Electrolytic dilute sulfuric acid to H2,O2,Electrolytic dilute sulfuric acid to H2,O

Electrolysis of dilute sulfuric acid is electrolysis of water.

Positive 4oh- -4e- = 2H2O + O2 Negative 2H+ +2E- =H2

Total reaction 2H2O=Electrolysis=2H2 +O2 The reason for this reaction is that the hydroxide ions are electrolyzed first because the sulfate ions are more difficult to be electrolyzed than the hydroxide ions. Oxygen is produced after the hydroxide is electrolyzed.

Hydrogen ions are electrolyzed into hydrogen. It's the equivalent of electrolyzed water.

The electrolysis of dilute sulfuric acid is equivalent to the electrolysis of water, because the oxygenate is more difficult to electrolyze, so the principle is the same as the reaction of electrolysis of water

I'll give you the high score.

I would say that the reaction is actually more complicated.

Electrolysis is actually a redox reaction.

Let's start by looking at the ions in solution.

The cation only has hydrogen ions (essentially hydrogen hydration ions, which can be understood as this way here), so the anode only has hydrogen ions for electrons.

Anions are: hydroxide ions and sulfate ions.

Due to the difference in structure, although hydroxide is relatively stable, it is not as stable as sulfate, because sulfate (oxygenate) is difficult to ionize and the structure is stable, so the cathode can only be oxygen in hydroxide to lose electrons to form oxygen.

And the addition of sulfuric acid to pure water is to ionize sulfuric acid, increase the conductivity of water, and speed up the reaction rate. Finish.

When you go to college, you don't have to write like this. However, from the analysis of high school, due to the limitations of high school learning, it is generally not written as what you write, because in high school, the left and right sides of the general equation cannot appear at the same time, one side is oh-, and the other side is h+.

In the case of electrolysis of dilute sulfuric acid, from an ionic point of view, the anode particles that can be discharged are OH- and SO42-, and although the concentration of hydroxide ions is small, OH- is still preferentially discharged. So it is written as 4oh- -4e- o2+2h2o.

In addition, since oh- here comes from weak electrolyte water, it is better to write it as 2H2O -4E-O2+4H+.

It is not possible to present oh- in large quantities under acidic conditions, only h2o can be written

Landlord, you are right about the ionic equation you wrote.

2h2o-4e^=o2+4h+

Because it is the hydroxide ions in the water that react, it is less likely to make a mistake when writing it as water.

How many grams of electrolyzed water is the mass in this process? How many grams of hydrogen and oxygen are produced? (There is no change in sulfuric acid in the reaction).

The mass of the electrolyzed water is set to x grams.

Then 200*8%=(200-x)*20%.

The solution is x=120

Let the hydrogen be generated in Y grams.

2h2o = 2h2+o2

120 y36:4=120:y

y = gram) number of grams of oxygen produced = grams).

And then, what do you want?

The conductivity of pure water is weak, and the experiment is slow, so the electrolysis of water.

Dilute sulfate or sodium hydroxide is often added to the water.

to enhance the conductivity of land and water; After electrolysis of water for a period of time, water decomposes to produce hydrogen and oxygen, the acidity of dilute sulfuric acid is enhanced, when the pH of the solution is less than 7, it is acidic, and the smaller the pH, the stronger the acidity, so the pH of the solution gradually decreases

Therefore, the answer is: to enhance the conductivity of water; Decrease

Zn+H2SO4==ZnSO4+H2 H2+CuO=(High Temperature)=Cu+H2O

zn →h2→cu

The amount of matter is 1: 1: 1

Mass 65g 2g 64g

Therefore, theoretically, 65g of zinc needs to be consumed to obtain the volume of hydrogen v=n*vm=1mol*; Because zinc generally contains impurities, the actual value is greater than the theoretical value.

1. According to: Zn+H2SO4=ZnSO4+H2 (gas); H2 + Cuo = Heating = Cu + H2O

Relation: zn---h2---cu

x y 64g

65/64=x/64g 2/64=y/64gx=65g y=2g

So if you want to get 64 gcu, theoretically consume 65 grams of zn;

2. The volume of H2 in the standard case is: 2g;

3. Because in the reaction of hydrogen to reduce copper oxide, hydrogen must first be introduced for a while, and after the experiment, hydrogen should continue to be introduced to the test tube for cooling, so that the mass of hydrogen consumed by 64 grams of copper is greater than 2 grams, that is, the mass of the actual consumption of Zn is greater than the theoretical value.

2H2O = = Electrolysis = = 2H2 + O2

36g 4g

xg 2000g

Then: or stool smock 36 coarse He x = 4 2000

x=18000g=18kg

Which branch to solve: Li Sui 2H2O ==2H2 + O22*18 2*

38 x y

x=y=