Looking for primary school math Olympiad topics?? Primary School Math Olympiad?

What grade is it? As long as you go to the top and type "xx grade Olympiad questions and answers", there will be a lot of them, and you can't read them all.

It is advisable to purchase relevant books according to the learning situation.

We can solve this problem mathematically.

First of all, we know that commodity A is priced at 30% of the profit, and commodity B is priced at 20% of the profit.

Then we can get that the selling price of commodity A is multiple of the original price, and the selling price of commodity B is multiple of the original price.

Then, we know that one of the two commodities A and B can be profitable, multiplied by the discount.

And because the cost of the two goods totals 200 yuan, you can get:

x * y * = *

x + y = 200

where x is the cost of commodity A and y is the cost of commodity B.

Solution: x = 100

y = 100

So the cost of commodity A is 100 yuan, and the cost of commodity B is also 100 yuan.

Let A be x, then B is 200-x

So the original price of A is.

B is because of the nine discounts, so the ** after the discount of A is.

B is A's discounted profit.

B is because the total profit of A and B is.

So the equations can be listed.

Then you can solve it and you will find the answer.

If the completion time of iQue Town A is t, then the completion time of B is t+18, and there are m pieces of handicrafts.

m÷[m/t+m/(t+18)=40

t=72 can be obtained

The completion time of A is 72, then the completion time of B is 90, and it can be seen that the efficiency of the rough A is sharpened: the efficiency of B = 5:4

Let the efficiency of A be x and the efficiency of B be y, because team A processes 400 more pieces than team B when it is completed, then.

x：y=5：4

40×x-40×y=400

x=50 y=40 can be obtained

A total of = 50 72 = 3600 pieces. Pick D

By the question, the Serie A team does more than the B team every day.

400 40 = 10.

Conventional practice, set equations.

If team A makes x parts per day, then team B makes x-10 parts per day, then the total number of parts is 40 (2x-10).

Individual processing such as bureau or team B is 18 days behind team A.

Then the equation of the slag and the latherement is established.

40（2x-10）/x+18

40（2x-10）/（x-10）

Solution x=50

then the total number of parts is.

Primary School Olympiad Questions, Primary School Olympiad Topics are magic.

Resource Catalog: Primary Mathematics Olympiad (Grades 1-6).

Grade 1 Mathematics Olympiad.

Grade 5 Mathematics Olympiad.

Grade 4 Mathematics Olympiad.

Grade 3 Mathematics Olympiad.

Sixth grade Mathematics Olympiad.

Grade 2 Mathematics Olympiad.

1 liter 2nd grade mathematics summer school.

Year 2 Mathematics Olympiad Autumn Class.

2nd grade Olympiad Winter Vacation Class.

Year 2 Mathematics Olympiad Spring Class.

Lecture 9 on the issue of overlap.

Lecture 14: Review Assessment.

Lecture 13: Magical equation addition and subtraction.

Lecture 12: The Mystery of the Number Array Diagram.

Answer: The full name of the Primary School Mathematics Olympiad is "Primary School Mathematics Olympiad", or "Primary School Mathematics Olympiad", which originated from "mathematics is the gymnastics of thinking", which reflects the commonality between mathematics and the Olympic sports spirit: faster, higher, stronger.

In fact, it is more accurately called "primary school competition mathematics". It embodies the ingenuity, flexibility, and variability of mathematics and the mathematical aesthetics that permeate it.

Classified as a cow grazing problem.

There is one entrance, and the number of people who enter in one minute is 1.

27-25=2 (i.e. 9-5=4 minutes for 2 new arrivals) 2 4 = for new arrivals per minute.

3 entrances, a total of 27 people in 9 minutes, 27-9* original (i.e. those who arrive before 9 o'clock).

It takes 45 minutes for these people to arrive.

So the first spectator arrives at 8:15.

Set one entrance for one minute, one serving of soul.

1) The original number of people + 9 minutes to increase the number of people = 3x9 = 27 copies (2) The original number of people + 5 minutes to increase the number of people = 5x5 = 25 copies can be obtained: 4 minutes to increase the number of people = 2 copies.

That is: 1 minute to increase the number of people = serving.

Substitution (1) gets: original number = shares.

The time required for the original number of people to be generated = minutes.

45 minutes before 9 a.m. at 8:15 a.m

Because 3*8-5*4=4; 8-4=4；4 = 4 so the number of viewers per minute = the number of votes cut at each entrance.

3*8-8=16 (points).

i.e. 8:44

Let the first person be at a speed of v t minutes before 9 o'clock

tv+9v)/3=tv+5v)5

The solution is t=15

It was 8:45

A, B, C, D.

Unit A is 3/11 of the total number of the other three units, and if the other three units are 11 shares, then the total number of units is 3, the total number of four units is 14, and the total number of units A is 3/14.

Unit B donated five-ninths of the total number of the other three units, and unit B accounted for five-tenths of the total number of four units.

Unit C donated 6/29 of the other three units combined, and Unit C accounted for 6/35 of the total number of the four units.

Thus, unit D accounts for the total number of 4 units: 1-3 14-5 14-6 35=1-(15+25+12) 70=18 70

Unit D donated 180,000 yuan, and unit D accounted for 18 70 of the total number of 4 units, so the total donation of the four units was 700,000 yuan.

Therefore, A donated 150,000 yuan, B donated 250,000 yuan, C donated 120,000 yuan, and D donated 180,000 yuan.

How many grades are you, I don't know if you can understand my approach. The answer is 150,000 for A, 250,000 for B, and 120,000 for C. Brother, don't be scared at a glance, it's just an equation, you can understand it if you read it, but if you have a few more unknowns, the solution is the same, you can understand it if you read it.

Let's say A donated $x, B donated $Y, and C donated $Z.

x/y+z+18=3/11 y/x+z+18=5/9 z/x+y+18=6/29

It becomes 11 3*x=y+z+18 9 5*y=x+z+18 29 6*z=x+y+18

Then use - =x+z+18-(y+z+18)=9 5*y-11 3*x=x-y x-y=9 5*y-11 3*x 14 3*x=14 5*y

Then use - =x+y+18-(x+z+18)=29 6*z-9 5*y=y-z y-z=29 6*z-9 5*y, 35 6*z=14 5*y

Combined, 14 3*x=14 5*y=35*z, it's easier to follow. Replace both y and z with x y=5 3*x z=4 5x

Then substituting y and z into 11 3*x=5 3*x+4 5*x+18 will solve this equation, right?Find x=15 and then substitute x=15 into y=5 3*x to get y=25 and then substitute x=15 into z=4 5x to find z=12 Solved Answer: A donated 150,000 yuan, B donated 250,000 yuan, and C donated 120,000 yuan.

It's not easy to hit so many by hand This is the detailed process 0 0 I hope it can help you.

Solution: Set A to donate x million yuan, B to donate y million yuan, and C to donate z million yuan.

From the title: x (x+y+18)=3 11 y x+z+18=5 9

z/x+y+18=6/29③

Solution: x=15 y=25 z=12Answer: A, B and C each donated 15,25,120,000 yuan.

A donated 150,000 yuan, B donated 250,000 yuan, C donated 120,000 yuan, and D donated 180,000 yuan.

When they meet, A travels more than B: kilometers.

Encounter time: 63 12 = hours.

From the arrival of A at the West Railway Station to the meeting of A and B, it takes time:

Hour A traveled per hour: kilometers.

42. After an hour, A arrives at the West Railway Station, and A travels 54 kilometers more than B at this time, indicating that B is 54 kilometers away from the West Railway Station at this time. Then from the distance from the west station at the time of the encounter, it means that from A to meet B, B traveled a kilometer, kilometers, indicating that hours have passed, so A speed

The total gross profit margin of the four commodities in a month = (500 =

(95*500*8%+170*60*13%+450*50*21%+923*3*28%)/(95*500+170*60+450*50+923*3)

Big brother, this. Let's use a calculator.

The underside circumference of the box is.

80 4 20 (cm).

The length and width of the box are.

20 4 5 (cm).

The surface area of the box is.

5 5 5 40 5 40) 2 850 (square centimeters).

The 4cm increase in height is the increase in the area of the four sides, because the underside has not changed. Each side adds 20 square centimeters, then the length of each side is 5cm, and the volume is naturally 5x5x5 125 cubic centimeters.

Let the side length of the original cube be x cm, then the surface area of the cube = 6*x*x=6x 2 The surface area of the cuboid = 4(x+4)*x+2x 2

Then 4 (x + 4) * x + 2 x 2-6 x 2 = 80, and the solution x = 5 then the volume of the cube = 5 3 = 125 cubic centimeters.