Primary School Mathematics Olympiad find a detailed and easy to understand process .

It takes 10 days for A to complete alone, then A completes 1 10 of the total amount every day, A and B do it together, as long as 6 days, 6 days A completes 6 10 of the total amount, then B completes 1-6 10 = 4 10 in 6 days, then B completes 4 10 6 = 1 15 of the total amount every dayB and C work together, it takes 8 days, and B can complete 1 15 8 = 8 18 of the total amount in 8 days, then the amount of work completed by C in 8 days is 1-8 15 = 7 15, and C completes 7 15 8 = 7 120 of the total amount every day

Now it is up to these three people to complete it together, then 1 10 + 1 15 + 7 120 = 9 40 can be completed every day, then it takes 1 9 40 = 40 9 days to complete all the total, A can complete 1 10-1 15 = 1 30 30 more than B every day, 40 9 days A completes 1 30 40 9 = 4 27 more than B, now we know that A completes 600 more than B, that is to say, 4 27 of the total is 600, then the total amount is 600 4 27 = 4050, and C is 40 A total of 7 120 40 9 = 7 27 was completed in 9 days, and the total was 4050, so C completed 4050 7 27 = 1050.

1 6-1 10 = 1 15 B's efficiency.

1 8-1 15 = 7 120 C efficiency.

The efficiency ratio of A, B and C is: 1 10:1 15:7 120=12:8:7600 7 (12-8)=1050 If the difference between A and B is 1, then C accounts for 7 (12-8) of the difference

A: 1050 completed.

Through the previous conditions, the ergonomics of A, B and C can be found respectively, and the corresponding fraction of 600 can be found to find the total number, and then C.

1050 pcs.

Erase 1,3, write 2, erase 2,2, write 2, from now on, erase the smallest two numbers each time, and finally leave 2006 and 2008, resulting in a maximum value of 2007.

Similarly, the minimum value is 2

The difference was 2005

If you can't see clearly, please draw correctly.

Let's take a picture of the topic directly, there should be a lot of conditions that should not be said.