The following system of equations is solved using the substitution elimination method

Hello! 1） x＋8y＝56 ❶

x＝24 ❷

Put substitution into , get:

24+8y=56

8y=32 gives y=4

2） x/2 -y/3=4 ❶

y=9/2 ❷

Put substitution into , get:

x/2-3/2=4

x/2=11/2

Solution x=11

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x+8y=56，x=24.Directly use the substitution elimination method. Substituting x=24 into x+8y=56 gives 24+8y=56The solution is y=4

x 2-y 3=4 multiply 6 to get 3x-2y=24, and substituting y=9 2 gives 3x-9=24

x=11 y=

x=24 is substituted into x+8y=56, and 24+8y=56 8y=56-24 8y=32, and the solution is y=4

y=9 2 is substituted into x 2-y 3=4, and x 2-9 2 3=4 x 2-3 2=4 x-3=8 is solved, and x=11 is obtained

（1）x=y+10 （2） x+2y=6（2） 2x-y=0（2） 9m-10n+23=0（2）

Solution Substituting (2) into (1), the solution is obtained by 2, the solution is obtained by 2, and the solution is obtained by (1).

y+10)+y=300 x=1+3y(3) y=2x(3) m=four-thirds n+

y+10+y=300 Substitute (3) into 1 to get (3) Substitute (1) to get seven-thirds 3

2y=300-10 (1+3y)+2y=6 3x-4x=10 Substitute 3 into 2.

y=145 5y=5 -x=10 n=（

Substituting y=145 into (2) gives y=1 x=-10 in the same format as the previous three questions

x=155 Replace y=1 with 1 Bring x=-10 into (3) Count it yourself

So {x=155,y=145 x=4 y=-20 elementary equation you should.

So {x=4,y=1 so {x=-10,y=-20 should be learned.

(1) Substitute y=2x-3 into 3x+2y=8 to get 3x+2(2x-3)=8 3x+4x-6=8 7x=14 x=2

Substituting x=2 into y=2x-3 gives y=2*2-3 y=1, so the solution of this system of equations is x=2

y=1(2) from 4m-n =-27 to n=27+4m, and n=27+4m to 2m+3n=11 to get 2m+3(27+4m)=11, 2m+81+12m=11, 14m=-70 m=-5

Substituting m=-5 into n=27+4m gives n=27+4*(-5) n=27-20 n=7

So, this equation has to be solved as m=-5n=7

y=2x-3 ①

3x+2y=8 ②

Solution: Bring in De:

3x+2(2x-3)=8

7x-6=8

x=2 brings x=2 into get:

y=2*2-3=1

So the system of equations is solved as: x=2y=1

1) y=2x-5 Substituting Eq. 2 obtains: 3x+2(2x-5)=-3 Solution: x=1 Substituting Eq. 1 obtains:

y=-2 (2) x=2y+3 Substituting Eq. 2 obtains: 3(2y+3)+y=2 Solution: y=-1 Substituting Eq. 1 obtains:

x=13) x=3y+7 Substituting Eq. 2 obtains: 4(3y+7)-9y=22 Solution: y=-2 Substituting Eq. 1 obtains: x=1

4) y=(5x-3) 2 Substituting Eq. 2 obtains: 10x-3(5x-3) 2=4 Solution: x=-1 5 Substituting Eq. 1 obtains: y=-2

1) y=2x-5 3x+2(2x-5)=3 x=8 72) x=3+2y 3(3+2y)+y=2 y=-13) x=7+3y 4(7+3y)-9y=22 y=-24) x=(3+2y) 5 10(3+2y) 5-3y=4 y=-2 just help you calculate one unknown, and the other one will come out with it. If the calculation is incorrect, please correct it.

1) x-3y=2 y=x Substituting y=x into x-3y=2 gives x-3x=2 and the solution gives x=8 =y= -1 (2)1 x+y=5 2 2x+y=8 from 1 to y=5-x Substituting y=5-x into 2x+y=8 gives x +5=8 and the solution gets x=3 y=2

3) 1 m-(n 2)=2 2 2m+3n=12 from 1 to n=2m-4 substituting n=2m-4 into 2m+3n=12 to get 8m-4=12 solution m=3 n=2

Braces: x+8y=56 and x=248y=56-24=32, y=4 braces: x/2-y=4 and y=9/2 x 2-3 2=4, x=11 Continent Divine Sleepiness:

1/2x-4y=30 and y-2x=15 Note: 1x out of 2 is 1/2 multiplied by xy=2x+15 to get x 2-4(15+2x)=30, x = -12 curly braces:

5x+6y=16 and 2x-3y=12x-3y=1, you have to get the blind macro 4x-6y=2, 6y=4x-2 to 5x+6y=16 to read early: 5x+4x-2=16, 9x=18, x=2

1 question, directly substitute the vested y=4, 2 questions are the same as the lack of y=33 questions, y=15+2x substitution, x=-12, y=-94 questions talk about y=2x-1 Xiaoxun 3 substitution, x=2, y=1 is like this.