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Set up x classes. 5x3+3(x-3)=6+5(x-1)-1315+3x-9=6+5x-5-13
3x+6=5x-12
5x-3x=6+12
2x=18x=9
A total of 5x3+3x(9-3)=15+18=33 units.
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If x shifts are set, the number of fans is 3*5+(x-3)*3=15+3x-9=3x+6, then there are:
6+(x-1)*5=3x+6+13
6+5x-5=3x+19
2x=20x=10
So, there are 10 classes and 36 fans.
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Solution: The first half of the sentence can be translated into: if each shift is divided into three, there are six more. The second half of the sentence can be converted to: if each shift is divided into five, there is still a difference of 12 units.
There are x classes.
The column equation is: 3x 6 = 5x 12
If the solution is x=9, then the electric fan has: 3x 6=33 (sets) Answer: There are 9 classes and 33 electric fans.
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Summary. 600x8 = 4800 kg, 5 tons = 5000 kg, 4800 less than 5000, no overweight.
The school bought 450 desks and prepared to divide them into six grades, each with three classes, and the average number of classes assigned to each class.
There are two ways to do this question, the first is 450 6 = 75, 75 3 = 25 (sheets).
The second way is to calculate how many classes there are 3x6=18 (pieces), 450 18=25 (sheets).
Adding 0 on the brigade is not ten times that of adding 0, so adding 0 is more than not adding 0 is almost blind 9 times, 9 times is 1764, 1 times is 1764 years old 9 = 196, 196 is not adding 0, adding 0 is 1960.
The correct result was 1960
3 3 kg, 3300 g, 3 t, 3030 kg.
2100 = 3000 kg = 3 tons.
350 = 1000 kg = 1 ton, 1 + 2 = 3 tons, 3 is less than 4, can pass.
6. The tonnage of half of the sail is 18-10 = 8 tons, and the remaining half of the bridge Xiaolian truck weighs 10, and the truck weighs 10-8 = 2 tons. The weight of the cargo is 18-2 = 16 tons.
Do you have any questions, such as this kind of Lianghan problem with different units, whether it is a comparison size or an application problem, it must be converted to the same single trillion scum position before it can be compared or added or subtracted from the mu.
Have more questions? Dear, you can continue to ask questions.
Tons = 3000 kg, 3000-200 = 2800 kg.
4。8x9 = 72 tons, 72 is greater than 70, can be shipped.
5。800x5 = 4000 kg = 4 tons.
600x8 = 4800 kg, 5 tons = 5000 kg, 4800 less than 5000, no overweight.
You can also ask a question and continue to kiss.
6 tons = 6000 kg, 6000-3000 = 3000 kg, 3000 kg sold in the afternoon.
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A computer costs 3,000 yuan, and the school has 12 classes, if each class is divided into 5 computers, 60 computers. According to the information related to the inquiry, a bucket class is divided into five units, and 12 classes are 12 times 5 equals 60 computers.
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12 units.
This problem uses multiplication in arithmetic, if each class is divided into two fans, six classes are 2 times 6 equals 12 fans. There are 4 kinds of most basic operations in the operation, addition, subtraction, multiplication, and division.
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The difference between class 1 and class 3 is 100-97 3 people.
So class 3 has (93-3) 2 45 people.
2 shifts 100-48 52 people.
Class 1 93-45 48 people.
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One class was divided into four notebooks.
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The total number of computers is constant, so the total number of computers can be found to be 3 15=45 (units).
If there are five units per shift, then 45 5 9 (pcs).
A: It can be divided into 9 classes.
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First calculate the total number of computers: 3 15 45 (units), and then calculate how many classes these computers can be divided into if each shift is divided into 5 units: 45 5 9 (units).
Comprehensive formula: 3 15 5 45 5 9 (pcs).
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3×15÷5
45 5 9 pcs.
A: It can be divided into 9 classes.
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3*15 5 9 (class).
A: It can be divided into 9 classes.
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Set 5 too per class can be divided into x classes, according to the topic.
5x=3*15
Solve x 9 so you can divide it into 9 classes.
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The school has purchased 85 new desks, which are planned to be distributed to the five classes of the third grade, how many desks will each class get on average?
85 5 l7 sheets.
The answer is that the school has purchased 85 new desks, which are planned to be divided into five classes in the third grade, with an average of 17 desks per class.
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