This year, the elder brother is 14 years old, the younger brother is 11 years old, and when the sum

After X years, the sum of the ages of the elder brother and the younger brother is 101 years.

The column equation is 14 + x + 11 + x = 101

Solve equation x = 38

After 38 years, the elder brother's age is 14 + 38 = 52 years old, and the younger brother's age is 11 + 38 = 49 years old.

Good luck with your studies!

The age of the 14-year-old brother and the 11-year-old brother are 101 years old, the elder brother is 38 years old and 14 years old, 52 years old, 38 years old and 11 years old, 49 years old, 52 years old, etc.

This year, the elder brother is 14 years old, the younger brother is 11 years old, and when the sum of the two brothers' ages is 101 years old, the elder brother is 52 years old and the younger brother is 49 years old.

104 (years old).

Brother: 104 2 = 52 (years).

Younger brother: 101-52 = 49 (years).

A: The elder brother is 52 years old and the younger brother is 49 years old.

According to the title: assuming that the elder brother's age is x, then the age difference between the two brothers is: 14-11=3, then x+x-3=101, and the solution x=52 years old, so when the sum of the brothers' ages is 101, the elder brother is 52 years old.

The elder brother is 3 years older than the younger brother.

14-11 = 3 (years).

Age and younger brother at the age of 101.

101-3) 2=49 (years).

Age and 101 years old brother is.

49 + 3 = 52 (years).

A: When the sum of the brothers' ages is 101 years old, the older brother is 52 years old.

Let's have an age of x. The younger brother's age is x-3.

x+x-3=101

2x=104

x=52

The younger brother is 10 years old this year, the elder brother is 1 5 years older than the younger brother, and the elder brother is 10 * (1 + 1 5) years old this year (12 ruler song).

10*6 Nest Sleepy Stool Brigade 5

12 (years old).

12 (years old).Answer: Brother Sakura is 12 years old this year.

Two years later, the elder brother was 14 years old, the younger brother was 8 years old, and the elder brother was 6 years older than his younger brother Qi Bei.

Two years later, my brother's sedan chair burned 2 years old, 12 + 2 = 14 years old, and my younger brother closed up 2 years old, 6 + 2 = 8 years old, the age difference will not change, it has always been 6 years old.

This year, the younger brother is 3 years old and the elder brother is 11 years old, which is 14 years old, and the difference between the elder brother and the younger brother is 8 years. When the younger brother and the elder brother are 22 years old, the elder brother should be 15 years old, and the younger brother will be 7 years old. Because.

Brother Zheng is 3 years old, and his brother is 11 years old.

3+11=14 (years).

11 + 4 = 15 (Hu Cong Bei Sui).

A: The two are 11 years old. When the two were 22 years old, the elder brother was 15 years old and the younger brother was 7 years old.

The younger brother is now x years old. 11-x=x-3 2x=11+3 2x=14 x=7Answer: My brother's current age is 7 years old.

Summary. The specific calculation process is as follows:

This year, the younger brother is 4 years old, the older brother is 12 years old, and when the elder brother is x years old, how old is the younger brother.

The specific calculation process is as follows:

x-12+4＝x-8

So younger brother x-8 years old.

Summary. The younger brother is 6 + 10 = 16 years old.

The younger brother is 6 years old, the elder brother is 10 years old, and after 10 years, the elder brother is a few years older than the younger brother.

This year, the elder brother is ten years old, and the younger brother is six years old, so ten years later.

My brother is 10 + 10 = 20 years old.

The younger brother is 6 + 10 = 16 years old.

20-16 = 4 years old.

So ten years later, the elder brother is four years older than the younger brother.

Expand. Subtract the younger brother's age from the elder brother's age in ten years to get the older age.

2 years old, the age problem in mathematics is named according to the content of the problem, its main feature is that the age difference between the two people does not change, however, the multiple relationship between the ages of the two people changes with age. The answer to this kind of question needs to grasp the rules, and parents can pass it on to their children.

Three basic characteristics].

The age difference between the two people is constant.

The age of two people increases or decreases at the same time.

The multiple of two people's age is varied.

Solution formula] precession does not change, and it is added and subtracted at the same time.

As the age changes, so does the multiple.

Grasp these three points, everything is simple.

Ideas and methods for solving problems.

1.You can use the solution ideas and methods of the "difference multiple problem".

2.The most basic types of age questions are yesterday and today, one with the proportional method and the other with the ** and equation method.

Example 1: Dad is 35 years old this year, Liangliang is 5 years old this year, how many times is Liangliang's age this year? What about next year?

Solution: 35 5 7 (times).

35 1) (5 1) 6 (times).

A: This year, Dad's age is 7 times that of Liangliang.

Next year, Dad's age will be 6 times that of Liangliang.

Example 2: The mother is 37 years old and the daughter is 7 years old, and the mother will be 4 times older than the daughter in a few years?

Solution: (1) How much older is the mother than the daughter? 37 7 30 (years old).

2) How many years later will the mother be 4 times older than the daughter? 30 (4 1) 7 3 (years).

Listed as (37 7) (4 1) 7 3 (years).

A: After 3 years, the mother is 4 times older than the daughter.

Try it out. The age of the father and son was 49 years old a year ago, and the age of the father is 4 times the age of the son this year.

2.A said to B, "You were 4 years old when my age used to be your current age." Listed as (37 7) (4 1) 7 3 (years).

A: After 3 years, the mother is 4 times older than the daughter.

Try it out. The age of the father and son was 49 years old a year ago, and the age of the father is 4 times the age of the son this year.

2.A said to B, "You were 4 years old when my age used to be your current age."

It can be assumed that after x years, the sum of the ages of the two is 49, that is, 12 + x + 16 + x = 49, and x is equal to the year. That is, under normal circumstances, the age of two people and cannot be 49.

The younger brother is 12 years old this year and the elder brother is 16 years old this year, so if the sum of the ages of the younger brother and the elder brother after x years is 49, then there is 12+x+16+x=49, so x= is obtained.

That is, the sum of the ages of the younger brother and the older brother after the year is 49.

Suppose x years later, the sum of the elder brother and younger brother's ages is equal to 49

then 12+16+2x=49

28+2x=49

2x=21x=

A: After 10 and a half years, the sum of their ages is equal to 49

Solution: Let the sum of the ages of the younger brother and the elder brother after X years be 49.

12+x+16+x=49

2x=49-28

x = year) Answer: The sum of the ages of the younger brother and the older brother is 49.

The logic of this question is not understood, if you can, in a few years, the sum of the ages of the elder brother and the younger brother will be 49 years old, then the answer will appear for half a year. That is: 12 + 16 + 2x = 49 2x = 49-28

x= So the sum of the required years is 49 years, which is ten and a half years.

This one can't be seen. Since the elder brother's age and geological age always add even, and there is no half-year difference.

Ten years later, the elder brother is 26 years old and the younger brother is 22 years old. The right age for both is 18 years old.

After 11 years, the younger brother is 23 years old and the older brother is 27 years old. The brothers are 50 years old.

This is very good, you put this 49 2 and then subtract the age difference between the younger brother and this Gege, their age difference is four, subtract this four, you know what age they are, two people, the age is equal to 49.

This is a relatively simple problem, which can be set to the sum of the ages of the elder brother and the younger brother after the year x, and the equation is 49 coins, which is 2x +4 equals 49, and 2x should be equal to 45. So after the year, the sum of the ages of the two brothers is 49, but if it is a full year, there is no year in which the sum of the ages of the two brothers is 49.

The younger brother is 12 years old this year, the elder brother is 16 years old this year, and a few years later, the sum of the ages of the younger brother and the elder brother is 49, and the older brother is four years older than the younger brother, so the sum of the ages of the elder brother and the younger brother cannot be equal to 49.

The younger brother is 12 years old this year, the elder brother is 16 years old this year, and the younger brother and elder brother are 69 years old 2 years later.

The younger brother is twelve years old, the elder brother is sixteen years old today, the younger brother is 12 years old, the elder brother is 16 years old, and in a few years, the age of the younger brother and the elder brother. This is 49. When you are thirty-two, I will purchase four, and when you are thirty-two, I will be 49 years old.

21 2 years).

The sum of the elder brother and younger brother after the year was 49 years old.

The younger brother is 12 years old and the older brother is 16 years old, and the sum of the younger brother and the older brother in a few years is a year later.

years later, the sum of the elder brother and younger brother was 49

The younger brother is 12 years old this year, and the elder brother is 16 years old, and ten years later, the sum of the younger brother and older brother should be 49.

Suppose the sum of the younger brother and older brother after x years is 49.

12 ten x ten 16 ten x 49

2x＝21x＝

Because the number of years cannot be a decimal, is there a mistake in the question?

The younger brother is 12 years old and the older brother is 16 years old, so the sum of their elder brother's ages is 49, then it should be said. Either way, they can't be 49.

Subtract the sum of the current ages of the two by 49, and divide the number by 2 to be the year! How easy!

My brother is 12 years old this year, my brother is 16 years old this year, and the first song in a few years will be Zhihu, and I will also be 49, about ten years later.

I think there may be something wrong with this question, because the age of the elder brother and the younger brother are even, so the sum of them must also be operated on, no matter how many years have passed.