Is there a limit to the speed of an object falling from an infinitely high place towards the earth

First of all, when the object is infinitely high according to f=gmm r 2, its gravitational pull is very small and almost equal to 0, so it may not fall towards the Earth. Also, even if it falls to the earth, the speed will not be infinite, and the speed will not exceed the speed of light. Your question itself is problematic

According to the principle of acceleration, it is theoretically like this: infinite height, increasing velocity, but not exceeding the speed of light, and it has not been proved that the speed of an object exceeds the speed of light.

There is also a problem to consider: there is no gravitational force without infinite height, there is no acceleration without gravitational attraction, and it cannot be infinite without deceleration.

What you're talking about is just an ideal.

When I was in middle school, I had this naïve idea, but now I understand it.

In fact, there is no need to think about gravity.

First of all, you have to know that the gravitational force decreases with increasing distance.

Secondly, if you have studied advanced mathematics.

The Fourier series should be calculated.

For example, 1+1 2+1 4+1 16....

Even if there is an infinite number of add-ons.

But this polynomial must converge to a number no greater than 2.

So the speed is not infinite.

Let's talk about the theory of relativity.

According to Einstein's special theory of relativity, the formula for mass transformation.

I can't write it here, but you can look it up on the Internet for yourself.

When the speed reaches the speed of light, the mass is infinite.

And the sum of energy in the universe is finite.

So there will be no objects equal to or higher than the speed of light.

It can only approach the speed of light infinitely.

mgh=

The key is to know h

If yes, as the question: infinitely high.

Then the speed should also be unlimited.

And I think.

Gravitational force should be distance-bound.

So when a certain distance is reached.

There is no gravitational pull.

That is, there is no acceleration due to gravity.

g=0 => v=0

If it's within the gravitational range.

Just know the radius of the gravitational sphere.

Balance with energy.

That's how it should be.

mv 2 2 = gmm r, but don't forget that this formula can only be used when g (acceleration due to gravity) is certain - the mentally retarded will say like you. That's the formula. r is the radius of the earth.

According to you, this is unassailable. But in nature, will this happen in our universe?!

It is not possible to take into account the impact of other planets, and not to consider resistance.

Since it is infinitely far away from the Earth, the gravitational force is 0 and will not fall to the Earth.

An object falls freely from a height of h=45m, and the object falls to the ground after time t, g=10ms 2, h=1 2*gt2, and t=3s.

It can be seen that the initial velocity of the last second is the ant'= 2s of the final velocity v, v = gt'=20m/s。

The height of passage in the last second is x = 45m - the front t'= displacement of 2s, x=45m-1 2* gt'^2=45m-20m=25m

h=1/2gt^2;

t=3s;A total of three seconds, the beginning velocity of the last second is the end velocity of the first two seconds;

v=0+gt=20m/s;

The same goes for the end velocity after 3s.

v=30m/s;

s=(20+30)/2*1=25m;

Free Fall Movement:

H = 1 2gt 2, t = 3 seconds, g takes 10.

The object falls to the ground for 3 seconds.

Summary. Hello! Dear, I'm glad to answer for you, the horizontal linear velocity around the earth will not decrease when an object is falling freely relative to the ground.

Because when an object is falling freely, its velocity changes only in the vertical direction, whereas the horizontal linear velocity is in the horizontal direction, so the horizontal linear velocity does not change. When an object is falling freely, the kinetic energy of the object becomes less due to gravity and is converted into potential energy. This is in line with the law of conservation of kinetic energy, as the law of conservation of kinetic energy is defined as the fact that kinetic energy does not change when the object falls freely, i.e., the sum of kinetic energy does not change.

Will the horizontal linear velocity of an object falling high in the air at a stationary height decrease relative to the ground? So how does the overall kinetic energy change? Is it still possible to simply use the law of conservation of kinetic energy?

Hello! Dear, I'm glad to answer for you, the horizontal linear velocity around the earth will not decrease when an object is falling freely relative to the ground. Because when an object is falling freely, its velocity changes only in the vertical direction, whereas the horizontal linear velocity is in the horizontal direction, so the horizontal linear velocity does not change.

When an object is falling freely, the kinetic energy of the object becomes less due to gravity and is converted into potential energy. This is in line with the law of conservation of kinetic energy, as the law of conservation of kinetic energy is defined as the fact that kinetic energy does not change when the object falls freely, i.e., the sum of kinetic energy does not change.

In general, when an object is in free fall, the horizontal linear velocity around the Earth does not change, but the overall kinetic energy becomes smaller, and this is consistent with the law of conservation of kinetic energy.

But after the object reaches the ground, it is still stationary relative to the earth, the radius becomes smaller, and the linear velocity will not become smaller (although the radius becomes very small) What is the potential energy, and the decrease in gravitational potential energy should not bring about an increase in kinetic energy I am mainly curious about the decrease in the horizontal linear velocity of the object, and what the corresponding kinetic energy has become I think about a little too much, sorry.

Dear, how many questions do you have?

When an object hits the ground, it is indeed right to be stationary relative to the Earth. The radius of the object becomes smaller, resulting in a smaller linear velocity. This is because when an object lands, it is subjected to friction and air resistance, which slows down the object.

Gravitational potential energy is the energy produced due to the gravitational action between an object and the earth. When an object lands, the gravitational potential energy decreases while the kinetic energy increases. This is because the object is subjected to an elastic force when it lands, which causes the object to experience an increase in kinetic energy.

The linear velocity of the object decreases horizontally, and the corresponding kinetic energy is converted into heat energy generated by friction and air resistance. This heat energy is absorbed by the object and other objects in the environment.

Okay, thank you, I will give five stars, then if I take the ground as a reference frame, the object falls vertically, theoretically the horizontal direction should not be forced, do you have to consider the geostrophic deflection force?

If the ground is used as the frame of reference and the object falls vertically, then the object will not be subjected to external forces in the horizontal direction. Because the motion of the object is linear motion and there is no horizontal component. However, if the influence of the Earth's rotation on the falling motion of the object is considered, there will be a geostrophic deflection force, which may cause the object to have a small velocity component in the horizontal direction.

This velocity component is due to the rotation of the Earth.

How much time elapses for an object to free fall from a height above the ground, the kinetic energy of the object and the gravitational potential energy are equal. To see how high an object has freefallen from a height above the ground, the kinetic energy of the object is equal to the gravitational potential energy. Conservation of mechanical energy.

When the height is half, the potential energy is half of the original, and the other half is kinetic energy, and the kinetic energy and gravitational potential energy are equal when the height is equal.

The time of falling the meter is t, then h=(1 2)*g*t 2t=

Summary. 1) According to the formula: h=gt2:

The falling distance h1 = 10 12 m = 5 m in the first s (2) Let the height of the object from the ground when it begins to fall be h, and the falling time is t, then there is: h=gt2....①h-4h1=g（t-△t）2…By-De:

4h1=gt2-g（t-△t）2，∴t= s…(3) Substituting the formula to obtain: h= 10 ( m= m Answer: (1) The distance of falling in the first s: 5m (2) The height of the object from the ground when the object begins to fall at the time when the object is moving in the air.

1. It is known that an object starts to move from a certain height above the ground and collapses, and the known object falls 5 meters within 1 second, and the object falls to the ground after 5 seconds. (g=10m s2) to find: (1) How high is the object from the ground at the beginning?

2) How fast is the object at the moment it hits the ground? (3) Displacement of the object in 2 seconds (4) Displacement of the object in 3 seconds?

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Is it okay to hurry up.

1) According to the formula: h=gt2: the distance of the falling of the escort in the first s, h1= 10 12 m=5 m (2) Scatter resistance:

The height of the object from the ground when it starts to fall is h, and the fall time is t, then there is: h=gt2....①h-4h1=g（t-△t）2…obtained by - 4h1=gt2-g(t- t)2, t= s....(3) Substituting the formula to:

h= 10 ( m= m Answer: (1) The distance of the falling Ashiga in the 1st s is 5m (2) The time when the object is moving in the air, the height of the object from the ground when it starts falling.

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If the distance of a free-fall is infinite, is it possible for an object to reach the speed of light?

v^2=2gh=2*10*20=400

The velocity when reaching the ground is v=20m s

The time taken to fall to the ground is t=v g=20 10=2s