Grade 6 math problems require a process

x-y|+|y-z|+|z-x|=(y-x)+(z-y)+(z-x)2z-2x

Therefore, when z takes the maximum and x takes the smallest, the formula has a maximum value, because x, y, and z are the hundreds, tens, and single digits in a three-digit number, so x cannot take 0, so the minimum value that x can take is 1, and the maximum value that z can take is 9, so 2z-2x=2x9-2x1=18-2=16x-y|+|y-z|+|z-x|=(y-x)+(z-y)+(z-x)2z-2x

Therefore, when z takes the maximum and x takes the smallest, the formula has a maximum value, because x, y, and z are the hundreds, tens, and single digits in a three-digit number, so x cannot take 0, so the minimum value that x can take is 1, and the maximum value that z can take is 9, so 2z-2x=2x9-2x1=18-2=16x-y|+|y-z|+|z-x|=(y-x)+(z-y)+(z-x)2z-2x

Therefore, when z takes the maximum and x takes the smallest, the formula has a maximum value, because x, y, and z are respectively a three-digit number in the hundreds, tens, and single digits, so x cannot take 0, so the minimum value that x can take is 1, and the maximum value that z can take is 9, so 2z-2x=2x9-2x1=18-2=16

I'll do this.

But now I kind of forgot about it.

I want to think about it first

Something like this

Yes, it must be.

You first and then in the end, it's pretty much the same, it should be.

Maybe that's fine

It adds it first and then graces this.

I'm sorry, I don't know.

Say a word to the TV shouting:

Sorry, teacher, I didn't study well! ~

Circumference of the maximum circle =

Maximum circle radius =

Maximum circle area =

The diameter ratio of a circle is 1:2:3

So the circumference ratio is: 2 :3 = 1:2:3

The circumference of the circle is the required wire length.

Then let the circumferences of the three circles be x, 2x, and 3x

x+2x+3x=

6x=x=so the circumference of the circle1.

Circle 2 circumference.

Circle 3 circumference.

Visible circle 3 is the largest.

Then 2 r=

r=r=r=3 area s = r ==

So the maximum circle area.

The diameters of the three gardens are A, 2A, and 3A

then the solution is a = 2 decimeters.

The maximum circle diameter is 3a = 6 dm.

Radius = 3 decimeters.

Area = square decimeter.

c=pi*d Let the three diameters be d, 2d, 3d, and the sum of the circumferences of the three circles =pi*(d+2d+3d)=i.e., pi*6d=

So d = decimeter) so 3d = 6

Maximum circle area = pi * (6 2) * (6 2) = square decimeters.

The Handsome Wolf Hunting team will answer for you:

There are two types of lidless trays.

Made of two squares and three rectangles, 100 cartons need 200 squares, obviously the squares are not enough;

If you use a square and 4 rectangles, you need 100 squares for 100 cartons, and you can't use up all the squares exactly.

Set up to make a kind of carton x, then make a kind of carton (100-x), 2x + (100-x) = 120, x = 20, 100-x = 80, 20 kinds of carton need to be rectangular: 3 20 = 60 sheets, kind of carton (100-20 = 80 pieces), need to be rectangular: 4 80 = 320 sheets, a total of 60 + 320 = 380 sheets of rectangle.

(1) A horizontal box needs 3 rectangles, 2 squares, and a vertical box needs 4 rectangles and 1 square.

Then: 4x+3y=320

x+2y=130

The solution yields x=50 and y=40

2) Set x vertical cartons and Y horizontal cartons. The system of equations x+y=a

4x+3y+x+2y=5x+5y=500

i.e. x+y=a=100

And since both cartons must be there, so x can be all integers from 1 to 99, so there are 99 schemes.

If it is made into a vertical type of x, then a horizontal type (100-x) pieces.

The equation is: x+(100-x)*2=120

The solution is x=80, that is, 80 vertical and 20 horizontal.

So you need rectangular cardboard: 80*4+20*3=380pcs.

Bingyun [Zizhu], hello:

In a cuboid pool with a length of 3 meters, a width of 2 meters, and a height of 2 meters, put a cylinder with a bottom circumference of 314 square decimeters, and the water surface rises by 2 decimeters, what is the volume of this cylinder? (To process).

Water surface rise: 2 dmm.

Cylindrical volume: 3 2 cubic decimeters).

The circumference of the cylindrical container is centimeters, put in a conical plumb weight and submerge it completely, the water surface rises by 6 centimeters, what is the volume of the conical plumb weight? (To process).

Container radius: cm).

Weight volume: cubic centimeters).

A cylindrical glass jar with a base diameter of 20 cm. Take a cone with a base radius of 8 cm completely into the water, and the water surface rises by 3 cm, find the volume of this cone. (To process).

Radius of the cylinder: 20 2 10 (cm).

Cone volume: cubic centimeters).

Fill a cylindrical cup with a base radius of 10 cm and submerge it in a conical weight with a base radius of 5 cm. When the plumb weight is removed from the cup, the water level of the cup drops by 5 cm, how many centimeters is the plumb weight? (To process).

Weight volume: cubic centimeters).

The height of the plumb weight is: 1570 3 (cm).

What is the ratio of the mass to the volume of a piece of starch iron that weighs 546 grams in a cylindrical container with a base area of 20 square centimeters, and the water surface rises by centimeters? (To process).

Iron block volume: 20 cubic centimeters).

The ratio is: 546: 70 grams of cubic centimeters).

1. The title is wrong: "Put a cylinder with a bottom circumference of 314 square decimeters," how can the perimeter be "square decimeter"?

Moreover, this data is not used, the volume of the cylinder is: 3 2 cubic meters) 2, the radius of the cylindrical container: cm).

Conical weight volume: cubic centimeters).

3. The radius of the glass cylinder: 20 2 10 (cm).

Cone volume: cubic centimeters).

4. Plumb weight: cubic centimeters).

The plumb weight height is:1570 (cm).

5. Starch iron block volume: 20 cubic centimeters).

The ratio is: 546:70 grams cubic centimeters).

1. Water surface rise: 2 decimeters.

Cylindrical volume: 3 2 cubic decimeters).

2. Container radius: cm).

Weight volume: cubic centimeters).

3. The radius of the cylinder: 20 2 10 (cm).

Cone volume: cubic centimeters).

4. Plumb weight: cubic centimeters).

The height of the plumb weight is: 1570 3 (cm).

5. Iron volume: 20 cubic centimeters).

The ratio is: 546: 70 grams of cubic centimeters).

1.The volume of the cylinder is equal to the volume of the rising water v = cubic meter.

Solution: 1:1 4 2 9 9 8

102 8 17 48 (person) ......The number of people in the computer group is 102 9 17 54 (people) ......The number of people in the art group is 2: 1, 12, 1, 20, 1, 30

1 5 1 30 6 (days).

3:3 15 18 (day).

3 10 (1 12 1 15) 2 (day) ......The number of days of cooperation between A and B is 2 days) ......The total number of days B did it.

3 10 (1 6 1 10) days) ......The number of days that A does it alone.

The landlord seems to be lazy?

1: Set the art group x, the computer group y, then the title of 2x 9 = y 4 x + y = 102

The solution is x=54 y=48

Do the rest yourself

The number of people who subscribe to the "Mathematics Newspaper for Primary School Students": 3 4x40 = 30 (people).

Number of people who subscribe to "Chinese Learning for Primary School Students": 4 5x40 = 32 (people).

The number of people in both categories: 30 + 20-40 = 22 (people).

Suppose there are x people who only set the math newspaper, there are y people who only set the language newspaper, and there are z people who both set the math newspaper.

x+y+x=40

x+z=3/4*40

y+z=4/5*40

Simultaneous solution yields x=6 y=8 z=24, so there are at least 24 people who have both of them.

40*3 4=30 (person).

40*4 5=32 (person).

30 + 32 - 40 = 22 (people).

A: At least 22 people for both?

40 times 4/5 plus 40 times 3/4 minus 40 equals 22

According to the product of the inner term equal to the product of the outer term, it can be obtained:

1)4:x=:1

x=82)7:x=13:1

13x=7x=7/13

4:x= Divide both sides of the equation by 4 to get x=

7: x=13 Divide both sides of the equation by 7 at the same time to get x=13 7