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The equation can be obtained by the properties of the proportional series:
x(3x+3)=(2x+2)(2x+2)
The solution yields x=-1, or x=-4
When x=-1, x,2x+2,3x+3 are -1,0,0 respectively, forming an equal proportional series, x≠-1;
When x=-4, x,2x+2,3x+3 are -4,-6,-9 respectively, which can form a proportional series,x=-4
So the answer is -4
A proportional sequence means that if a series starts from the 2nd term, the ratio of each term to its previous term is equal to the same constant. This constant is called the common ratio of the proportional series, which is usually represented by the letter q (q≠0), and the proportional series a1≠ 0. Each of these AN items is not 0.
Note: When q=1, an is a constant series.
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x, 2x+2, 3x+3 is a proportional series of consecutive terms, (2x+2)2x(3x+3), collated, and x2 is obtained
5x+4=0, the solution is x=-1, or x=-4
When x=-1, x,2x+2,3x+3 are -1,0,0 respectively, forming an equal proportional series, x≠-1;
When x=-4, x,2x+2,3x+3 are -4,-6,-9 respectively, which can form a proportional series,x=-4
So the answer is: -4
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x,2x+2,3x+3 is a proportional series of consecutive terms, (2x+2) 2 =x(3x+3), collation, x2 +5x+4=0, solution x=-1, or x=-4 When x=-1, x,2x+2,3x+3 are -1,0,0 respectively, forming a proportional series, x≠-1; When x=-4, x, 2x+2, 3x+3....
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x, 2x+2, 3x+3 is a proportional series of consecutive terms, (2x+2)2x(3x+3), collated, and x2 is obtained
5x+4=0, x=-1, or x=-4 When x=-1, x,2x+2,3x+3 are -1,0,0 respectively, and cannot form a proportional series, x≠-1;
When x=-4, x,2x+2,3x+3 are -4,-6,-9 respectively, which can form a proportional series,x=-4
So the answer is: -4
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Because it is a proportional series, (2x+2) 2=x(3x+3) so x=-1or-4
When x=-1.
2x+2 is 0, so round.
x = -4 m q = 3 2
The fourth item is -27 2
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x,2x+2,3x+3 is proportional to the series, the first three terms have x*(3x+3)=(2x+2) 2, that is, 3x(x+1)-4(x+1) 2=0(x+1)(3x-4x-4)=0(x+1)(x+4)=0, so when x=-1 or -4x=-1, the first three terms are -1,0,0, not proportional series. When x=-4 is rounded, the first three terms are -4, -6, -9, and the common ratio is 3 2, so the fourth term is -9*3 2=-.
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Example 1 + J2, 3-1, 3'+3 into proportional series, then x=(+pro, hello, can you take a picture of the original question to the teacher?)
The questions you sent are incomplete, and the teacher is not accurate.
Dear, I think the problem should be if -x,y+3 is proportional to the series, find x,y.
In this case, the slippery stool has: 1 2=2 3-x, and the calculated x=-1;Tantan 1 2=3-x (y+3), substituting x=-1, the calculation is believed to be y=5.
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x, 2x+2, 3x+3 is the first three terms of a proportional series, then (2x+2) 2=x(3x+3).
4x^2+8x+4=3x^2+3x
x^2+5x+4=0
x+1)(x+4)=0
x=-1 or x=-4
When x=-1, the first three terms of the series are -1,0,0, rounded.
When x=-4, the first three terms of the series are -4, -6, -9
So, item 4 = (-9) 2 (-6) =
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First, find the value of x, (2x+2) 2=x(3x+3) solution, x=-1
or -4 test, x = -1, the first three are .
1,0,0 do not match, discard.
x = -4, the first three terms are -4, -6, -9
Common ratio q=3 2, general term.
an=a1*q^(n-1)
-4)*(3/2)^(n-1)
Cause. an=-27/2
Get n=4 so.
is the fourth item.
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x, 2x+2, and 3x+3 are the first three terms of the proportional series.
then there is x*(3x+3)=(2x+2) 2
That is, 3x(x+1)-4(x+1) 2=0
x+1)(3x-4x-4)=0
x+1)(x+4)=0
So x=-1 or -4
When x=-1, the first three terms are -1, 0, 0, not proportional series. When x=-4 is rounded, the first three terms are -4, -6, -9, and the common ratio is 3 2, so the fourth term is -9*3 2=-27 2
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Fourth term = (2x+2)(3x+3) x
6x²+12x+6)÷x
6x+12+6/x
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Because x,2x+2,3x+3 is a proportional sequence, so (2x+2) 2=x(3x+3), simplified to x 2+5x+4=0, the solution is x= -1 (rounded off because 2x+2=0) or x= -4, the first 3 terms of this series are -4, -6, -9, so the fourth term is -27 2.
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Proportional numbers.
2x+2)^2=x(3x+3)
4x^2+8x+4=3x^2+3x
x^2+5x+4=0
x+1)(x+4)=0
x=-1 or x=-4
When x=-1, the first three terms are -1,0,0 do not match.
x = -4, -4, -6, -9
Get the fourth term = -6 * 9 4 = -27 2
Solution 1: x +3x -3x+k
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Because the value of the function is 0 when x= -2 and x=1 2, the analytical formula can be set to y=a(x+2)(2x-1), and substituting x=0 and y= -1 into the -1=a(0+2)(0-1) to obtain a=1 2, so the analytical expression of the quadratic function is y=1 2*(x+2)(2x-1)= x 2+3 2*x-1.