A more difficult math problem, some more difficult math problems.

If the total number of two bundles is considered as 1, then the number of copies in the first bundle is 7 (8+7) = 7 15, and the number of copies in the second bundle is 8 15.

8 15-7 15 = 1 15, that is, 1 15 of these two bundles of books has 8*2 copies.

Then 15*8*2=240 copies. There are 240 books in this bundle.

If the sixth grade divides all the books into 5 12, then the fifth grade and the fourth grade divide the 7 12 of the whole book, and the ratio of the number between the fifth grade and the fourth grade is 4 to 3, then it can be calculated that the fifth grade gets 4 12 of all the books, and the fourth grade gets 3 12 of all the books

Therefore, the number of books assigned to the sixth grade is 240 * 5 12 = 100 books.

The number of books allocated to the fifth grade is 240*4 12=80.

The number of books allocated to the fourth grade is 240*3 12=60.

Give points, thank you.

Solution: 1) Because the ratio of 12 of all the books in the 6th grade to the 4th grade is 4 to 3, the books in the 5th grade are all 7 12 * 4 7 = 1 3, and the books in the 4th grade are all 7 12 * 3 7 = 1 4.

2) And since the first bundle of books is 7/8 of the second bundle of books, and the 8 books of the second bundle are divided among the first bundle of books, and the two bundles are equal, then we can know that half of the 8/1 of the second bundle of books is 8 books, so the second bundle of books has 8 (1 16) = 128 books, so the first bundle of books has 128 * 7 8 = 112 books.

There are a total of 240 books in the two bundles.

3) The number of books assigned to the sixth grade is 240*5 12=100.

The number of books assigned to the fifth grade is 240*1 3=80.

The number of books assigned to the fourth grade is 240*1 4=60.

There are x copies of the first bundle of books, and there are y copies of the second bundle of books.

x+8=y-8

x = 7/8y

Solve x=112 y=128

5/12 times (112+128) = 1005 for grade 6: 4/7 times (112+128-100) = 804 for grade 3/7 times (112+128-100) = 60

VI 240 5 12 = 100 (Ben).

240-100) (4+3) = 20 (Ben).

V. 20 4 = 80 (Ben).

IV. 20 3 = 60 (Ben).

A: There are 100 books for the sixth grade, 80 books for the fifth grade, and 60 books for the fourth grade.

P.S. 8 is half of the number of copies of the second bundle than the first bundle, so 8 is actually 1/16 of the first bundle, divide 8 by the corresponding score of 1 16, and calculate the amount of the unit "1", that is, the number of books in the first bundle, and then it will be calculated. Understand for yourself, understand, understand).

I'm a little overwhelmed with math directly.,I simulated the process with python.,And the corresponding number of days required for 10 to 200 points was drawn.,I hope it helps.。

A brief explanation of the first diagram is the last part of the ** and the running result.

**SectionThe basic logic is to check whether the points are enough to run a new task every day according to the problem, and then run it and operate accordingly; At the end of the day, the points and task slots will be updated.

Run the results section, where the first column is the number of days, the last column is the total number of tasks that have been started at the moment, the middle eight columns correspond to the 8 task slots, the last row is the number of tasks that are running in the 8 task slots, and the penultimate row is the number of days when the current task is executed in the 8 card slots when the net earns enough 100 points, -1 means that there are no tasks running.

1: 30 2=15 So a walk is 90-15 75, so it takes 75*2 150 to walk round trip

2: If there is a problem, we can know that c=2 and then 3 times of a*3 + b*3 + 2=1 so 3 times of a*3 + b*3 1-2 -1

Then bring -3 into to get 3 times of a*( 3) + 3 times of b*( 3) 3 times of a*3 + b*3) 1) = 1

So 3 times of a*(3) + b*(3)+2 1+2 3

There is one day left, and the process is more complicated.

Are you setting a study plan for yourself? Is this called more difficult?

1.Two identical triangles can be joined together into a parallelogram, the base and height of the parallelogram are equal to the base and height of the triangle, respectively, and the area of each triangle is equal to the half

2.A right-angled triangle with three sides of 5 cm, 4 cm, and 3 cm, and their area is (6) square centimeters.

3.A triangle and a parallelogram are equal in height at the base, if the area of the parallelogram is 64 square meters, then the area of the triangle is (32 square meters); If the area of a triangle is 24 square centimeters, then the area of a parallelogram is (48 square centimeters)?

1 The upper or lower bottom is equal to the base of the triangle Higher than the height of the triangle The area of each triangle is equal to one-half of the parallelogram row.

2 of them the area is 12

3. The area of a triangle is 32, and the area of a parallelogram is 48

1.(base) and (height) are equal to the (base) and (height) of the triangle and equal to (half) of the parallelogram

2.(6) square centimeters.

3.(32 square meters), (48 square centimeters).

1, (bottom), (height), (bottom), (height), (half of the area).

3, (32 square meters) (48 square centimeters).

1.The bottom is one half of the bottom high.

2.VI 3Thirty-two square meters forty-eight square centimeters.

1) Rent a 29-seater bus for 180 yuan each, rent a 33-seater bus for 190 yuan per car, hope that all teachers and students in the sixth grade of primary school will take a car to go on an outing, if they all take a 29-seater car then there are 16 people without seats, if they are all into a 33-seater car there are four vacant seats left, there are a total of (161) teachers and students participating in the spring outing, if you are responsible for renting a car, what do you think is the most reasonable group? (4) 33-seater cars and (1) 29-seater cars should be rented for the reason (just full, no vacant seats, saving 10 yuan) (fill in the blanks directly).

2) A and B two cities are 504 meters apart, the passenger car line takes 8 hours, the truck line takes 12 hours, if the passenger car and the truck at the same time from A and B into the opposite departure, each other, after how many hours the two cars meet? (Equation Answer).

Solution: Think of the total distance as the unit "1".

3) The total height of Li Gang, Wang Yi, and Chen Yu is 434 cm, and when they stand side by side in front of the stationery store counter, (the shoe height is ignored), Li Gang's height is 2 5 on the counter, and Wang Yi's height is 1 2 in the counter.

Solution: The question is incomplete.

1) A total of 161 people, 4 cars with 33 seats, 1 car with 29 seats. Most affordable.