituted into x-4y=10 to get x=2

Substituting x and y into x-my=5 gives m=

Substituting 3x+y=4n gives n=1

Because the solution of the two systems of equations is the same, this means that these four unknowns can form a system of quaternary equations.

The second equation plus the fourth gives x=2, and the first equation gives y=-2, so n=1, m=

Regret M-3)x+2y |m-2|The power of +8=0 is the two-width element equation with respect to x,y.

So |m-2|=1 and m-3≠ Biqiao Bridge 0

So m=1

According to the principle that "if you pour out 6 kg of water in the first bucket, there will be the same amount of water in the two buckets", and the difference between the two buckets is 6 kg, so the problem is solved according to the sum and difference formula

Answer: Solution: (50+6) 2,56 2,28 (kg);

A: The first bucket was originally filled with 28 kg of water

So the answer is: 28

Solution: 50 2=25

The first bucket of water turned out: 25 + 6 = 31 kg.

Set the first bucket of water to hold x kilograms of water.

x-6=50-x

x=28

Dealer Profit (210-12) 13 — 132 12

Hotel Profit 25 — 210-12) 13

1】x=3y+1

Substituting the second equation yields 2(3y+1)+ay=-1, simplifying (6+a)y=-3

When a=-6, there is no solution.

2] The solution of the system of equations is opposite to each other, then x+y=0 is an implicit condition, and the three equations can be solved m.