People from high school came to the question of self study in the first year of high school!!

Mathematics, you have finished reading all the required courses, so find a set of college entrance examination review materials for the third year of high school, and do it honestly from the beginning, and it is estimated that it will be enough to finish it before the second year of high school next year.

Chemistry, this course requires a certain amount of exercises to consolidate. You also find a set of materials for the first round of college entrance examination review to do it from scratch.

In addition, the textbooks of middle school are now very fragmented, and it is not comfortable to read, so it should be of great help if you find a book of "three-year inorganic chemistry in secondary specialized schools", especially for chemical engineering majors, according to your conditions.

You can find this online.

It's a little early to discuss the college entrance examination questions. If you persist in this way, the college entrance examination is not a problem.

You're only in your first year of high school now, don't think too much, just do well in the college entrance examination, everyone has their own characteristics, but you haven't found it, self-confidence.

The college entrance examination is still simple, start with a simple foundation, have spare energy or do something difficult, and the college entrance examination generally has innovative questions, you can practice. I personally think this book is good, and many of the above questions are college entrance examination questions.

Comparatively speaking, it is easier than the usual questions. It's about the same as five three.

(1) The breakthrough of this problem is that X heating will produce three substances (two of which are gases), HCl will have gas, and NaOH will also have gas. So X is (NH4)2CO3

Then it's easy, c:nh3. F is NO2, G is HNO3(2)CO2+Na2O2---Na2CO3+O2 (self-trimming) (3) Where is reaction 2?

In addition, A is CO2, B is H2O, D is O2, E is NO, and F is NO2.

x Ammonium bicarbonate.

c. Ammonia f, nitrogen dioxide, g nitric acid.

Let's take a look at this question first, there are two breakthroughs, the first is the generation of three different substances at the beginning of X, it can be seen that the substance learned in high school is ammonium bicarbonate, and the other is the reaction of the last g and copper to form two different substances, there are several such reactions in high school, but in connection with the previous ammonium bicarbonate, you can launch a variety of substances containing nitrogen, so as to launch various substances, and the netizens in front of each substance have already given the answer, so I will not repeat it. There are a lot of such questions in high school, right? I remember that there is also the college entrance examination, I hope you learn how to do this kind of question, come on!

X is (NH4)2CO3 C is NH3 A is CO2 B is H2O D is O2 E is No F is NO2 G is HNO3

nh4++oh-=nh3+h2o

Find out the x first

X reacts with acid to form gas, and it can be thought that X contains carbonate; X reacts with a base to form a gas, and it can be thought that x contains ammonium. X heats to produce 3 substances, and it can be thought that B is water. So x can be ammonium carbonate or ammonium bicarbonate.

Then C is ammonia, A is carbon dioxide, D is oxygen, E is nitric oxide, F is nitrogen dioxide, and G is nitric acid.

The reaction is 2Na2O2+2CO2=2Na2CO3+O2 reaction is (should be the reaction of nitric acid and copper).

g+cu=f：4(h+)+2((no3)2-)+cu=(cu2+)+2no2+2h2o

g+cu=g：8(h+)+2((no3)2-)+3cu=3(cu2+)+2no+4h2o

Question 1: Because the set a= , so -1 so its number of subsets is 8, and the number of true subsets is 7.

Question 2; Since the functions f(x) and g(x) are both odd functions on the function, f(x)=a*f(x)+b*g(x)+2 has a maximum value of 5 on (0,+), so f(-x)=-f(x), g(-x)=-g(x). f(-x)=a*f(-x)+b*g(-x)+2=-a*f(x)-b*g(x)+2, so the minimum value of f(x) on (- 0) is -1

p=-1,q=-3,r=-10

anb= so there is x=-2 in a, and x=-2 in b Substituting x -px-2=0, x +qx+r=0, we get p=-1, 4-2q+r=0 --.

Then a==.

Since aub=, then there must be x=5 in b, substituting b=, to get 25+5q+r=0--*.

1. Lu Feng solves the two formulas: q=-3,r=-10 I wish you the same dazzling learning ability as the earrings.

From the meaning of the question, we can know that the x of a is 1, 5, and the x of b is -2, and then it becomes a system of equations, and the value of pqr is solved, and it is enough.

Use the function y=a?b x + c (a, b, c are constants) is well simulated. The premise tells us that the monthly growth rate of output is nonlinearly decreasing, and the quadratic function does not have such a property, but the exponential function has such a property.

So y=a?b x + c (a, b, c are constants).

Use y= to find the monthly growth rate, and by calculating it, you can find that the monthly growth rate is a stable value!

In fact, y = January production + (1+a%) month - 1).