Math Problem 1 Junior 1 Question 5

There are a total of 10 boxes of milk powder, numbered 1·10, one bag from the first box, 2 bags from the second box, 3 bags from the third box, and so on, until 10 bags are taken out from the tenth box. Let the weight be weighed and the result is x grams, then there is less (55 times 400-x) grams, because each bag is 20 grams less, so the answer is (55 times 400-x) divided by 20

Boxes are numbered from 1 to 10.

Then take out 1 bag from the first box in turn. Take out 2 bags from the second box. Take out 3 bags of ...... in the third boxTake out 10 bags from the tenth box. Put it together and weigh it.

If all the milk powder is sufficient. Then the weight should be 22,000 grams.

But the actual weight is definitely less than that.

Let's say it's actually weighed out as x grams. That's less (22,000-x) grams, which is caused by the insufficiency of those bags of powdered milk.

It is known that if each bag is less than 20 grams, then the number of bags of insufficient milk powder is (22000-x) 20 bags.

That is, the number of the under-enough milk powder box.

We did it before, very bt, forgot.

The AC is located at a distance of x km. (Equal use time).

x÷4+（18-x)=x÷60+（18-x）÷41/4x+3/10-1/60x=1/60x+1/2x-1/30x=

7/12x=

x=9ac equals 9 kilometers.

Each walked 9 km, because the AC distance is equal to the walk distance of the students in group B, and A is 18-9=9 km.

I'm in the sixth grade, so I don't know if it's okay to do it like this

Observing the graph, it can be concluded that in the nth graph, the number of small rectangles on the long and small rectangles of the large rectangle is 2n-1

The number of small rectangles on the width of a large rectangle is 2n

40 cm = Therefore, the length of the rectangle on the floor of the gymnasium contains a small rectangle, and therefore the width contains 52 small rectangles.

So the total number of small rectangles is 51 52 = 2652.

Therefore, the total cost: 2652 4 = 10608 (yuan).

When the number of transverse blocks changes2,4,6,8...

When the number of vertical blocks changes, 1, 3, 5, 7...

From the meaning of the title, it can be seen that the length of the rectangular ground is, the length of the rectangular wooden block is 40cm=, then the number of vertical wooden blocks is the block, according to the relationship of the equal difference series, the rectangular ground has been laid 26 times ((51+1) 2=26), then.

Transverse wooden blocks were also laid 26 times.

The number of blocks required is 51 52 = 2652.

Therefore, the total cost: 2652 4 = 10608 (yuan).

a1=26

a2=65a3=122

a4=26...After every three cycles.

Since 2008 is divided by 3 and 1, a2008=a1=26

26 is calculated to the 2nd power of the first n1 + 1 = 26, which is a1

Calculate the sum of the digits of a1 to get n2=8

Calculate n2 to the power of 2 + 1 to get a2 = 65

Calculate the sum of the digits of a2 to get n3=11

Then calculate n3 to the 2nd power + 1 to a3 = 122

Calculate the sum of the digits of A3 to get n4=5

At this time, there was a cycle ......

2008 3 = 669 surplus 1

So a2008=26

Solution: Suppose this fan buys x men's basketball tickets, table tennis tickets (15 x) 1000 x 500 (15 x) = 120001000x 7500 500x = 12000500x = 12000 7500

500x=4500

x=9A: He can buy 9 tickets for men's basketball and 6 tickets for table tennis.

Solution: If you buy x tickets for men's basketball, you will have 15-x table tennis tickets.

1000x+500(15-x)=12000 gives x=9

A: Buy 12 men's basketball tickets and 6 table tennis tickets.

Set up x tickets for the men's basketball team, then.

1000x+500(15-x)=12000

x=9 so 9 tickets for men's basketball and 6 tickets for table tennis.

Set x Zhang men's basketball team.

Y table tennis.

x+y=15

1000x+500y=12000

x=9 y=6

Nine male blues. 6 table tennis balls.

Set to buy x basketball tickets and y table tennis tickets. We get a system of binary linear equations: x+y+=15, 1000x+500y=12000, y=6, x=9

You can buy x men's basketball tickets and y table tennis tickets.

then 1000x+500y<=12000, and x>=0,y>=0,x+y=15, solve the system of equations 1000x+500y<=12000x+y=15; Get {x=9y=6.).

m=-2n=1

In junior high school, there is also a sprinkle in addition to this.

Bonus points It doesn't matter what the key is, what is the problem?

What is the requirement for this formula???

It is about x kilometers from Jiangbei Airport to the Liberation Monument, and the equation is obtained according to the conditions.

5+(x-5)*

x=45

Set x km.

The 5+ answer should be 45 km!

It is located about x kilometers from Jiangbei Airport to the Liberation Monument.

5+x=45

Because less than one kilometer is counted as one kilometer.

So 44

y=5+ is 53 and x is 40, so it's forty kilometers.

Solution: It is about x kilometers from Jiangbei Airport to the Liberation Monument.

Solution x=40

A: It is about 40 kilometers from Jiangbei Airport to Jiefang Monument.

I took a look at the ls, and there was only one right, note: the title "more than 5 kilometers in addition to 5 yuan should be calculated as one kilometer yuan" includes the first 5 kilometers!

Solution: Let the distance be x

Solution x=45

It is 45 kilometers from Jiangbei Airport to Jiefang Monument.