Sixth grade application questions a bit difficult .

1) The sum of the inner angles of the triangle is 180, divided into 9 parts, each part is 20, then the three corners are 20*2=40, 20*3=60, 20*4=80

2) The sum speed of the two cars is 270 km/h.

The speed of car A is 108*5 9=60 km/h.

The speed of car B is 108*4 9=48 km/h.

3) I didn't make it clear which was the end.

The speed of the passenger car is 4-3=1 faster than that of the truck, so the passenger car travels 6*2=12 kilometers more than the truck.

Then the distance between A and B is (3+4)*12=72 kilometers.

4) Cement accounts for 1 6 of concrete, tons of concrete contain tons of cement, 500 kg of cement is only tons so not enough 5) After 2 3 of the number of soccer balls is replaced by basketball, there are 60 * 1 4 = 15 footballs, and 60-15 = 45 basketballs.

Then the football originally had 15 * 3 = 45.

Answer: The three angles are 40°, 60°, 80°A: 108*(5 9)=60 (kilometers per hour) Answer: Car A travels 60 kilometers per hour.

3) It should be the midpoint, not the end.

6 2 [(4 7)-(3 7)] = 84 km A: The distance between the two stations is 84 km.

Tons) tons = 1100 kg.

A: 1100 kg is needed, so 500 kg of cement is not enough for 60*1 (3+1)=15pcs.

15 (3 5) = 25.

The number of basketballs is:

60-25 = 35.

2) 270 5 + 4 = 9 A: 108 * 5 9 = 60 (km) 3) The ratio of the speed of the truck to the speed of the passenger car is 3:4 The distance ratio at the time of meeting is 4:

3 Passenger cars traveled 4 (3 4) 4 7 Trucks traveled 1 4 7 3 7 Passenger cars traveled 6 2 12 km more than trucks at the time of meeting A and B were 12 (4 7-3 7) 84 km apart.

4) The amount of cement required for tons of concrete is: tons The amount of cement given in the question is: 50*10=500kg=tons So it is not enough.

5) The number of soccer balls is replaced by 2 3 for basketball, and the remaining number of soccer balls is: 60*1 (3+1)=15 that is, 3 5 is 15, then the number of soccer balls is 15 (3 5)=25 The number of basketballs is: 60-25=35.

Its three angles are 40 degrees each. 60 degrees. 80 degrees.

2) 270 km).

108 (5+4) = 12 (km).

12*5=60 (kmh). The speed of car A.

3) Is the end point a nail or a B?

4) tons) = 1100 (kg).

500 kg of cement is not enough.

5) If the number of soccer balls is x, then the number of basketballs is (60-x).

x*(1-2 3)*3=60-x+x*2 3x=45 (pcs). The number of footballs.

2）270÷

3) Solution: Set up a line for x hours.

4x-3x=6×2 x=12

4) Tons = 6600 kg is not enough.

1. How many kilometers has the car traveled from A to B, which is 5/7 of the whole journey, 60 kilometers more than half of the whole journey?

Application questions for the second semester of Grade 6. >

200 (km).

A: The car traveled 200 kilometers.

2. The production of a batch of parts for a certain car, the original plan is to produce 75 per day, and the task will be completed in 20 days, but the actual production must be 25 per day, and the task can be completed in a few days? "This problem needs to be solved with proportions! 》

Solution: The task can be completed in actual x days.

25+75)x=75×20

100x=1500

x=15A: Actual number = 15 days to complete the task.

I only use equations! Let A be B x, then.

Total distance = 45*2 (m.)

The distance traveled by A = 225 + 45 = 270 meters.

The distance traveled by B = 225-45 = 180 meters.

Car A and B drive from A to B at the same time, car A returns immediately after arriving at place B, and meets car B at a distance of 45 meters from place B, the speed ratio of car A and B is 3:2, how many kilometers does car A travel when they meet?