Ask two high school chemistry questions and two high school chemistry questions

The following questions are answered in the context of high school only.

1. Yes, because for NaHSO4, cation: Na+, H+, anion: sulfate, so the ratio is 1:2, and Na2O2, then cation: Na+, anion: peroxide example, so it is also 1:2

Note: Bisulfate does not exist and is composed of two ions, H+ ion and sulfate ion in the crystal, rather than one ion.

2, chemical formula: xy2, explanation: for this unit cell x quantity:

1 8*4=1 2, and the number of y: 1, so it is x1 2y1, and the approximate is xy2; Or to think of it this way, there are 8 y's around each x, and 4 x's around each y, so it should be xy2

2) 12 of them, just draw a picture.

3) 109 degrees 28 minutes, the regular tetrahedral problem in solid geometry, you know how to calculate it.

4) m= *2*na*(a root number2)*(a root number2)*(a root number2), that is, its cubic figure, solve this equation yourself, a is what you find.

If you don't understand, you have time to read the chapter on crystals in inorganic chemistry at university, or structural chemistry (difficult, not recommended).

1 No, sodium bisulfate contains a sulfate and a bisulfate.

Sodium peroxide contains one sodium ion and one peroxide ion.

2 I don't see the figure.

For a Na cation and an HSO4 anion for sodium peroxide is not explained.

1) 8 pcs, 4 pcs, x2y2) 6 pcs.

I can't explain it to you clearly, because I have to draw a picture for you.

1:NaHSO4 is 1:1 Because bisulfate is a functional group, both an anion and sodium is a cation, so the ratio of anions and cations is 1:1

The number of anions and anions of Na2O2 is not 1:2, because peroxide is a functional group with two sodium ions, so the ratio of anions and cations is 1:2

2::(1)4-4 NaO.

3）arccos1/3

4) It's been too long on vacation and I forgot- I'm sorry I hope.

1 False, sodium bisulfate is not, it is bisulfate ion, not you take it for granted, 1 H+ and 1 SO42-

2 No picture.

When a divalent metal reacts with nitric acid, the ratio of the amount of substances consumed by the metal to nitric acid is 2:5, assuming that the metal has 2mol, it loses 4mol of electrons to form 2mol metal cation. 2mol metal cation needs 4mol of NO3- to form nitrate, so the reduced Hno3 may be 1mol, and this 1mol of Hno3 gives 4mol of electrons, and the valency of N element decreases by 4 valence to +1 valence, so the product is N2O.

But there is another case, you have an average valency of N from NH4NO3 to +1 valence, and you should also think that the remaining 1mol of HNO3 only gets 4mol electrons to be reduced, and the valency is reduced by 8 valence, generating NH4+ ions, and the remaining NH4NO3 can also meet the condition. So the answer is 2, a and d.

CA + 2HNO3 = CA(NO3)2 + H2O, then CA + 2HNO3 + 3H2O = CA(NO3)2·4H2O, so 2HNO3 3H2O

1. Let this metal be m, when m:hno3 is 2:5, the equation 4m+10hno3=4m(no3)2+n2o+5h2o, so the product is a n2o

2. Cao + 2 Hno3 = Ca(NO3)2 + H2O One water is formed in the reaction, and at the same time, 3 water molecules need to be provided in the solution (because the product is tetrahydrated calcium nitrate).

So the percentage concentration of nitric acid = 2*63 (2*63+3*18)=70%.

ai2（so4）3=2ai3+ +3so42-x c2x=c x=c/2

x for. Concentration of AI2 (e.g., bridge SO4)3.

By Wu Oak Zen c = (1000pa) m =

p is the dust degree of the dense cavity and m is the molar mass.

Choose a because it is an exothermic reaction, and the absolute value of the heat of reaction is the smallest, that is, the heat released is the smallest.

That is, the energy of the reactants should be low, and the energy of the products should be high.

The energy of a substance of the same kind, the same amount and the same pressure is.

Gases, liquids, solids.

Combining the 4 options, the answer is A

ps problem.

First, look at whether the reaction is endothermic or exothermic.

Common endothermic reactions: hydrolysis reaction, ionization reaction, decomposition reaction; Common exothermic reactions: neutralization reaction, combustion reaction, chemical reaction).

Like the question above.

Available. The energy of a substance of the same kind, the same amount and the same pressure is.

Gases, liquids, solids.

to compare. Pay attention: the coefficient before the substance.

The two reactive reactants and products are the same and have the same state.

The coefficient of heat absorption increases.

h enlarged. The exothermic coefficient increases.

h decreased. The second problem is Gaisce's Law.

You should be able to understand it that way.

h1=h2+1/2

h31/2△h4

Equation for Route 2.

Become. C(S) + H2O(G) = Co (G) + H2 (G) H22 Co (G) + O2 (G) = 2 Co2 (G) H32H2 (G) + O2 (G) = 2H2O(G) H4 Add the above to get the first equation.

So. is the mathematical relationship above.

1.In one part of solution: N(Mg2+)=, N(SO42-)=Bmol, N(K+)=(2B-1)mol

The concentration of potassium ions in the original mixed solution is: c(k+)=2(2b-1) mol l

The mL Fe3(SO4)2 solution contains 96 mol of SO42-:A

Containing Fe3+:3A (96 2)=A 64mol Take v 4 ml solution containing Fe3+:A 256 mol

Dilute to 4 V ml C(Fe3+) = (A256) (4V 1000) = 125A 128 V moll

(1) It can be shown that the neutral atom is larger than the surrounding atom in the scale model of the methane molecule, but the central atom is smaller than the surrounding atom in carbon tetrachloride. cl>c>h

2) Yes, (12) b can be converted, if the CO32- concentration is large, it can produce BaCO3 precipitate due to the same.

Ksp(BaSO4) Ksp(BaCO3) = As long as C(CO32-) is 24 times larger than C(SO42-), it can be converted to increase the CO32- concentration, and since it is a saturated BaCO3 solution, the precipitate mass increases, and C(Ba2+) decreases. The solubility product is a fixed value, of course, unchanged.

1. Scale model, the atom has a size, the carbon atom is smaller than the chlorine atom 2, I think it is right, remove the hydrogen hydroxyl hydrogen, the hydrogen on the carbon connected to the hydroxyl group 12, add a small amount of Na2CO3 solid to the saturated BaCO3 solution, C(Ba2+) does not change, because the barium carbonate is no longer soluble.

The solubility product of BaCO3 does not change, and the temperature does not change.

The solubility product is the product of the concentrations of the two substances, and d is therefore true, and d and a are expressing the same meaning.

1.Hydrogen atom and chlorine atom are not equal in size2Right.

1 question: 2kclo3=2kcl+3o2

2h2o2→2h2o+o2

2kmNO4 (potassium permanganate) == K2mNO4 (potassium manganate) + mnO2 (manganese dioxide) + O2 (oxygen).

Multiply the last two reactions by 3 so that the O2 coefficient is the same.

Analysis: (!) The equation transfer electrons is 6 (2) The equation is that the ox element itself is redox from -1 to 0, from -1 to -2 so the electron is 3, (3) the manganese element is reduced, only the oxygen element is increased, and the electrons transferred from the oxygen analysis are also 6 so it is 6:

The 22 questions are considered from the reaction essence ion equation.

3cu + 2no3- +8h+ =3cu2+ +4h2o +2no3 2 8 2x

According to the measurement coefficient, it is judged that the calculation of copper produces NO, (nitrate, excess hydrogen ions) v=

1.The amount of substances used to produce oxygen is the same, and the valence of oxygen in potassium permanganate and potassium chlorate is negative 2 valence, and hydrogen peroxide is negative 1 valence, and after the reaction, they are all parts, and the ratio of the three can be obtained from the conservation of electrons in redox is 2:2:1

2.It's kind of weird, but are you sure you get the title right? It may be that I can't answer the question yet.