a b ab 54 finds the value of a b

It is to find the maximum value of a+b, because ab (a+b) 4, then we can get, 54=a+b+ab a+b+[(a+b) 4], let a+b=t, we can get t 4 +t-54 0 to solve this inequality.

a+b+ab=54

a+b(a+1)=a+1+b(a+1)-1=(a+1)(b+1)-1=54

That is, (a+1)(b+1)=55=5x11 or 1*55 Since ab is a positive integer, (a+1)=5, (b+1) =11, so a+b=4+10=14

Solution: a+b+ab=54;

a(1+b)+b=54

a(1+b)+b+1=54+1

a(b+1)+1(b+1)=55

a+1)(b+1)=55

If ab is a positive integer (if it is not an integer, it may be a decimal or a negative number, then the same method is used to extrapolate), then if the conditions can be satisfied:

a+1)(b+1)=5*11 or 11*5, that is, when a+1=11, b+1=5, a=10, b=4;

a+1=5, b+1=11, a=4, b=10;

Then a+b=14;

There should be a restriction, I think it should be a, b is a natural number.

a+b+ab=48;

a+b+ab+1=49;

a+1)(b+1)=49;

a+1=7,b+1=7;Get a=6, b=6.

or a+1=1,b+1=49;We get a=0, b=48.

or a+1=49,b+1=1;We get a=48, b=0.

Depending on the first part of the formula and the result, there is a quiet rent.

a+a+a+b+b=56

3a+2b=56①

Then according to the formula posture after the part and the result of the trace before, there is.

4+a+a+b+b+b=56

2a+3b=56-4=52②

3- 2, get:

9a-4a=168-104

5a=64a=b=

It is known that the high handicap is in the middle: a=b+4, slip section.

3 (b + 4) + 2b qishan 56

Find: b 44 5, a 44 5 + 4 64 5

Rewrite the first equation as b=4-a, and then substitute it into the second equation to get :

a(4-a)=8

After the transformation of Tong Chajian, we get:

a²-4a+8=0

Using the root finding formula, we get:

a=2±2i

Because the title does not specify the range of hail hole values for a and b, there are two sets of solutions: a=2+2i, b=2-2i or a=2-2i, b=2+2i.

It can be seen that a and b are both complex numbers, not real numbers. Therefore, if the problem requires a and b to be real numbers, then the system of equations has no solution.

a+b=4 (1)

ab=8 (2)

sub (2) into (1)

a+8/a =4

a^2-4a+8=0

a, to the world b) there is no real rise in the nuclear quarrel digging solution.

3a+2b=54 2a+3b=56 5a+5b=54+56 Divide by 5.