How to calculate HDD speed and average seek time, HDD average seek time and average waiting time?

Hello, it's a pleasure to help you. The rotation speed is 6000 rpm, and the second required for each revolution can be calculated, that is, 10ms, average access time = average seek time + average waiting time, average waiting time = half of the time and space rise and shouting interval per revolution, that is, 5ms, and the average access time can be calculated as Douye 5 + 5 = 10ms

The formula for calculating the average waiting time of a hard disk is as follows: average access time = average mu dust seek time + average waiting (latent) time.

1. Average access time = average seek time + average waiting (latent) time.

2. The waiting time of the hard disk, also known as latency, refers to the time when the head is already in the track to be accessed, waiting for the sector to be accessed to rotate below the head. The average waiting time is half the time it takes for the platter to spin one week.

3. The speed of the hard disk is 6000r min, so the time to get a revolution of the disk is 60s*1000 6000=10ms, so the average waiting time is: 10ms 2=5ms. So, the average access time = 5ms + 5ms = 10ms.

The average time is.

Part 1 Time to find track = average seek time = 6msPart 2 Time to find sector = time to turn the disk 2 (because I don't know where the curved sector is, count it as half a turn) = (60 seconds) (2 * 10,000 rpm) = 3ms

Part III Disk Controller Latency =

Part 4 Data Transfer Time = Number of Bytes Transferred Disk Transfer Speed = 4k 20m = 3rd power).

In summary, 6ms+3ms+.

The average time is.

Part 1: Track discovery time = average seek time = 6ms;

Part 2: Time to find the sector = time for the disk to rotate once 2 (because I don't know where the sector is, it is counted as half a turn) = (60 seconds) (2 * 10000 revolutions) = 3ms;

Part 3: Disk Controller Latency = ;

Part 4: Data Transfer Time = Number of Bytes Transferred Disk Transfer Speed = 4k 20m = power).

Hence the result: 6ms + 3ms + =.

The average time is.

Part 1: Track discovery time = average seek time = 6ms;

Part 2: Time to find the sector = time for the disk to rotate once 2 (because I don't know where the sector is, it is counted as half a turn) = (60 seconds) (2 * 10000 revolutions) = 3ms;

Part 3: Disk Controller Latency = ;

Part 4: Data Transfer Time = Number of Bytes Transferred Disk Transfer Speed = 4k 20m = power).

Hence the result: 6ms + 3ms + =.

The average time is.

Part 1: Track discovery time = average seek time = 6ms;

Part 2: Time to find the sector = time for the disk to rotate once 2 (because I don't know where the sector is, it is counted as half a turn) = (60 seconds) (2 * 10000 revolutions) = 3ms;

Part 3: Disk Controller Latency = ;

Part 4: Data Transfer Time = Number of Bytes Transferred Disk Transfer Speed = 4k 20m = power).

Hence the result: 6ms + 3ms + =.

The average time is.

Part 1 Time to find track = average seek time = 6msPart 2 Time to find sector = time to turn the disk 2 (because I don't know where the curved sector is, count it as half a turn) = (60 seconds) (2 * 10,000 rpm) = 3ms

Part III Disk Controller Latency =

Part 4 Data Transfer Time = Number of Bytes Transferred Disk Transfer Speed = 4k 20m = 3rd power).

In summary, 6ms+3ms+.

The average time is.

Part 1 Time to find track = average seek time = 6msPart 2 Time to find sector = time to turn the disk 2 (because I don't know where the curved sector is, count it as half a turn) = (60 seconds) (2 * 10,000 rpm) = 3ms

Part III Disk Controller Latency =

Part 4 Data Transfer Time = Number of Bytes Transferred Disk Transfer Speed = 4k 20m = 3rd power).

In summary, 6ms+3ms+.