Distress! Please C language master!

#include

main()

long i;

for(i=1;(i*i*i*i*i*i)<999999;i++)if((i*i*i*i*i*i)>=100000)printf("%ld",(i*i*i*i*i*i));

return 0;

A number z, which is the square of x, is the cube of y, finds such a number.

y/x=y=n*n;

x=n*n*n;

So z=y*y*y=x*x=n*n*n*n*n*n*n;

This is also a nonsense, expecting the master to give an algorithm.

It should overflow with an int type.

At least for a long time, I think it's ......

#include

main()

long i,j,k;

for(i=100000;i<1000000;i++)for(j=1;j<=sqrt(i);j++)if (j*j==i){

for(k=1;kprintf("The numbers that meet the conditions are: %d, which is the square of %d, is the cube of %d; ",i,j,k);

Running result: The numbers that meet the conditions are: 117649, which is 343 square, is 49 cubic;

The numbers that meet the conditions are: 262144, which is 512 squared, is 64 cubic;

The numbers that meet the conditions are: 531441, which is 729 squared, is 81 cubic;

Why does this need to be discussed?

"!" in c" is a non-operation in a logical operation.

It is a non-operator in C, and when used in front of a variable, a non-arithmetic expression is constructed, and the result of the expression is a boolean value (i.e., only true or false). When using a variable, if the variable is not a Boolean data type, it will be forcibly converted to a Boolean type and then used, for example, the integer variable 123 will be converted to true, and the integer variable 0 will be converted to false.

put sum=sum+x; After moving to }, x=1; Former.

It's too complicated to write, as follows.

That's it. Genus – int main(void).

Classic examples of the C language are 1+2!+3!+.20!of and.

After reading your program, you also circled me.

I dizzy. 1. According to your idea, from 1 to n, create a loop (cyclic variable t), and then create an inner loop (cyclic variable i), which is used to calculate the factorial of t, and then add it up (variable sum), and you're good to go.

The idea is relatively clear, but there are a few mistakes:

1. A[100] is here to make trouble, right? Remove! By the way, replace a[t]=t with x=1,i2、sum=sum+x are misplaced.,How much do you want to add.。 Move it to x=1 and replace x=1 by the way, there is already one in front of it.

That might be the case. The procedure is:

main()

printf(“%d”,sum);

Second, its practical cycle can solve the problem and greatly simplify the procedure:

main()

printf(“%d”,sum);}