Under the standard condition, the same number of atoms as 48g of O2 is .

48go2 Quantity of matter 48 32= o Quantity of atomic substance = 3mola 8g ch4 Quantity of matter Quantity of matter of atom b Water is liquid.

c 17g nh3 1molNH3 Amount of atomic substance 4Mold Helium 3molhe Amount of atomic substance 3mol Answer d

48g O2: Amount of oxygen substance: 48 32= Oxygen atom:

a. The amount of 8GCH4 substance: 8 16= Number of atoms:

b. The amount of H2O substance: The topic is that under the standard condition, 0 degrees, H2O is the state of ice, which cannot be calculated.

c. The amount of 17g NH3 substance: 17 17=1mol Number of atoms: 1*4=4mol

d. The amount of helium substance: HE is a noble gas, so the number of atoms is 3mol

8g of methane is, it contains atoms.

48g of oxygen is, contains 3mol of atoms.

In the standard state, gas is 3mol, and helium is a monoatomic molecule, so there are 3mol atoms.

48g O2 contains 3mol of oxygen atom d is exactly 3mol of helium atom because helium is a monoatomic molecule.

The amount of CO2 of the substance.

Yes n=m m=44 44=1mol

1 CO2 contains 1 C atom and 2 O atoms, a total of 3 atoms, so it is 3mol, that is, 3 Na trembling atoms.

Let's start with the extinction hidden carbon dioxide starvation stall 22 44 = mol.

Total number of atoms = ammonia Total number of atoms = 5

The number of moles is 5=

Number of moles = moles.

Volume = litres of ammonia and gas.

That is, the total number of atoms in a liter of ammonia is equal to the total number of atoms in 22 grams of carbon dioxide.

m (h2so4)=98g/mol

The amount of matter: n = m m = 98 98 = 1mol of the number of h atoms of the number of h atoms of the reed: n = 2 * 1 * na=2na the amount of the high notice of the substance with o atoms n(o) = 4mol

Oxygen: 1 32mol, 2 32mol atoms liter decon.

Iron: 1 56mol, 1 56mol atoms.

Hydrogen noisy gas: 1 2mol, 1mol atom.

Nitrogen: 1 28mol, 2 28mol atoms.

It was hydrogen.

44 grams of carbon dioxide.

The amount of matter is 1mol, and there are 2mol of oxygen atoms and 1mol of carbon dioxide in 1mol of carbon dioxide molecule.

The total number of atoms is 3* to the power of 23.

Let's find the number of mols first, 44g [(12+16*2)g mol] = 1mol

A CO2 molecule contains three atoms, i.e., one carbon atom and two oxygen atoms.

So 1molCO2 contains 3* atoms to the power of 23

The amount of carbon dioxide in 44g is 1 mole, and 1 mole of carbon dioxide contains 1 mole of carbon atoms and 2 moles of oxygen atoms, a total of 3 mole atoms, so the number of atoms contained in 44 grams of carbon dioxide is 3*.

(1) Under standard conditions, the amount of 4g H2 is: n=m

m=4g2g/mol

The amount of 2mol,O2 is: n=vvm, and the amount of H2O is 1mol, according to n=n?Na can be seen that under the same conditions, the more the amount of substances in the gas, the more the number of molecules, so the largest number of molecules contained is H2;

According to the composition of the molecule, it can be known:

The number of atoms in 4g H2 is 2 2mol Na mol=4Na, the number of atoms in O2 is 2, and the number of atoms in 1mol H2O is 3 1mol Na mol=3Na, therefore, the largest number of atoms is H2;

The mass of O2 is: m=n?m=, the mass of 1mol H2O is: 1mol 18g mol=18g, therefore, the largest mass is H2O;

Under the same conditions, the more substances, the larger the volume of gas, but under the standard condition, water is liquid (or solid) and the volume is the smallest, so the answer is: h2; h2；h2o；h2o；

2) According to Avogadro's law, under the same conditions, any gas of the same volume contains the same number of particles, then: at the same temperature and pressure, the ratio of the number of molecules of methane (CH4) to carbon dioxide in the same volume is 1:1;

According to n=n?na can be seen that the ratio of the quantity of matter is 1:1;

If a methane molecule contains 5 atoms and a carbon dioxide molecule contains 3 atoms, the ratio of the total number of atoms is 5:3;

According to m=n?m shows that when the quantity of matter is the same, the ratio of masses is equal to the ratio of the relative molecular mass, then the ratio of masses is 16:44=4:11;

According to the ratio of the density of the gas at the same temperature and pressure, the ratio of the density is equal to the ratio of the relative molecular mass, then the ratio of the density is 1:11

So the answer is: 1:1; 1：1；5：3；4：11；4：11．