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Replace the method with a variable to integrate, give the key steps, and finally you can calculate the answer.
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As shown in the figure below, the partial integration is used at first, and then the commutation method is used.
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This is an anomalous integral x that tends to be e, and the denominator of the integrand tends to 0, so the limit is used.
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Let (2e y-3e) = u, then e y = (u 2+3e) 2, y = ln(u 2+3e)-ln2
dy = 2udu (u 2+3e), get.
i = 2∫[1+ln2-ln(u^2+3e)]du/(u^2+3e)
2(1+ln2)∫du/(u^2+3e) -2∫ln(u^2+3e)]du/(u^2+3e)
2(1+ln2)/√(3e)]arctan[u//√(3e)] 2∫ln(u^2+3e)]du/(u^2+3e)
Let u = (3e)tanv, then du = (3e)(secv) 2dv
i1 = ∫ln(u^2+3e)]du/(u^2+3e)
ln[3e(secv)^2]√(3e)(secv)^2dv/[3e(secv)^2]
1/√(3e)]∫ln[3e(secv)^2]dv = [1/√(3e)]∫ln(3e)-2ln(cosv)]dv
vln(3e)/√(3e) -2/√(3e)]∫ln(cosv)dv
vln(3e)/√(3e) -2/√(3e)]vln(cosv) +2/√(3e)]∫v(-sinv)/(cosv)]dv
vln(3e)/√(3e) -2/√(3e)]vln(cosv) -2/√(3e)]∫vtanvdv
It doesn't seem to be possible to express ?
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Simplify the denominator first.
The numerator is 1-y?If it is 1+y, it is very easy to do, and you can use the commutation method d(ye) to exchange the yuan.
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Using the partial integration method, find the original function for sin and the derivative for x 2.
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<> this question uses the partial integration method, and the calculation of the sensitive file is as follows: x 2sinxdx=- x 2dcosx=-x 2cosx+ cosx*2xdx=-x 2cosx+2 xdsinx=-x 2cosx+2xsinx-2 sinxdx=-x 2cosx+2xsinx+2cosx+2cosx+c
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You can change the order of the integrals, starting with the Y Integral. It should be simpler.
If you have any questions, please point them out.
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You're already wrong in the first step, you're using the x-power of e to derive, right?Then you should use cosx for guidance.
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The detailed procedure RT is shown ......Hope it helps....Work something out.
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I don't know which question you're referring to, the question on the right is not fully photographed, and the right side is not visible.
arcsiny)'=(1-y 2) (1 2) This is easy, and then the integration gives the formula arcsiny. >>>More
Answer: Let f(t)=t(1-2t)(1-3t) t [0,1].
It is advisable to let f(t)=t(1-2t)(1-3t) a(3t-1) be established in [0,1] constantly, and determine a first >>>More
The original amount of wine in the pot is required, and the change of the wine in the pot and the final result - three times multiplied (multiplied by 2) and quantitatively minus (** bucket) and light. To solve this problem, we generally start from the result after the change, and use the mutual inversion relationship of multiplication and division, addition and subtraction, and gradually reverse the reduction. "Three encounters with shops and flowers, drink up the wine in the pot", It can be seen that there is a wine bucket in the pot when the three encounters the flower, then there is a wine bar 1 2 buckets when the three encounters the shop, then, there is a wine 1 2 + 1 bucket when the second encounter flower, and there is a wine (1 2 + 1) 2 bucket when the second encounter shop, so there is wine (1 2 + 1) 2 + 1 bucket when the flower is encountered, and there is wine when there is a store when the store is encountered, that is, the calculation formula of the original wine in the pot is. >>>More
From the figure, 20° represents 20°W, 70° represents 70°E, 160° represents 160°E, that is to say, 70°E is located in the middle of 20°W and 160°E, because the relationship between the morning and dusk lines and the equator is bisected with each other, so the intersection of the meridian and the equator where 70°E is located is the intersection of the morning line and the equator, that is to say, 70°E is 6:00, (because the line given in the figure is the morning line). If you want to find Beijing time, you can only ask for 120°E local time, the difference between 70°E and 120°E is 50°, which is equivalent to 3 hours and 20 minutes, and 120°E is in the east of 70°E, according to the principle of east plus west minus, the Beijing time is 9:20
Note r0=2i+2j+k
r(t)-r0|^2=(cost/sqrt2+sint/sqrt3)^2+(-cost/sqrt2+sint/sqrt3)^2+(sint/sqrt3)^2 >>>More