The Story of Entrepreneurship Math Problem 20

Answer: Solution: (1) If the price of each piece of clothing is x yuan, then 50%x+20=80%x-40

x=200, then the cost of each piece of clothing is: yuan).

Answer: The price of each piece of clothing is 200 yuan, and the cost of each piece of clothing is 120 yuan, that is, the small sheet can be discounted by up to 6%.

2) The floor plan of the box is:

The surface area is 2(2 1 + 2 3 + 1 3) = 2 (2 + 6 + 3) = 22 cm2;

3) The pattern of the design can be left or right:

Name the meaning of the design pattern, such as: candle - the bridge of friendship or candlelight to warm the world, the small candle to light the world, etc

The list price is 200, and the price is 120

Woo!

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I'm confused, wait until I'll ask the Ah Hua next door next door who graduated from junior high school again

Newton was a very humble man and never arrogant. Newton was once asked, "What is the secret of your success?" Newton said, "If I have a small achievement, there is no other secret but hard work." ”

1) Solution: Set the price to be X yuan.

x=200 A: The list price is 200 yuan.

2) 5% off.

The first question is 200 yuan per garment, and the cost of each piece is 120 yuan.

Go long with a 6% discount.

(1) According to the title, it gets.

r1=p(q1-20)=(-2x+80)[(x+30)-20],-x2+20x+800 (1 x 20, and x is an integer), r2=p(q2-20)=(-2x+80)(45-20), -50x+2000(21 30, and x is an integer);

2) When 1 x 20 and x is an integer, r1=-(x-10)2+900, when x=10, the maximum value of r1 is 900, when 21 x 30 and x is an integer, r2=-50x+2000, -50 0, r2 decreases with the increase of x, when x=21, the maximum value of r2 is 950,950 900, when x=21 is on the 21st day, the daily sales profit is the largest, and the maximum value is 950 yuan Comments: This question needs to be read repeatedly to understand the meaning of the question, According to the basic equivalence relationship in the marketing problem, the function relationship is established, the segmented functions are listed according to the time period, and then the maximum values of the two functions are obtained by combining the value range of the independent variables, and the conclusions are drawn

1) y1 = [(1 2x+30)-20](-2x+80)=-x squared + 20x + 800 (1 x 30, x is an integer).

y2 = -50x+2000 (21 x 30, and x is an integer).

The second question was not done.

The question is dry, not all! Some don't make sense at all.