A 2nd grade math problem in elementary school, extremely difficult Please help me

It's easy. Of course it's 97 yuan.

100 yuan or 100 yuan for neighbors. Didn't make or lose. The young man's 100 yuan of fake money was exchanged for 79 yuan of real money. With 21 yuan goods. But the merchandise shopkeeper earned three dollars. So. Boss Wang could only be regarded as a loss of 97 yuan.

Calculation of lost money:

Boss Wang first gave the young man 79 in exchange for 100 when he changed the change, and he still had 21, which was earned.

And what about the losses? The cost of the gift fee is 18I also paid back the neighborhood 100, so the total loss was 21-18-100 = -97 yuan - =

As for the answer to 176, it is wrong. Originally, the 79 yuan was not their own, which was the reason for everyone's mistakes.

Silent condolences to Boss Wang.

I think I lost 97 for the following reasons:

The old class paid a gift of 18 yuan, but left 21 yuan, and finally gave 100 yuan to the neighborhood

Boss Wang can earn 21-18=3 yuan by selling this gift;

He exchanged 100 yuan of change from the neighbors, and found 79 yuan for the young man, so Boss Wang still had 100-79=21 yuan in his hand;

After paying back 100 yuan to the neighbor out of his own pocket, he lost 100 yuan, and he had 21 yuan in his hand, so 100-21, he lost 79 yuan;

The cost of the gift is 18 yuan, so Boss Wang lost a total of 79 + 18 = 97 yuan.

The eldest brother lost 79 and this gift totaled 97 yuan.

18 + 79 + 100 = 197 (yuan).

This is at cost!

If you don't press that, it's :

100 + 21 + 79 = 200 (yuan).

Remember, remember, remember, stopped!!

Eldest brother!!!

197 yuan, the cost of the gift is calculated.

It can't be counted that way.

They would have been out of 30

Later, the boss refunded 5 yuan, which is a total of 25 yuan.

After a refund of 3 yuan.

It's 28 yuan.

Add 2 yuan for waiters.

That's 30 yuan.

It can't be counted as a separate one.

Alone it is misleading.

The boss took 25, the waiter 2 yuan, and the 3 people each gave 9 fast, 25 + 2 = 9 + 9 + 9

A piece is not missing.

If you talk about the idea of using equations, it should be very simple, but if you say that you don't use the idea of equations, you can still find it, but it may still be a little difficult for students in the second grade of elementary school to understand. You can think about it, if the money to buy a schoolbag is reduced by two yuan, then the total cost is 54 yuan, in this way, the price of the schoolbag is 8 times that of the notebook, and if the notebook rings into a copy, the schoolbag has eight copies, that is to say, nine copies are a total of 54 yuan, that one is 6 yuan, and the notebook is 6 yuan, and the schoolbag is 56-6 = 50 yuan.

School bag notebook 8+2

Notebook Notebook 8+2=56

9 notebook=54

Notebook $5.

School bag 51 yuan.

Xiao Ming bought a schoolbag and a notebook, spending a total of 56 yuan. It is known that the cost of buying a schoolbag is 8 times more than the cost of buying a notebook and 2 yuan, how much is the cost of a notebook and a schoolbag?

Column: 8+1=9 - indicates the total number of copies of the money to buy the schoolbag and notebook.

56-2=54 (yuan) - the total price of the total number of copies of the money to buy the school bag and notebook.

54 9 = 6 (yuan) - the price of 1 9 copies of the total number of copies of the money to buy a school bag and notebook.

6 x 8 + 2 = 50 (yuan) - 8" indicates the number of copies of the money to buy the school bag. What I asked for was the price of the school bag.

6 x 1 = 6 (yuan) - find the price of the notebook.

A: A schoolbag is 50 yuan, and a notebook is 6 yuan.

Assuming that the cost of the schoolbag is just 8 times that of the notebook, it will cost 2 yuan less, that is, a total of 56-2=54 yuan.

At this time, the notebook is 1 copy and the schoolbag is 8 copies, each copy: 54 (1+8) = 6 yuan.

The notebook is 1 copy, 6 yuan, and the schoolbag is 56-6 = 50 yuan.

Hello, although there is an answer, I want to talk about my thoughts, for reference, if the money of this is 1 copy, the money of the schoolbag is 8 copies and more than 2 yuan, so after removing this 2 yuan, there is 54 yuan left, a total of 9 points, each point is 6 yuan, so this 6 yuan, 50 yuan for the schoolbag,

Set up a notebook x then a school bag 8x+2

8x+2+x=56

9x=54x=6, so the notebook is 6 yuan.

School bag 50 yuan.

Who said that you can't use equations in the second grade, I clearly remember that when I was in the second grade, there was a problem that the teacher taught us with equations... But the teacher taught us to set A, which is no different from X.

Without equations, the equation is:

The ** of the notebook is (56-2) (8 + 1) = 6 yuan, and the ** of the schoolbag is 56-6 = 50 yuan.

Notebook = (56-2) (8 + 1) = 6 yuan.

School bag = 6 8 + 2 = 48 + 2 = 50 motions.

(56-2) (1+8)=6 yuan notebook.

6x8+2=50 school bag.

Answer: Slightly.

Because the schoolbag is 8 times more than the notebook by 2 yuan, then 1 schoolbag plus 1 notebook can be regarded as 9 notebooks plus 2 yuan. So the total price of 56 yuan minus 2 yuan is the ** of 9 notebooks.

The ** of the notebook is 6 yuan.

The ** of the schoolbag is 50 yuan.

Total price = 56 yuan = the money to buy a schoolbag and a notebook = the money to buy a notebook (8 + 1) times more than 2 yuan.

Notebook = (56-2) (8 + 1) = 6 yuan.

School bag = 56-6 = 50 yuan.

It can be understood in this way, 56 yuan is a notebook + a school bag, that is, a notebook + 8 notebooks + 2, that is, 9 notebooks and 2 yuan more,,, so 9 notebooks are 54 yuan, one is 6 yuan, so a school bag is 56-6 = 50,

(56-2) 9 = 6 for notebooks.

6x8+2=50 school bag**.

It takes 1 minute.

56－2＝54

So the notebook is 6 yuan, and the school bag is 50 yuan.

Buy a notebook: 56-2=54 54 9=6 yuan Buy a schoolbag 6*8+2=50 yuan Hehe, so be it.

There are 98 gray chickens.

Because there are 86 white chickens.

Gray chicken: 86 + 12 = 98 (only).

Black chicken: 86-9=77 (only).

One, 86 white chickens, 12 more gray chickens, 98 gray chickens

Second, the white chicken is 86, the black chicken is less than 9, and the black chicken is more than 77.

1 Thinking this way, we set that we used x tons of water in March.

According to the title, April uses 90% of March is multiplied by x tons of water and launched, x is equal to 30 tons, i.e. April = tons The second method can be set to use x tons of water in April, and x2 is solved according to the quantitative relationship in the questionFrom the properties of the cube, we can see that the area of the two pairs is the same in six months, so the total area is equal to twice the sum of these three areas.

The percentage is obtained by dividing the area of the three faces by the total area.