A small question, please help a lot.

You can use the "Interval Statistics" function. In the **figure, move the cursor to 2319 points**, hold the right button, and then pull the cursor to aim at 3186 points**, a rectangular box will be pulled, as soon as you let go, it will prompt you "interval statistics", click on it, and the result will pop up, not only telling you that there are 87 numbers in this range, but also a lot of information. If the time span is used, it should be reduced by one, that is, 86 trading days have passed.

In terms of zooming in, zooming out, and searching left and right of the historical map, Tongdaxin is the most convenient. For example, if you want to see 6124 points, press the arrow of the keyboard "down", zoom out to enter the screen earlier, and then move the cursor to 6124 near the **, press the keyboard "up" arrow, and the software will quickly zoom in on that day.

Using "interval statistics" is flexible, fast, and convenient. But to enter the screen at two o'clock at the beginning and the end, if it is more than 300 days, ** will be very small, not easy to accurately position, which is considered a disadvantage.

1. 5 25+20= 11% more.

2. (48 ()+48= then ()=72

3. 48-() 48+()= ()=32 ;

24-24*25%=18m 24-24*25%.

4. 120-6 120= The survival rate is 95%.

5. 4 16 + 20 =, 11% more 4 20 = 20% faster

Six, 12 60=, reduced by 20% Yuan Cheaper 120 Yuan.

7. Suppose that the total length of this highway is a meter, then there is an equation 40%a-25%a=30, that is, the solution is a=200 kilometers,,, that is, the total length of this highway is 200 kilometers.

8. Set: A and B are separated by S kilometers, then according to the topic; 15%s+35=1 2s, i.e., there is a solution s=100 km.

Then, A and B are 100 kilometers apart.

The answers, in order, are

Naughty has 25 extracurricular books, Xiaoxiao has 20 extracurricular books, the number of naughty extracurricular books is more than Xiaoxiao's (25)%, and Xiaoxiao's extracurricular books are less than Naughty's (20)%.

20% more than 48 and 48 20% more than (40).

A wire is 24 meters long, and if you use 25% of it, you will be left with (18) meters; If you use more rice, you will be left with (40)% of the wire

The school planted 120 trees, and 6 classes did not survive, and the survival rate was (95)%.

From school to the Youth Palace, it took 20 minutes for Xiaoxiao and 16 minutes for Naughty, Xiaoxiao took more time than Naughty (25)%, and Naughty was faster than Xiaoxiao (20)%.

A part, the original cost of 60 yuan per piece, reduced by 12 yuan, a reduction of 20 percent?

The original price of a dress is 800 yuan, and it is discounted by 120 yuan?

An engineering team repaired a highway, repaired 25% of the total length in the first week, 40% of the total length in the second week, and repaired 30 kilometers more than the first week in the second week. (Solved with equations) 200 km.

Suppose the highway is x kilometers long, and the equation can be obtained.

x multiplied by (40%-25%) = 30

The solution yields x=200

A car has traveled 15% of the way from A to B, and another 35 kilometers is exactly half of the journey. How many kilometers are A and B apart? 100 km.

One. （25-20）/20=25%、(25-20）/25=20%、（x-48）/48=20%.x=,(48-x）/x=20%.x=60, two. 24 (1-25%)=18, (iii.) (120-6) 120=95%, IV. (20-16) 16=25%, (20-16) 20=20%5. 12÷60=20%

Six. 800×（1-85%）=200

Seven. Let the total length be x kilometers, then: 40%x-25%x=30, x=200 eight. 35÷（50%-15%）=100

1 25% 20% 20% 2 40 3 18 40% 4 95% 5 25% 25% 6 20% 7 12 8 40% x-25% x=30 x=200 9 100

Solution 1: From (3b-2) +丨2a-b-3丨=0, 3b-2=0 and 2a-b-3=0, the two solutions are obtained by a=11 6, b=2 3.

Therefore, substitution can obtain 5(2a-b)-2(6a-2b+4)+(4a-3b-2)=2a-4b-10=-9

EnglishYou can go to English**, or just look up the grammar, I'm going to sleep too, I'm sorry, I can only help you with that.

No problem. If A gives 1 2 of his matches to B, then B's matches are 4 3 of A, and the ratio of the number of matches of A and B before the division is: ( c 6:

1 Solution: Assuming that the number of matches of A and B before the division is x and y, then the number of matches of A and B after the division is 1 2*x and 1 2*x+y, then: 1 2*x*(4 3)=1 2*x+yx:

According to the three conditions of (1), (2) and (5), you can list all the cases where the four additives are different from each other, and the maximum number of additions does not exceed 7, and the sum is 17:

According to the two conditions (3) and (4), it is not difficult to see that the number of rings of four bullets per person is grinding:

A: 1, 3, 6, 7

B: 2, 3, 5, 7

C: 2, 4, 5, 6

From the above analysis, it can be seen that the number of rings of A and C is 6