What a problem!! Ask the master to help

Three-quarters x multiplied by three-quarters y equals nine-sixteenths xy, a decrease of seven-sixteenths, ie.

1/a+1/b+1/c=(ab+bc+ca)/abc=ab+bc+ca

a+b+c) squared = a square + b square + c square + 2ab + 2bc + 2ca that is, 0 = a square + b square + c square + 2 (ab + bc + ca) from the question a, b, c are not 0, so a square + b square + c square is greater than 0, so 2 (ab + bc + ca) is a negative number, that is to say, 1 a + 1 b + 1 c is a negative number.

1. In the algebra xy2 (referring to the quadratic of xy), the values of x and y are reduced by 25% each, then the algebraic equation (d).

a 50 per cent reduction b 75 per cent reduction

c Decrease 37/64 of its value d Decrease 272/64 of its value, the real numbers a, b, c satisfy a+b+c=0, and abc=1 then the value of 1/a plus 1/b plus 1/c (a).

a positive number b 0

c Negative d positive and negative indefinite.

Please write the answer and process!!

I can't do the first question, so it's good to pick a d, it looks pretty cool!

The second question is C

a+b+c) the quadratic of 0 (both squares) a+b+c) the quadratic result is +2ab+2bc+2ac, which in turn is obtained from abc=0:

1 a+1 b+1 c bc+ac+ab abc (general score), so the problem is to find the value after the general score (abc = 1), the quadratic of a + the quadratic of b + the quadratic of c is a positive number that must be greater than 0, and if you move the equation a little, you can get a negative number in the end!

1 No answer, the question is wrong).

Algebraic formula: (xy) 2

Unless: [x(y) 2].

Select C2 A=1 BC B+C=-A

1 b+1 c=(b+c) bc=-a*a (negative) 1 a+1 b+1 c=1 a-a 2

If the absolute value of a is greater than 1, select c

1．c75%x*(75%y)^2=(3/4)x*(9/16)y^2=(27/64)xy^2

2. d1/a + 1/b + 1/c= (a+b)/ab + 1/c = (-c)/(1/c) +1/c

c^2 + 1/c

The symbol is determined by C and can be positive or negative.

For a detailed explanation,

2. If you mean the square of xy, you are wrong, if you are squared by y, you should choose c(1-1 4)x (1-1 4)y2, and 2 will be (1-1 4)y.

Select C to get the square of a + the square of b + the square of c + 2ab + 2ac + 2bca square + b square + c square = - (2ab + 2ac + 2bc) 1 a + 1 b + 1 c bc + ac + ab abc = bc + ac + ab less than 0

1. It should be x(y)2, and the result is c. x(y)2-(3/4)x.(3/

A +1 b +1 c = (ab + bc + ac) (abc ) knows abc = 1, then the value of ab + bc + ac is required. A2+B2+C2+(Ab+BC+AC)=0 from A+B+C=0, because A2+B2+C2 is positive, then AB+BC+AC is negative, choose C.

z'=(

z'= Select D

a+b) 2-b 2-c c is not certain, so choose d

1:c2:c

abc=1 Then two of a, b, and c must be negative.

a+b+c=0 then b=-a-c, let b be a positive number, set a random number as 2, let a and c be -1 and -1 respectively, then the value of the problem is negative.

1 3x 4*(3y 4)2=27xy2 64 This is the reduced value, so subtracting the current value from the original value is equal to c.

2 1/a+1/b+1/c=a+b+c/abc=0/1=0

So the answer is b

abcdefg lalala hijklmn lalala opqrst lalala uvwxyz lalala xyz,now you say?I can say my abc lalala hahaha.

Halo Faint when you see a math problem!!

Even if you can do it, you're dizzy!

This thing only needs the first formula, and the last two are wasted, and the constant establishment (tell me the range if you want to solve it).

<> due to the number of brigades on the nuclear bridge and the number of transportation to seek guidance and change the stool.