The Four King Kongs VS the Eighteen Arhats, the Four Heavenly Kings vs. the Eighteen Arhats

Red: 2kq74

Black: KQ7643

Fang: K965

May: Q951Mei Q

34455667799qqkkk2

2.Mei Q-Fang 6

If the other party gets on A, we pass:

247qk3467qk

55 99 kk

If the opponent is on 10, we are on red Q:

346qk55 77 99 kk 4 2

If the other party continues not to do it, the other party is left with AA10, and we continue to play red 4, and the other party does not dare to play any at this time.

After the red 4, continue to play the red 7

The opponent AA10, our 3467Q + 55 99 KKKK 2 So, when the side 6, the opponent does not dare to dismantle the card.

3.Mei Q - Fang 6 - Red 4

If the opponent plays A, we play 2

kk 99 55

A 3467k pair wins.

If the opponent is on 10, we are on red Q:

2 7 kkk 55 99

3467q4.Mei Q - Fang 6 - Red 4 - Red 7

If the opponent plays A, we play 2

q kk 55 99

3467qk

If the opponent is on 10, we are on red Q:

2 kkk 55 99

3467q5.Mei Q - Fang 6 - Red 4 - Red 7 - Mei 5 - Red 2 - 34567 - KKK99 - QQ

Eighteen wins!

If you can't get three cards right, eighteen cards will lose. If three can be paired, the solution is as follows:

Flower: 2379qk

Square: 457qk

Red: 46qk

Black: 9561Red 6

457qk99qqkk2

2.Red 6 - Black 6

If the opponent is on 10, we are on Q:

344557799qqkkk2 is a win.

If the other party gets on A, we pass:

237qk44 55 99 qq kk 73.Red 6 - Black 6 - Flower 3

44557799qqqkkk2 If the opponent dismantles the card, the single wins.

4.Red 6 - Black 6 - Flower 3 - Black 9

If the opponent is on 10, we are on Q:

4455779qqkkk2 Win when you issue a single order.

If the other party gets on A, we pass:

279qk44 55 qq kk 7

5.Red 6-Black 6-Flower 3-Black 9-Flower 9-Flower 2-Q-kkk55-77 Eighteen Wins!

When A is playing 9 or 7, as long as B does not lose time in hitting 10, A will not be able to pass a pair of 4 and a pair of 5, and will lose.

You just have to let them hit once to know the result.

It seems that it can't be beaten, there are many people, and the group fight will be over!

This is a question you have to ask the people of Buddhism!!

Steps added:

I take 18 sheets.

I'm out of 3, the first case: if you want to come out of A, I won't come out, you will definitely lose;

The second case: if you come out of 10, I will come out of Q or K, and if you don't come out, I will dismantle 4, and if you continue like this, you will also lose;

The third case: if you don't come out, I will play 1 Q or K alone, and you will lose if you play A; If you don't come out, I'll split 4, and you'll still lose.

This situation? The third case: if you don't come out, I will play 1 Q or K alone, and you will lose if you play A; If you don't come out, I'll split 4, and you'll still lose.

How can I show 2 singles?

Follow "yujian tutu - probationary period level 1" like this:

18 sheets 4 sheets.

Out of 3 out of no.

The next thing I'm talking about is a single q or k, I didn't say 4, I want to leave one of 3 q or 3 k, if you don't come out, I'll split the right 4. For example, (I'm out of Q):

Out of Q out of A, I'm out of 2, there is still a pair of Q left, and then out of the pair of you won't lose?

Even if you don't come out, continue (I'll tear down 4):

I'm always just in the case of 1 order or no single at all.

Out of 4 out of 10, here you are out of 10, I only split 3 k, you out of A will lose.

Four cards: a pair of 10s, a pair of aces.

Eighteen cards: a 3, a pair of 4s, a pair of 5s, a pair of 7s, a pair of 8s, a pair of 9s, three queens, three kings, and a 2.

Or 18 cards to win.

First out of 3, then out of Q, and then out of a single 4, a piece of out, you draw a with 2 dozen, and then out of a pair.

On Q, big things come true

Fang: 256jk

May: 456jk

Red: 3479

Black: 79jk1Red 7

456jk99jjkk2

2.Red 7 - Black 7

If the other party splits 10, we will go to Q and win the bill.

If the other party dismantles A, we pass:

456jk99jjkk

3.Red 7 - Black 7 - Red 3

If the other party splits 10, we will go to Q and win the bill.

If the other party dismantles A, we go on 2, and the pair wins.

4.Red 7 - Black 7 - Red 3 - Mei 5

If the other party splits 10, we will go to Q and win the bill.

If the other party dismantles A, we pass:

256jk4499jjkk

65.Red 7-Black 7-Red 3-Mei 5-Fang 5-2-JJJ44-KKKK66-99 Multi-win! In the rules, 23456 must be counted as straight, and three belt pairs can be played, otherwise more will be lost.

I've seen 34567 hit out, he definitely doesn't want to play another 456jk he still doesn't want to play another 7, he definitely has an A pressed and then you have a 2 buckle back, hit K and J first, and finally play 9 If he doesn't press, continue to cancel the order and play with him Don't tear off his A Hit more than 10 pairs first. You can try it or not!