27 4x and 2x 1 1 0 with factoring process

27=4x²

4x²-27=0

2x - root number 27) (2x + root number 27) = 0

2x - root number 27 = 0 or 2x + root number 27 = 0

So x = (root number 27) 2 or x = (- root number 27) 2, where root number 27 = 3 times root number 3

2x²-1)²-1=0

2x²-1-1）（2x²-1+1）=0

4（x²-1）（x²）=0

4（x+1)(x-1)x²=0

x+1=0 or x-1=0 or x=0

So x=-1 or x=1 or x=0

Have fun.

2(x-2)(x-2)=(x+2)（x-2）；If x-2 is greater than or equal to zero, divide both sides by x-2 at the same time, and we get that 2x-4=x+2;It is obtained that x=6 when x-2 is less than zero.

, and divide by x-2 to get -2(x-2)=x+2;Gives x=2 3

Topic: Solving Equations Using the Defactoring Method.

2(x－2)²=x²+4。

Analysis: This is a problem for solving quadratic equations, which requires the solution to be solved by factoring the method, and it is found that there are common factors on the left and right sides of the equation.

x 2, x 2 can be extracted each, and then simplified to solve.

Answer: 2 (x 2) = x 4

2(x－2)²=x+2)(x－2)

2(x－2)(x－2)=(x－2)(x+2)2x－4)(x－2)=(x+2)(x－2)2x－4－x－2)(x－2)=0

x－6)(x－2)=0

x 6 = 0 or x 2 = 0

x=6 or x=2

Substituting x=6 into the original equation yields:

Left = 2 (6 2) = 32, right = 6 4 = 32 left = right, meaning that x=6 is the solution of the equation.

In the same way, substituting x=2 into the equation test shows that x=2 is also the solution of the equation.

So, the solution of the original equation is:

x = 6 or x = 2.

2(x-2)²=x²-4

2(x-2)²=x＋2)(x-2)

When x≠2, 2(x-2) = x 2

2x-4=x＋2

x=6 When x=2, the equation also holds.

Therefore x=2 or x=6

2x to the 2nd power + 8 = x to the 2nd power - 4

x to the second of two + four.

Brother Xie Yin: (x-2) 2-9(x+1) 2=0x-2) 2-[3(x+1)] 2=0

x-2)+3(x+1)][x-2)-3(x+1)]=04x+1)(-2x-5)=0

So 4x+1=0 or -2x-5=0

x=-1 4 or x=-5 2

4（x+3）²=25（x-2）²

4（x+3）² 25（x-2）²=0

2 (x +3) + 5 (x - 2)) (2 (x + 3) - 5 (x -2)) = 0

7x - 4) Jin Bridge (-3x + 16) = 0, so x = 4 7 or Buki x = 16 3

Solution: -(2x -5x.)

2x²-5x+

2=0(2x-1)(x-2)=0

x = 1 2 or x = 2

2. It seems that you can't use decomposition, this question is simpler with the formula method.

(-15)²-4•7•(-2)=225+56=281∴x=(15±√281)/14

-2x²+5x-2=(2x-1)(-x+2)=0;x=-1/2;x=2

7x²-15x-2

It is estimated that the question was copied incorrectly, and it cannot be broken down into a total factor.