Urgent!! Ask for help from the C language master! Get on your knees and beg for programming!

prob : prime

author: cnyali

include contains standard I/O header files;

int main(){ The main program starts; }

freopen(" ", " w ", stdout);

Open the file in a writable state;

int i, j;i,j are cyclic variables;

int n;n is shown in the title;

int p;p is whether a number divisible by i has been found;

p=1: found;

p=0: not found, then this i is prime;

scanf("%d", &n);Enter n;

for( i=2; i<=n;i++) from 2 to n, each number is i;

p = 0;Initialization p is 0;

for( j=2;jif( i % j ==0 ){ determine whether i divides j by the remainder is 0; }}

p=1;If it is 0, find a number that is divisible;

So let p be 1;

break;Interrupt the enumeration and jump out of the loop;

if(p==0) if you find no divisible number for each number of 2 i-1;

printf("%d ",i);then print this number;

Come to an end; If you graduated from elementary school, you will definitely be able to understand it, the stupidest way, and the one with high efficiency.

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1. Fill in the blanks.

1. The C program development platform is composed of three parts: C environment, C standard library and C. , compile, connect.

5. From a macro point of view, the source C file is composed of characters and numbers.

2. Multiple choice questions.

11. If the ASCII code of the letter A is known to be a decimal number 65 and C2 is a character type, the statement C2= is executed'a'+'6'-'3';, the value in C2 is (b).

a) d b) 68c) indeterminate value d) c12, of the following four options, the option for which all of the user identifiers are invalid is (c).

a）ba 、x_0、do

b）float、1a0、_y

c）x-y、goto、123

d）_123、tmp、char

13. The following characters are carriage returns, and the newline characters are (a).

a) b v c a d f14, the correct string constant below is (c).

a） 'a' b）'376' c）"\" d）376

15. The expression that can represent the condition 0 x 100 is (d).

a) 0<=x<=100 b)x>=0,x<=100c)0 x 100 d)x>=0&&x<=100 5. Read the program write result.

1、main()

Such statements may be different on different platforms.

Output 5a5

This little problem of yours still needs to be looked at by someone who is proficient!!

The first item (2010-201 1) and the tenth item (2010-201 19) are added to give the result of zero.

The second item is added to the ninth item, and the result is zero.

The third item is added to the eighth item, and the result is zero.

The fourth item is added to the seventh item, and the result is zero.

The fifth item is added to the sixth item, and the result is zero.

So, the five zeros are added together, and the result is zero.

There are 10 formulas in total.

2010*10-201*（1+3+5+..19) 1 + 19 = 3 + 17 = in parentheses....A total of 5 20

0 didn't understand and asked. Welcome to adopt. Your adoption is my motivation. Good luck with your studies.