Math problems ,,, come to people, math problems, look

Yuan) kg) 100 (1 80%) = 180 (kg) page) kg) 10 4 5 = kg) Length: 2 5 = 10 (cm) Width: 2 3 = 6 (cm).

Solution: (1) 390 (1 80) 19502) Apple: 20 (1 80) 100; Pears: 100 times 80 803) 60 divided by 2 (2 3) = 150

Multiply by 25 and divide by 4 5

5) Length: (32 2) multiplied by 5 (3 5) = 10; Width: 32 2 10 6

Each time it is folded in half, the thickness is twice that of the previous one, and the thickness of the paper is x, and the first time: x is the (1-1) power of 2 times x

30th: 2 (30-1) power times x

So, fold 30 times, and the thickness of the paper is 2 (30-1) x 536870912*x liter bucket. 8844m

Hehe. It can only be expressed in words, and mathematical formulas cannot be played.

1.Because (2x+y-4) +x-2 =0

So 2x+y-4=0, x-2=0 11x-2x=100-42

So x=0+2=2, y=0-2*2+4=0 9x=58

So xy=2*0=0 x=58 9

3.Original = 36x y + 3x y -x y 4I haven't learned inequalities yet.

3=39x y²-x²y

5.Original=3(a -1) Original=4x(1+2xy+y).

3(a+1)(a-1) =4x(1+y)²

1. 0

Because the sum of two non-negative numbers is 0, they are both 0Therefore, x-2=0, 2x+y-4=0, x=2, y=0

2. x=58/9

3. -33x^3*y^3-x^2*y

4. Original equivalence 2x+2-3x-6<0

x<4

x>-4

5.Sorry, I can't see clearly.

1. The simplest fraction between one-third and 1 with a denominator of 12 is (5 12 or 7 12 or 11 12).

1: Find the midpoint of the three sides of the triangle and connect them sequentially.

2: Find the midpoint of the three sides of the triangle, connect a vertex with the midpoint of the corresponding edge, and then look at the picture by yourself.

3: Divide any side of the triangle into 4 points and connect the 3 points with the corresponding vertices <>

4: 41/42.

1.Verify that b2-4ac is greater than 0Since the coefficient of the quadratic term is greater than 0, the function image opens upward, and the real root is found, x1x2}

If b 2-4ac is less than or equal to 0, then it can be taken as [x x belongs to r}

2.First b 2-4ac > 0 i.e. 4m 2-4 (m+2)>0, m>2 and m<-1

The sum of squares of the real root is [ 2 + 2

b 2-2ac) a 2 = 4m 2-2 (m+2)> i.e. (2m-3) (m+1) >0

Get m>3 2 and m<-1

Take the intersection and get m>2 and m<-1

x1*x2=*=c/a

3.How to say this, it is the same.

If the coefficient of the quadratic term of the function is greater than 0 and the opening is upward, if the solution set is a non-empty set, then b 2-4ac is greater than or equal to 0

This question gives a<0, then b -4ac=(16a) 2-4*3*(-12a 2)=400 2 must be greater than or equal to 0

When a<0 is compliant. Find the real number and x1, x2, and x10 to get a range of m, and then c a<0 to get another range of m, and then the intersection of the two ranges, and finally get the range of m.

a+1 a=2, square both sides of this equation, which is the square of a + one square of a + 2=4

So the square of a + one square of a = 2

After putting (a+1 a)=2 squares, you can calculate, and the answer is equal to 2

The square of a + one of the squares of a = the square of (a + 1 a) - 2a * 1 a = the square of (a + 1 a) - the square of 2 = 2 - 2 = 2

(a+1 a) squared = 4 = a squared + 1 a squared + 2

So you want =2

Equal to 2....

a+1/a)^2=2^2

a 2+1 a 2+2 a 1 a=2 2 has come up with the answer a 2+1 a 2=2

The square of a + the square of a = the square of (a + 1 a) - 2 = the square of 2 = 4 - 2 = 2

A squared + a square = (a + 1 a) square - 2 = 2

Equal to 2....Because it can be calculated that (a+1 a) square is equal to 4.

2, a+1 a=2 through the differentiation of a 2-2a+1 = 0 can be solved a=1, so a 2 + 1 a 2 = 2

The first Friday is 16-14 = 2.

The 5th of this month is the 1st of the week

Let the first Friday be the number x, and the next Friday will be 7+x, 14+x, 21+x, 28+x

then x+7+x14+x21+x28+x=80

x=2 so the 5th is Monday.

The 2nd is the first Friday, then the 5th is the Monday.