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Tomorrow:"yyyy-mm-dd");
Yesterday:"yyyy-mm-dd");
If you don't understand, you can ask.
If satisfied, hope.
o(∩_o~
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c How do I convert a date in yyyy-mm-dd hh:mm:ss format to yyyymmddhhmmss format?
Method 1 string result=,"yyyy-mm-dd ",null).tostring
yyyymmddhhmmssfff");
Method 2: Remove "-" and "" ".
string result=, @"[\-", " ");
Method 3: string result ="yyyymmddhhmmssfff");
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1、"",dt);//2005-11-5 14:232、"",dt);2005 11 5 14:23:20 This format is more suitable for foreigners.
The same is true for decimal (which is quite useful for data with a database data type of money).
var dd = ;,dd)
The result is displayed as noticing that there is no rounding.
If dt=null, it is also possible, but if it is null, it will be empty.
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datetime t = ;
string s = "yyyyymmdd hh:mm:ss");
Strings date and time strings.
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Convert from string 1 to date type.
Convert from date type to formatted string 2 with tostring("yyyy-mm-dd"Something like this.
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c How do I convert a date in yyyy-mm-dd hh:mm:ss format to yyyymmddhhmmss format? Method 1.
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If you are sure that the string you want to convert must be in time format, you can use this);
Otherwise, if isparse is true, the conversion success value is assigned to dt, otherwise the conversion fails.
datetime dt=new datetime()bool isparse= ,out dt);
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It's so troublesome, you might as well directly convert the time to the yyyymmdd number type and compare it directly, it's the same effect.
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Compare directly with dates.
var today = ;
var dt = ;
Use the tryparse method to convert the character date if (,out dt)).
else
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You can first turn int to datetime
Or you try ;
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c Obtain the next day date of the system and convert it to (yyyy-mm-dd) format as follows:
string result ="yyyymmddhhmmssfff");
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Don't understand what you mean?
yyyy-mm-dd hh:mm:ss");
yyyy-mm-dd");
hh:mm:ss");
This is a time conversion function, independent of the local time format!
Another way is to directly modify the time format in the computer, and modify it to yyyy-mm-dd hh:mm:ss
The format is just fine!
Spoil beautiful men. txt size:
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