Does anyone know this integral question?An integral question?

Updated on educate 2024-06-11
11 answers
  1. Anonymous users2024-02-11

    Replace the method with a variable to integrate, give the key steps, and finally you can calculate the answer.

  2. Anonymous users2024-02-10

    As shown in the figure below, the partial integration is used at first, and then the commutation method is used.

  3. Anonymous users2024-02-09

    This is an anomalous integral x that tends to be e, and the denominator of the integrand tends to 0, so the limit is used.

  4. Anonymous users2024-02-08

    Let (2e y-3e) = u, then e y = (u 2+3e) 2, y = ln(u 2+3e)-ln2

    dy = 2udu (u 2+3e), get.

    i = 2∫[1+ln2-ln(u^2+3e)]du/(u^2+3e)

    2(1+ln2)∫du/(u^2+3e) -2∫ln(u^2+3e)]du/(u^2+3e)

    2(1+ln2)/√(3e)]arctan[u//√(3e)] 2∫ln(u^2+3e)]du/(u^2+3e)

    Let u = (3e)tanv, then du = (3e)(secv) 2dv

    i1 = ∫ln(u^2+3e)]du/(u^2+3e)

    ln[3e(secv)^2]√(3e)(secv)^2dv/[3e(secv)^2]

    1/√(3e)]∫ln[3e(secv)^2]dv = [1/√(3e)]∫ln(3e)-2ln(cosv)]dv

    vln(3e)/√(3e) -2/√(3e)]∫ln(cosv)dv

    vln(3e)/√(3e) -2/√(3e)]vln(cosv) +2/√(3e)]∫v(-sinv)/(cosv)]dv

    vln(3e)/√(3e) -2/√(3e)]vln(cosv) -2/√(3e)]∫vtanvdv

    It doesn't seem to be possible to express ?

  5. Anonymous users2024-02-07

    Simplify the denominator first.

    The numerator is 1-y?If it is 1+y, it is very easy to do, and you can use the commutation method d(ye) to exchange the yuan.

  6. Anonymous users2024-02-06

    Using the partial integration method, find the original function for sin and the derivative for x 2.

  7. Anonymous users2024-02-05

    <> this question uses the partial integration method, and the calculation of the sensitive file is as follows: x 2sinxdx=- x 2dcosx=-x 2cosx+ cosx*2xdx=-x 2cosx+2 xdsinx=-x 2cosx+2xsinx-2 sinxdx=-x 2cosx+2xsinx+2cosx+2cosx+c

  8. Anonymous users2024-02-04

    You can change the order of the integrals, starting with the Y Integral. It should be simpler.

    If you have any questions, please point them out.

  9. Anonymous users2024-02-03

    You're already wrong in the first step, you're using the x-power of e to derive, right?Then you should use cosx for guidance.

  10. Anonymous users2024-02-02

    The detailed procedure RT is shown ......Hope it helps....Work something out.

  11. Anonymous users2024-02-01

    I don't know which question you're referring to, the question on the right is not fully photographed, and the right side is not visible.

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