Middle School Math Problem If 3a a 2 0, then 6a 2a ?

The key to this question is a

Process: Because 3a -a-2 = 0

So a=1 or a=-2 3

When a=1, -6a, -2a=-8

When a=-2 3, -6a -2a=-4 3

Because 3a -a-2=0 so.

3a+2)(a-1)=0 (factorization).

So 3a+2=0 or a-1=0

So a=1 or a=-2 3

Bring a=1, a=-2, 3 into -6a -2a, and when a=1, -6a -2a=-8

When a=-2 3, -6a -2a=-4 3

3a -a-2=0 crosses multiplied to give (3a -2)(a-1)=0 a=1 or a=-2 3

After substituting in turn, you can get:

When a=1.

6a²-2a= -8；

When a=-2 3.

6a²-2a= -4/3

Because 3a to the 2nd power -a-2=0;So 3a to the 2nd power -a = 2and because the 2nd power of -6a -2a is -2 times the 2nd power of 3a -a; So 2 (-2) = -4

3a²-a-2=0

As far as is known.

3a+2)（a-1)=0

So a=1 or a=-2 3

The equation sought is -6a -2a

It can be reduced to -(6a +2a) = -2a (3a + 1) because a = 1 or a = -2 3

Substituting yields 6a -2a = -8 or -4 3

Solving a quadratic equation (cross multiplication) finds the value of a in substitution.

3a²-a-2=0

a-1）*（3a+2）=0

Solution a=1 or a=-2 3

Substituting a finds when a=1 -6a -2a=-8 when a=-2 3 and -6a -2a=-4 3

Decomposition factor(3a+2)(a-1)=0

So 3a+2=0 or a-1=0

Original = -2a(3a+1).

So the original formula = -8 or.

Don't you know how to multiply the cross?

It can be split into (3a+2)(a-1)=0 and quickly calculate a=1 or -2 3 and then bring in the can. The answer is -8 or -4 3

Brother: You don't know how to do this, you can refer to the example problems in the book, I guess you haven't learned cross multiplication, so use factorization.

Answer: 7 2( Process: Deform the original equation to (a -4a+4) + (9b +6b+1) = 0 and then deform it to (a-2) +3b+1) =0 Solution:

a=2 b=-1 3 So 1 a-1 b=1 2+3=7 2 (The decimal is Hope to solve your problem, hope.

a²+a=-1

So a + a + 1 = 0

Obviously, a is not equal to 1

So a-1 is not equal to 0

Therefore, (a-1)(a +a+1)=0

i.e. a -1 = 0

So a = 1

Hence a +2a +2a +3

a³+2(a²+a)+3

1+2x(-1)+3

Solution: a -3a + 1 = 0 to get a -3a + a = 0, that is, a = 3a -a, a = 3a-1

3a³-8a²+a+3/(a²+1)

3（3a²-a）-8a²+a+3/(a²+1)=9a²-3a-8a²+a+3/(a²+1)=a²-2a+3/（a²+1）

3a-1-2a+3/（3a-1+1）

a-1+1/a

a+1 a=3 from a -3a+1=0 (divide the two sides by a, because a is not equal to 0, otherwise the two sides of the equation are not equal).

So the original formula = 2

After answering the questions, I wish you a happy time.

I have to admit that the current junior high school students are very strong.

a1=-1，a2=-2/3

Good luck with your studies