-
Piece; represents the intersection of the straight line 2x-y=1,x+4y=5, and the intersection is found as (1,1) on the straight line y=x, then d is encapsulated by c;
b=,(1)When a=3,a b=,a b=empty set; (2) When a=1, a b=, a b={1}; (3) When a=4, a b=, a b={4}; (4) When a is not equal to 1, 3, 4, a b = and a b = empty set;
Since a (cub)=,b=,a=,
-
Scores. k 2 + 4 = (hail with light 2k + 1) line friend 4n = k 4 + 2 = (k + 2) 4
2k+1 is always an odd number.
k+2 may be odd or even.
The source width is contained in m and n
-
8 Yes, (a,b) and (b,a) are different sets, so the ab set can be equal, a b = so there must be 1,3 elements in the ab set.
a=,b=---2 pairs.
a=,b=---2 pairs.
a=,b=---2 pairs.
a=,b=---2 pairs.
a=,b=---1 pair.
It's not right just now.,It's not in line with the topic of a b=.,This is right for you.。
-
a={x |4x+p<0} closed pei lao={x |x<-p 4} and a are contained in the car lift b
The result is -p 4 less than or equal to -1
So p is greater than or equal to 4
-
p 4> Kai socks-1 and talk about Sun Bang-p Han talk 4>2
P<4 and P<-8
The value range is p<-8
-
The set a=,p= q=, so there is: p=,q=
Since p=q, then there is: q=
If q=, then there is: a=0, p=q=
If q=, then there is: a 2 = a + 1, there is a = (1 + 5) 2
-
cua=,k∈z}
cub=,k∈z}
So there is: a is the true subset of cub and b is the true subset of cua.
-
I've just learned, so I hope to communicate more in the future.
If all elements of set A are also elements of set B, then A is said to be a subset of B;
If there is an element in b and not in a, and a is a subset of b, then a is said to be a true subset of b.
a.{Yes {x|.}x root number ten} (false).
When x=3, x" root number ten, so { is not {x|x root number ten}, not a true subset.
b.{1,2,3} is a subset (error) of {0,1,2,5}
Element 3 does not belong to the set of Min homozygous {0,1,2,5}
c.{x|x-1=0} is {x|(x-1)(x+2)=0} of the Mako and Stool set (correct).
x-1=0, then x=1
x-1)(x+2)=0, then x1=1, x2=-2
So, {x|x=1} is {x|x1=1,x2=-2
The true subset of the bridge shed.
d.{-5,7} is {x|x 20} (error).
Elements -5,7 do not belong to the set {x|x²<20}
I think this kind of question starts with the concept, I hope it can help you.
-
c subset is that it can have the same as itself, and the true subset is in addition to itself, so don't understand it, and then ask.
-
For example, in analytical and computational physics, it is necessary to have knowledge and skills such as mathematical functions and equation solving. (5) Ability requirements: Of course, I am a mathematics teacher. I have brought back many graduating classes of Gao Liquid World Slow High School, and I am currently teaching the first year of high school. Thank you for looking at me.
-
The square of a3 is less than 10
The latter does not have a 3 in B, and the former is not a subset of the World Bank of the Zoye latter.
c Pair. D7 squared Punch pants 20
The numerator and denominator are multiplied by cos10° at the same time >>>More
m<=(a+b+c)(1 a+1 b+1 c)m<=3+b a+c a+a b+c b+a c+b c because b a+a b>=2, a=b, c=2b, c=2a=2b >>>More
1. Knowing a= , b= , a a, and a b, find aa a, and a b, and solve the simultaneous equations of y=2x-1, y=x+3 to obtain x=4, y=7a=(4,7). >>>More
'=a-1 x 2 because x [1,+infinity]so x 2>0
That is, the minimum value of ax 2-1 0 a 1 x 2 is obtained when x=+ infinity. >>>More
First of all, let's talk about the idea, 56 = 2*2*2*7, so only log42 2 and log42 7 are required >>>More