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Anonymous users2024-02-11Hello. The first is the meaning of efficiency.
I have a school in the third year of junior high school.
The second is. Let the encounter time be t, the velocity of A is v A, and the velocity of B is v B
v A * t = B : v A v B =
A = v B * t gets: v A v B = t (1) and (2) can obtain: proportion. Solution: t=2
Then v A v B =
Speed sum: 36 2 = 18 km.
A's velocity: 18 (4+5)x4=8 km/h.
Thank you. B's speed: 18 (4+5)x5=10 km/h.
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Anonymous users2024-02-10Solution: Let the encounter time t, the velocity of A is v A, and the velocity of B is v B
v A * t = B : v A v B =
A = v B * t gets: v A v B = t
From (1) and (2) obtain: Proportion. Solution: t=2 then vA, vB=
Speed sum: 36 2 = 18 km.
A's velocity: 18 (4+5)x4=8 km/h.
B's speed: 18 (4+5)x5=10 km/h Look!
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Anonymous users2024-02-09Hello, I am glad that I am at your service and have the following answer for you: The solution to this problem is to use Newton's second law, which is f=ma, where f is the force, m is the mass, and a is the acceleration. Therefore, this formula can be used to calculate the value of acceleration squared multiplied by time.
The steps are as follows:1First of all, Ji Wang Zheng calculates the force f, that is, f=ma; 2.
Then, the acceleration a is calculated, i.e., a=f m; 3.Then, the value of acceleration squared multiplied by time is calculated, i.e., a 2*t; 4.Finally, divide the value of acceleration squared by time by 2, i.e., (a2*t)2.
Personal tip: Newton's second law is a very useful law of physics that can be used to solve many physics problems, so it is important to keep this law in mind when solving physics problems.
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Anonymous users2024-02-08According to the description of our high school textbook, there is acceleration a=(δv) (δt)=(v1-v2) t, because the unit of velocity (v) is m s, and the unit of time (t) is s, so divide m s by s and s to get its unit: m s 2
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Anonymous users2024-02-07The displacement of the first period st=1 2at
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Anonymous users2024-02-06Distance = time multiplied by speed.
Speed = distance divided by time.
Time = distance divided by speed.
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Anonymous users2024-02-05Distance = time multiplied by speed.
Speed = distance divided by time.
Time = distance divided by speed. Hope.
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Anonymous users2024-02-04Time multiplied by speed equals distance. You made a mistake.
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Anonymous users2024-02-03Distance = time multiplied by speed.
Speed = distance divided by time.
Time = distance divided by speed.
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