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Set: purchase A x unit, purchase B y unit, purchase C z unit.
Option 1: Purchase A and B, with x+y=50, 1500x+2100y=90000
The solution yields x=25, y=25;
Scheme 2: Purchase A and C, with x+z=50, 1500x+2500z=90000
The solution is x=35, z=15;
Plan 3: Purchase B and C, with y+z=50, 2100y+2500z=90000
The solution is y=, z=. (does not fit the topic, discard).
Answer: There are two schemes, the first one: purchase 25 units of A and 25 units of B. The second type: purchase 35 units of A and 15 units of C.
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Let A: X B: Y C: Z
Option 1: Purchase A and B, with x+y=50, 1500x+2100y=90000
The solution yields x=25, y=25;
Scheme 2: Purchase A and C, with x+z=50, 1500x+2500z=90000
The solution is x=35, z=15;
Plan 3: Purchase B and C, with y+z=50, 2100y+2500z=90000
The solution is y=, z=. (does not fit the topic, discard).
The profit in question 2 can be calculated based on the above two scenarios.
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Solution: Let A be x and B be (50-x).
1500x+(50-x)2100=90000 gives x=25
So both A and B are 25
The above is one of a kind. It can also be A-C, B-C. The same method is calculated, and the result is an integer.
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1500x+2100(50-x)=90000 No solution.
1500x+2500(50-x)=90000x=25 A 25 pieces C 25 pieces.
2100x+2500(50-x)=90000 solution is a fraction and is not eligible.
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Design: bolt workers x people.
From the meaning of the title, it can be seen that 12x=[18*(28-x)] 2[504-18x] 2=12x
252-9x=12x
21x=252
x = 12 bolt workers have 12 people.
Nut worker: 28-12 = 16 (people).
ps.Checked and correct].
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I don't use the method of solving equations, but I do the math
If two nuts are treated as one nut, a person can only produce 9 nuts a day, because two females are against one bolt.
So the number of people who produce nuts The number of people who produce bolts = 12 9 = 4 If 34 people produce nuts, 3 people will produce bolts.
That's a group of 7 people.
28 people can be divided into 4 groups.
So the number of people who produce nuts is 4*4=16
The number of people who produce bolts is 3*4=12
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Solution: Set x workers to produce nuts.
2*12x=18(28-x)
x=12A: 12 workers produce nuts.
Hope it helps!
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Using the binary system of equations, let the number of people producing bolts be x and the number of nuts produced is y, then there is 2*12x=18y (the meaning of one bolt with two nuts); Due to the number of people, there is x+y=28 by.
2*12x=18y
x+y=28
The solution yields x=12, y=16
That is, 12 people should be allowed to produce bolts and 16 people to produce nuts.
Can you read it?
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Set the bolt worker x and the nut worker 28-x
12x=18*2*(28-x)
48x=1008
x=21
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Set up the production of bolts x people, the production of nuts y people.
x+y=28
12x=9y one bolt with two nuts, so, to produce 18y nuts, 9y is the total number of bolts.
The solution yields x=12, y=16
A: There are 12 people in the production of bolts and 16 people in the production of nuts.
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Hello: It is our pleasure to solve the problem, we will try our best to solve your problem, unfortunately I will not.
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If x people produce bolts, then the production of nuts has 28-x 12x*2=(28-x)*18 x = 12 of the solution equation A: 12 people produce bolts and 16 people produce nuts.
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12 people produce bolts and 16 people nuts.
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The product can be discounted at a minimum.
3000x=2000×(1+5℅)
3000x=2000+100
3000x=2100
x=2100÷3000
x = equivalent to 7% off.
This item can be discounted at a minimum of 7%.
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Set the price to be $x.
x-2000) 2000 is greater than solution x=2100
2100 3000= Minimum 7% off.
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You can first set it to be sold at x discount, so that you can list the formula, selling price = selling price.
200(1+5%)=300x
Will you solve this equation?
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If it is sold at x discount, the selling price can be expressed as 300x 10 yuan, and the equation can be obtained.
300x/10=200(1+5%)
Get x=7
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Set the price of this product after the discount is X yuan, which is sold at a Y discount, so according to the title:
x-200)/200*100%=5%
Get x=210 (yuan).
y=210/300=
A: This item is sold at 7% off.
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Solution: The profit margin is 5%.
The actual sales price is 200 (1+5%) = 210 (yuan) 210 300 = 7 10
Seven percent off. A: This item is sold at 7% off.
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