It is known that the solution of the unary equation 4x 2m 3x 1 and 3x 2m 6x 1 about x is the same to

Subtract both sides of the equation to obtain: x=-3x, solve x=0, and substitute any one of the equations to get m=1 2

Solve the equation: 4x+2m=3x+1, shift:

4x-3x=1-2m, merge similar items:

x=1-2m

Solve the equation: 3x+2m=6x+1, shift term:

3x-6x=1-2m, merge similar items:

3x=1-2m, coefficient: 1:

x=(1-2m)÷(3)

x=(2m-1)/3

1-2m=(2m-1) 3, then solve the equation: remove the denominator, and multiply 3 on both sides of the equation at the same time to obtain:

3 (1-2m) = 2m-1, remove parentheses:

3-6m=2m-1, shift:

6m-2m=-1-3 merge similar terms:

8m = -4, coefficient: 1:

m=-4÷(-8)

m=1/2

4x+2m=3x+1 3x+2m=6x+1x=1-2m x=(2m-1)/3

Because their solution is the same.

So there is 1-2m =(2m-1) 3

m=1/2

Solve the equation: 4x+2m=3x+1, shift:

4x-3x=1-2m, merge similar items:

x=1-2m

Solve the equation: 3x+2m=6x+1, shift term:

3x-6x=1-2m, merge similar items:

3x=1-2m, coefficientized Zhongxiang 1:

x=(1-2m)÷(3)

x=(2m-1)/3

1-2m=(2m-1) 3, then solve the equation: remove the denominator, and multiply 3 on both sides of the equation at the same time to obtain:

3 (1-2m) = 2m-1, to bracket the volt number:

3-6m=2m-1, shift:

6m-2m=-1-3 merge similar terms:

8m=-4, coefficient 1: number of halls.

m=-4÷(-8)

m=1 2 The solution of the equation 4x+2m=3x+1 is the same as that of the equation 3x+2m=6x+1 about x, find the value of m.

4x+2m=3x+1

x＝1－2m

3x+2m=6x+1

x＝﹙2m－1﹚3／

m＝1/2

Solve the equation: 4x+2m=3x+1, shift:

4x-3x=1-2m, merge similar items:

x=1-2m

Solve the equation: 3x+2m=6x+1, shift term:

3x-6x=1-2m, merge similar items:

3x=1-2m, coefficient: 1:

x=(1-2m)÷(3)

x=(2m-1)/3

1-2m=(2m-1) 3, then solve the equation: remove the denominator, and multiply 3 on both sides of the equation at the same time to obtain:

3 (1-2m) = 2m-1, remove parentheses:

3-6m=2m-1, shift:

6m-2m=-1-3 merge similar terms:

8m = -4, coefficient: 1:

m=-4÷(-8)

m=1/2

Solution: (1) The solution of equation 4x+2m=3x+1 is x=1-2m, and the solution of equation 3x+2m=6x+1 is x=(2m-1) 3The solution of equation 4x+2m=3x+1 and equation 3x+2m=6x+1 is the same, then there is.

1-2m=(2m-1)/3

So m=1 2

2) Algebraic formula(m+2) 2011*(2m-7 5) 2012=[(m+2)*(2m-7 5)] 2011*(2m-7 5).

(1) It is known that the solution of the equation 4x+2m=3x+1 and the equation 3x+2m=6x+1 is the same. (1) Find the value of m.

Solution: Obtained by x=1-2m

From x=(2m-1) 3

then 1-2m=(2m-1) 3

The solution yields m=1 2

2) Find the value of the 2011th power * (2m - 7/5th) of the algebraic formula (m+2).

Solution: m=1 2 yields the 2011th power of the original formula = (5 2) and the 2012th power of (-2 5).

5 2) to the power of 2011 and 2 to the 5 power of 2012.

5 2) to the power of 2011 2 5 to the power of 2011 2 5 = (5 2 2 5) to the power of 2011 2 5 = 1 to the power of 2011 2 5

4x+2m=3x+1

x=1-2m

3x+2m=6x+1

3x=1-2m

x=(2m-1)/3

The solution of the equation 4x+2m=3x+1 is the same as that of the equation 3x+2m=6x+1.

1-2m=(2m-1)/3

m = 1 2 2m + 2) to the power of 2011 * (2m - seven-fifths) of the power of 2012.

5 2) to the power of 2011 and 2 to the 5 power of 2012.

5 2) to the power of 2011 2 5 to the power of 2011 2 5 = (5 2 2 5) to the power of 2011 2 5

4x+2m-1=3x, we get x=1+2m

3x+2m=6x+1, we get x=(2m-1) 3, so 1+2m=(2m-1) 3

Solving the above unary equation yields: m = 1

Solution: Because the solution of the equation 4x+2m=3x+1 about x is the same as the equation 3x+2m=6x+1, 4x+2m=3x+1

4x-3x=1-2m

x=1-2m

3x+2m=6x+1

3x=1-2m

x=1-2m/-3

Substitution: 1-2m = 1-2m -3

3x(1-2m)=1-2m

3+6m=1-2m

4m=4m=1

So m=1