Frequency conversion motor connection reducer selection problem 15

1. The speed regulation range of the inverter motor can be set arbitrarily, of course, the premise is whether the motor itself can withstand it.

2. The normal use range is 3 70Hz, if the motor is level 4, the rated speed is 1500rpm, and the corresponding frequency is 50Hz; 6-stage motor, 50Hz corresponding to the speed is 1000rpm; Class 8 motor, 50Hz corresponding to 750rpm.

3. The commonly used is a 4-stage motor. Adjust the speed of the inverter motor by adjusting the output frequency of the inverter.

4. If the output torque is not required, as long as the speed is reached, the reduction ratio is more than 75. If the frequency is too low, the speed will not be accurate. The recommended frequency is 5 or more.

5. If you want to output as much torque as possible, it is better to calculate the speed between 1450 and 1500, that is, when the output speed is 2rpm, the reduction ratio can be set between 725 and 750.

6. The inverter can adjust the speed and torque steplessly, and the reducer can adjust the speed and torque fixedly. The frequency converter adjusts the speed of the frequency conversion motor with frequency; Within the rated torque range, the output torque of the motor is changed by changing the current.

Your output speed only needs a constant speed, what's the use of using frequency conversion!!

If your output speed is adjusted within a certain range, then you must choose the low-speed inverter output frequency can not be lower than 30Hz, too low The output power of the motor is too small! When working at high speed, the output frequency of the inverter is 45Hz, which leaves some adjustment when the machine needs ultra-high speed.

When selecting, select according to the maximum speed of the reducer. At the fundamental frequency, the output torque can be guaranteed to be sufficient.

Under the fundamental frequency, it is constant torque, and at the fundamental frequency, it is constant power.

You yourself said it very clearly, can it be understood that I used the inverter to achieve the effect of adjusting the speed, and the reducer to achieve the effect of adjusting the torque.

It can be understood this way.

The reducer can be more stable and better to use the effect, which is a very important part of the selection of the motor, the selection of the motor must be matched with the reducer, otherwise it may cause damage problems, let's learn some common sense of matching.

The motor and the reducer must be matched with the power. You can't take the big with the small, and you can't bring the big with the small. The power of the motor we can pass the nameplate.

See, the parameters of the reducer (speed, torque, etc.) must be determined first, and then the appropriate motor must be matched according to the parameters of the reducer.

The two self-schemes, first calculated, according to the torque value of the output shaft and the speed of the output shaft, the output power is calculated.

This value is then multiplied, which is called the power margin. Another way is very simple, directly ask the staff who sell reducers: how big a motor should be equipped with their reducer. This is standardized, and the manufacturer's design engineers are more professional.

If the power of the reducer is not the same as the power of the motor, the motor resistance is at least 2 times the rated torque when overloaded, and the reducer is easily damaged. This is not done unless there are reliable protection measures in place or to ensure that an overload condition is never possible.

When the reducer is connected with the motor, it is directly set on the main shaft of the working machine, and when the reducer is running, the reaction torque acting on the box body is also installed on the reaction moment bracket or balanced by other methods, and it is directly matched, and the other end is connected with the fixed bracket.

The motor is matched with the reducer to make it run better and improve work efficiency at the same time.

When matching the motor to the reducer, a Zen pin must follow the correct method, or directly find the manufacturer or sales staff to match, so that it is easier to make a correct judgment.

Summary. Hello, glad to answer for you. The frequency conversion motor adjusts the frequency range of 25 50Hz.

The speed regulation range, in layman's terms, refers to the maximum allowable frequency range that can be guaranteed under the "rated operating state". Usually there is always an upper limit on the running speed of the motor, so this speed range emphasizes more on the low-frequency characteristics. For example, if a motor is designed according to 50Hz, if the controller can ensure that all the torque is full, then it can be said that the speed range is 1:

1000 up. However, the inverter with V F control is usually used, although it can run in, but the torque is very poor. So it doesn't reach 1:

Fellow, I really didn't understand, I can be more specific.

Hello, glad to answer for you. The frequency conversion motor adjusts the frequency range of 25 50Hz. The speed regulation range, commonly known as the stop, refers to the maximum allowable frequency under the "rated operating state".

Usually, there is always an upper limit on the speed of the motor, so the speed range of Paison emphasizes the low-frequency characteristics. For example, if a motor is designed according to 50Hz, if the controller can ensure that all the torque is full, then it can be said that the speed regulation range is 1:1000.

However, the inverter with V F control is usually used, although it can run in, but the torque is very poor. Therefore, it cannot reach such a wide speed adjustment range of 1:1000.

Your brother is good, I am very happy to serve you, and give you the following answers: the range of rapid acceleration and deceleration of the inverter motor depends on the rated output power of the inverter, in general, the greater the rated output power of the inverter, the greater the range of rapid acceleration and deceleration. Under normal circumstances, the rated output power of the inverter is, and the range of rapid acceleration and deceleration can reach Zheng Bu.

Hello, I am glad to serve you and give you the following answers: the range of rapid acceleration and deceleration of inverter motor is generally from 0 to the maximum speed, and the maximum speed can be determined according to the model and power of the motor. If there is a problem with the rapid acceleration and deceleration of the inverter motor, the following solutions can be taken:

1.Check the settings of the inverter to make sure that the settings of the inverter are correct so that the speed of the motor can be controlled correctly. 2.

Check the connection of the motor and make sure that the connection of the motor is correct so that the speed of the motor can be controlled correctly. 3.Check the current of the motor to make sure that the current of the motor is correct so that the speed of the motor can be controlled correctly.

4.Check the control system of the motor to make sure that the control system of the motor is correct, so that the dust skin is pointing at the brother Feng to control the speed of the motor. 5.

Check the settings of the control system of the motor and make sure that the settings of the control system of the motor are correct so that the speed of the motor can be controlled correctly. 6.Check the software of the control system of the motor and make sure that the software of the control system of the motor is correct so that the speed of the motor can be controlled correctly.

7.Check the hardware of the control system of the motor to make sure that the hardware of the control system of the motor is correct in order to properly control the speed of the motor. 8.

Check the circuit of the control system of the motor to make sure that the circuit of the control system of the motor is correct in order to control the speed of the motor correctly. Personal tip: When checking the range of rapid acceleration and deceleration of the inverter motor, it is necessary to carefully check the settings of the inverter, motor, control system, software, hardware and electrical circuit to ensure that the range of rapid acceleration and deceleration of the inverter motor is correct.

In order to calculate the suitable three-phase motor and gear unit, some parameter calculations need to be carried out first. Assuming that the movement of the load is carried out in a chain drive, the following approximate calculations can be made:

Calculate how many revolutions the load needs to move per second The load moves distance per second = Sprocket diameter = , radius r = Number of revolutions per second of load = Distance traveled by load per second Sprocket circumference =

Calculating the chain drive speed assumes a chain type of 10 a, and the chain contains 66 rollers per foot, with a distance of 3 8 inches, or millimeters, between each roller. The diameter of each roller is about millimeters, so the circumference of each roller is about millimeters. A 10a chain link long hail hall is millimeters silver, so the distance between each chain link is millimeters.

Therefore, the angle between each link is arccos( . Chain speed per second = number of revolutions per second of load Number of links required per revolution Angle between each link = 66 rpm

The choice of three-phase motor and gear unit was determined due to the total load of 70 kg, the weight of the chain 6 kg, and the total load of about 76 kg. According to the kinematic formula, f=ma (force equal to mass multiplied by acceleration source), the acceleration of the load and the required torque need to be considered. To simplify the calculation, here it is assumed that the acceleration of the load is that the effective radius is meters, i.e., the sprocket radius.

Torque = f r = 76kg According to the required speed, it is necessary to select a three-phase motor and reducer that meet the following two conditions:

In the case of stepper motors, the output torque range depends on the drive mode and controller, and needs to be selected and calculated on a case-by-case basis. It is recommended that you consult a professional motor and control engineer to better understand the selection and performance requirements of the stepper motor in this application scenario.

Output torque n·m

Output RPM

To sum up, for the above conditions, it is necessary to select a three-phase motor and reducer with an output torque of not less than and an output speed of not greater.

Based on the information you provide, we can calculate the required torque and output power, and then select the appropriate motor and gear unit based on these parameters. Here's how it works:

Calculate the load moment: load moment (torque) = load weight radius = 70 kg + 6 kg) m s m nm

Calculate the required output power: p = torque angular velocity = nm m s m) w

Now we know the torque and power output we need. Next, you'll need to choose a motor that can provide enough torque and output.

For a three-phase motor, you can choose a motor with a power rating slightly higher than W. For example, choose a motor with a power rating of 50 W or 100 W.

The selection of the reducer depends on your requirements for speed and torque. By choosing the right reduction ratio, you can convert the high-speed, low-torque output of the motor into a low-speed, high-torque output. In this example, you need to reduce the speed of the motor to m s, you can choose a gear unit with the corresponding reduction ratio.

For example, if you choose a 100 W motor with a speed of 3000 rpm, the reduction ratio should be: (3000 rpm * m) m s * 60 s min).

Regarding stepper motors, they can provide precise position control, but in some cases, their torque and output power may not be as good as that of three-phase motors. If you need high-precision position control and can find a stepper motor that can provide enough torque and output power, then you can consider using a stepper motor. When selecting a stepper motor, it is also necessary to pay attention to the rated torque and power rating to ensure that they can meet the load requirements.

Based on known conditions, it can be calculated that the total gravity experienced by the load is 70 kg * meters per square second = 686 N.

Since the load moves at a speed of meters per second and the length of each link is meters, the frequency of movement of the chain is meters per second meters per section = Hertz.

In order to calculate the size of the required motor and reducer, it is necessary to know the required retarding torque and rotational speed of the load. The torque can be calculated by the formula t = f * r, where f is the required force and r is the radius of the output shaft of the motor. In this example, assuming the radius of the motor output shaft is meters, the torque required for the load is 686 Nm * m = Nm.

The rotational speed can be obtained by multiplying the circumference of the sprocket by the frequency of movement of the chain, i.e., 2 r * Hertz = meters * Hertz = revolutions per second.

From this, it can be calculated that the required output power p = t * Nm * revolutions per second * 2 60 seconds per minute = kilowatts.

Considering the choice of motor and reducer, a three-phase asynchronous motor with a rated output power of 3 kW can be selected, and a reducer with a reduction shed speed ratio of 1:30 can be selected.

The determination of torque in the selection of frequency conversion motor is very important, mainly in the following 4 situations, see the attached figure.

The power rating of the motor is determined based on the maximum torque and the known rotational speed.

t=9550*p n power p=torque*rated speed Other parameters of 9550 motor, you can according to the rated speed and rated power.

JB T 7118-2004 YVF2 Series (IP54) Frequency Conversion Speed Regulation Special Three-phase Asynchronous Motor Technical Conditions (Frame No. 80 315) Query.