Good math help me, it s easy 10

1 day has 60*24 minutes, and 10 years have 10*365 days, so 1 minute in the sky is equal to [1 (60*24)]*10*365=

Unit conversion.

10 years = 10 * 365 = 3650 days.

So 1 minute in the sky, 3650 minutes in the ground, 3650 divided by 60, divided by 24,

1440 points 5254560 points = 1440 1440 = 1 point 5254560 1440 = points Approx. = 37533 points Underground is 37533 60= Approximately equals 623 hours Approximately equals 26 days.

It is found that the sum of two numbers is equal to the product of two numbers.

(1) Rule: (-1 n)*(1 (n+1)) = (-1 n)+(1 (n+1)).

2) =-1+1 2008=-2007 2008 Anyway, this law is not required to be taught, and it must be used for quick calculations.

A further rule should be: 1 (m*n)=(1 (m-n))*1 m)-(1 n))).

Rule: -1 n 1 (n+1)=-1 n+1 (n+1), it is obvious that you will divide the right side of the equal sign, which is the left side of the equal sign.

Original = -1+1 2-1 2+1 3-1 3+1 4-......1 2007 + 1 2008, the two adjacent items are eliminated, and finally only -1 + 1 2008 = 2007 2008

What's the first one, factorization?

2.Primitive=[5]=[-(125)]=125=15625

3.Original = 27 to the 6th power of 10 to the 12th power of 10 = to the 19th power is any real number (please check the title).

Solution: 1) f(x) = sin(wx+v6)+sin(wx-v6)-2cos (wx 2).

sinwx×√3/2+coswx×1/2+sinwx×√3/2-coswx×1/2+1-2cos²(wx/2)-1

sinwx×√3+coswx

1=2[sinwx×√3/2+coswx×1/2]-1

2sin (wx+vulture 6)-1

Because sin(wx+vultures 6) [1,1].

Then 2sin(wx+v6)-1 [-3,1].

That is, the range of the original function is [-3,1].

2) Again. The distance between the image of the function y=f(x) and the two adjacent intersections of the line y=-1 is 2

Then the period of y=f(x) is v2

4=2 vultures. So w=2 vultures 2 vultures = 1

So y=2sin(x+v6)-1

Because sinx is monotonically increasing in [2k vultures + vultures, 2k vultures + 2 vultures], k n is monotonically increasing.

Then sin(x+vulture6)at [2kvulture+vulture-vultures 6,2kvulture+2-vultures 6], k n increases monotonically.

i.e. sin(x+vulture6)at [2kvulture+5vulture6,2kvulture +11vulture 6], k n increases monotonically.

So the monotonic increase interval of the function y=f(x) is [2k vulture + 5 vulture 6, 2k vulture + 11 vulture 6],k n

The root number 3 is multiplied by sinwx-(coswx+1) and then merged with the auxiliary angle formula to obtain 2sin(wx-30 degrees)-1

From this we can get the range of minus 3 to 1, and from the first question, we can see that the minimum distance between y=-1 and the image is half the period and w=2! (Next, do the math yourself, replace the above angle with an arc representation, my phone can't do it).

The original formula can be reduced to f(x)=2cos(wx+vulture 3), and the value range can be known as: [-2,2].

There are known conditions to obtain: V2=period 2=2V, w=2, w=2

The monotonic increase interval is: [(2 vulture 3)+k vulture, k vulture - vulture 3].

Solution: 1) f(x) = sin(wx+v6)+sin(wx-v6)-2cos (wx 2).

sinwx×√3/2+coswx×1/2+sinwx×√3/2-coswx×1/2+1-2cos²(wx/2)-1

sinwx×√3+coswx

2[sinwx×√3/2+coswx×1/2]-1

2sin (wx+vulture 6)-1

Because. sin(wx+vulture 6) [1,1].

Then 2sin(wx+v6)-1 [-3,1].

That is, the range of the original function is [-3,1].

2) Again. The distance between the image of the function y=f(x) and the two adjacent intersections of the line y=-1 is 2

Then the period of y=f(x) is v2

4=2 vultures. So w=2 vultures 2 vultures = 1

So y=2sin(x+v6)-1

Because sinx is monotonically increasing in [2k vultures + vultures, 2k vultures + 2 vultures], k n is monotonically increasing.

Then sin(x+vulture6)at [2kvulture+vulture-vultures 6,2kvulture+2-vultures 6], k n increases monotonically.

i.e. sin(x+vulture6)at [2kvulture+5vulture6,2kvulture +11vulture 6], k n increases monotonically.

So. The monotonic increase interval of the function y=f(x) is [2k vulture + 5 vulture 6, 2k vulture + 11 vulture 6], k n

The original formula can be reduced to f(x)=2cos(wx+vulture 3), and the value range can be known as: [-2,2].

There are known conditions to obtain: V2=period 2=2V, w=2, w=2

The monotonic increase interval is: [(2 vulture 3)+k vulture, k vulture - vulture 3].

The root number 3 is multiplied by sinwx-(coswx+1) and then merged with the auxiliary angle formula to obtain 2sin(wx-30 degrees)-1

From this we can get the range of minus 3 to 1, and from the first question, we can see that the minimum distance between y=-1 and the image is half the period and w=2! (Next, do the math yourself, replace the above angle with an arc representation, my phone can't do it).