11 questions, high school chemistry, each option needs to be analyzed

Although it is 1mol, the total volume usually changes after being dissolved in 1 L of water, so the concentration is not 1 mol L;

b.It is not stated that the mass of this gas is unclear because the same volume of HCl, if the air pressure is different, then its density is different, so the same volume of HCl may be different. It is important to point out that HCl gas is in the standard state is the correct answer.

c.Same as adSince the volume of the solution is added to 250ml after it is dissolved in water, the volume of 250ml at this time is the volume of the solution, and the amount of NaOH is 1mol L.

Key points: The volume of the solution refers to the volume weighed after the solution is prepared, and the total volume of different substances is not equal to the sum of their respective volumes.

11a False, 1L of water is the volume of solvent, and the amount concentration of the substance is equal to the amount of the substance of the solute divided by the volume of the solution.

b False, it must be under standard conditions before it can be used.

C is wrong, there is a gap between the molecules, 1L+9L is not equal to 10L

d Yes, it is prepared into a 250ml solution, indicating that the volume is to see clearly, really a little annoyed Ya ,,, o(o

1. Chlorine reacts with water Cl2 + H2O = HCL + HClOA, due to the production of HCl, H+ will increase.

B. HCO3- reacts with H+HCO3- +H+ = CI2 + H2O. So HCO3- decreases.

C, 2 Fe2+ +Cl2 = 2 Fe3+ +2Cl-, reducing D, Ag+ +Cl- = AGCL also reducing A2 and C. Can exist: CO32-, SO42-, K+HCO3- +OH- = CO32- +H2OH4+ +OH- = NH3 + H2OSO32- can be oxidized to SO42- by the strong oxidant Na2O2

+ H2O --HCl + HClSelecta Hydrogen ion concentration is increased.

b Bicarbonate will react with H+ to form water and carbon dioxide, and reduce C HClo will oxidize ferrous ions to become iron ions.

d Silver ions will precipitate with Cl-.

2. 2na2o2 + 2h2o --4naoh + o2

Bicarbonate reacts with OH- to form carbonate.

Sulfite SO32- does not react.

Sulfate SO42- also does not react.

Potassium ions do not react.

The ammonium ion will combine with OH- to form NH3-H2O

So it's 3 kinds, choose C

1. First of all, Cl2+H2O===HCl+HCl+HCl, and then consider each option.

H+: A, due to the production of HCl, H+ will increase.

B. HCO3- reacts with H+HCO3- +H+ = CO2 + H2O. So HCO3- decreases.

C, 2 Fe2+ +Cl2 = 2 Fe3+ +2Cl-, which reduces D, Ag+ +Cl- = AgCl also reduces A2, sodium peroxide itself will react: 2Na2O2 + 2SO3 2Na2SO4 + O2

When sodium peroxide meets water, it produces NaOH and O2

where 2Na++OH-+HCO3- NA2CO3+H2ONh4++OH-=NH3+H2O

Therefore, the three CO32-, SO42-, and K+ that can coexist choose C

A is false, Na2SO4 ionization has nothing to do with whether it is energized or not.

B is wrong, K1 is closed to form an electrolytic cell, A is the anode, and the remaining H+ after OH- discharge, PH decreases, and does not change red.

C pair, close K2 to form a galvanic cell, A pole reacts O2+4H++4E-=2H2O, and consumes H+ to weaken acidity.

D is false, B pole has a large amount of OH-, and the H+ after the reaction will combine with OH- to form H2O

In addition to the factors affecting the concentration of the salt solution, the hydrolysis of NH4+ will reduce C(NH4+) by a small amount, which will also affect its concentration in the solution.

NO3- does not affect NH4+ hydrolysis; The ionization trend of HSO4- was larger, and the ionization of H+ inhibited the hydrolysis of NH4+, and less salt was required under the same C(NH4+) condition. HCO3- hydrolysis trend was larger, and the absorption of H+ promoted the hydrolysis of NH4+, and more salt was required under the same condition as C(NH4+).

1.The mechanism of action of both is because the melting point is high and has nothing to do with chemical reactions"An endothermic reaction occurs"Mistake.

2."Stone sulfur mixture"Mistake. The two do not form a stone sulfur mixture.

Fifth, and the concentration of HCL should be 10mol per liter. (High concentration).

Question 4 A cannot contain hs-,

b、hco3-

c、fe3+、

d、br-

A becomes larger and B remains the same. According to the equation, it can be seen that the ion concentration before and after is basically unchanged.

c becomes larger. The degree of ionization of weak acids is small, and the ions increase after the formation of salts.

d becomes larger, and after the formation of sodium chloride, some ammonia remains in the water.

Opt B, because only option B's dilute hydrochloric acid solution reacts with sodium hydroxide and the electrolyte concentration in the solution barely changes, so the conductivity does not change much.

The answer is b

Reason: For A, C, D, after adding sodium hydroxide, the electrolyte changes from weak to strong, which greatly increases the conductivity, and for b, it is a strong electrolyte, and the concentration of conductive ions does not change much, so there is no major change in conductivity.

d.Ammonium chloride is a salt, and there are ammonium and chloride ions in the solution that conduct electricity, and when NaOH is added, there are Na, Cl in the solution that conducts electricity.

A, NaOH and HCl are completely ionized, and HClO is partially ionized.

Number of ions completely ionized by NaOH: (Na+) = (OH-) = N

Number of ions completely ionized by HCl: (H+)=(Cl-)=M

Number of ions partially ionized by HCOl: (H+) = (ClO-) = A

Number of ions consumed in neutralization reaction: (h+) = (oh-) = b

na+)+h+)=(oh-)+cl-)+clo-)=n+m+a-b relational error.

B. NaHCO3 solution is alkaline, which confirms that the degree of hydrolysis of HCO3- is greater than the degree of ionization, so the correct relationship is (Na+)>HCO3-)>H2CO3)>(CO32-).

c. The molar concentration of ammonia with pH value = 11 is greater than the molar concentration of hydrochloric acid with pH value = 3, so the ammonia is excessive after the mixture of the two by the same volume, and the solution is alkaline. （nh4+）>cl-）。oh-)>h+) relational error.

d. The equivalent of L CH3COONA and L CH3COOH are mixed in equal volumes. CH3COONA is completely ionized into CH3COO- and NA+, CH3COOH is partially ionized to CH3COO- and H+, and CH3COO- is partially hydrolyzed into CH3COOH and OH-. So.

2（na+）=（ch3cooh）+（ch3coo-）；

na+）+h+）=（ch3coo-）+oh-）；

So the relation is correct.

A: According to the conservation of charge, the correct one is: [Na+]+H+]=[Cl-]+ClO-]+Oh-]

B: The degree of hydrolysis of NaHCO3 is greater than the degree of ionization, the correct is: [Na+]>HCO3-]>H2CO3]>[CO32-].

C: Mixed in equal volume, the solution is alkaline, the correct is: [NH4+]>Cl-}>OH-]>H+].

D: Correct. Conservation of material: 2[Na+]=[CH3COOH]+[CH3COO-]; Conservation of charge: [Na+]+H+]=[CH3COO-]+OH-];

It can be obtained by removing the Na+ ion concentration.

It's just a change in physical properties, not a change in chemical properties.

So. a chemical change in the nature of a water molecule is wrong.

b Shortening of the length of oxygen-hydrogen bonds in water molecules False (chemical properties) c Decrease of intermolecular forces in water No, the intermolecular forces of small molecular clusters of water increase compared to large molecular clusters, after all, the molecular clusters are small, the density is large, the intermolecular distance is small, and the force is large.

d The intermolecular structure and physical properties of water are correct.

I don't know how to ask.