A chemistry question, how to do the eighth question Ask for a detailed answer

The first question, m = n * m, from the conditions we know that n is the same, the mass ratio is the molar mass ratio of the two 17:34 = 1:2

The second question, m=n*m, the mass is the same, the molar mass ratio of nh3 and h2s is 17:34=1:2, then the ratio of the amount of the two substances is 2:1, that is, the volume ratio is 2:1 (the same conditions).

Thirdly, if the ratio of the quantities of matter between the two is 2:1, then the ratio of the number of hydrogen atoms is 2*3 (1*2)=3:1

The amount of the substance of ammonia and hydrogen sulfide in equal volume is equal with a mass ratio of 17::34 = 1:2

From the first space, it can be seen that the amount of ammonia at the same mass is twice that of hydrogen sulfide, so the volume is also 2:1

The ratio of hydrogen atoms is 3x2:2x1=3:1

The last one is empty, you're right, I won't write it, it's really hard to watch.

Feel free to ask. I hope mine can help you. Hope.

According to PV=NRT

The amount of the same substance in the first void. So the mass ratio is equal to the relative molecular mass ratio of 17 to 34 The second question is equal to the mass, so the quantity ratio of matter is 2 to 1, or that formula, so it is 2 to 1, and the third question is because the mass ratio of matter is 2 to 1, so it is 6 to 2, and the fourth empty is not said if you are right.

If you don't understand, please ask, be satisfied.

1.With the same temperature, same pressure, and same volume, the quantity of matter is the same, so the ratio of mass is equal to the ratio of molar mass, that is, 17:34=1:2

2.And if the mass is the same, the ratio of the quantity of matter is reversed, which is 2:1, because the temperature and pressure are the same, so the ratio of the quantity of matter is equal to the ratio of volume is 2:1

3.From the previous emptiness, the ratio of the quantity of matter is 2:1, NH3, SH2, and the ratio of the number of hydrogen atoms is 2*3:1*2=3:1

4.nh3, sh2, the number of hydrogen atoms is the same, so the ratio of the quantity of matter is 2:3, because the temperature and pressure are the same, so the ratio of the quantity of matter is equal to the ratio of volume is 2:3

I hope so

At the same temperature and pressure, it means that the molar mass is the same, and the mass ratio is equal to the mass ratio of the molecule.

In the same way, the volume ratio is equal to the reciprocal of the mass ratio of the molecule...

k2cr2o7+14hcl---2kcl+2crcl3+3cl2+7h2o

A Cl2 is the oxidation product of this reaction – right.

b The ratio of the amount of the oxidant to the reducing agent is 1:14 - false, is 1:6c When the electrons are transferred, the amount of the substance of the oxidized reducing agent is the opposite d From this reaction we can know the reducing hcl crcl3 - right.

9.(1) Increase first and then decrease.

2) 2S2- +SO32- +6H+ == 3S + 3H2O(3) Solid grinding Stirring Heating.

Ethylmethyl sulfite is oxidized to sulfate.

4）4na2so3 == na2s + 3na2so4

First of all, we need to clarify that the order of the reaction is neutralization reaction (hydrogen ions and hydroxides), metathesis reactions (hydrogen ions and carbonates), and hydrolysis reactions (hydrogen ions and metaaluminate).

1. Exclude b and d, because hydrogen ions and hydroxide are the first to react to produce water, not precipitation, so there is no precipitation at the beginning.

2. Metathesis reaction produces CO2 and H2O

3. Hydrolysis reaction: H+ +AlO2- +H2O ==Al(OH)3, the curve rises.

4. Finally, after the hydrolysis reaction is complete, the dropwise addition of acid will react with Al(OH)3 to form aluminum chloride and water, and the curve will decrease.

5. C can be excluded from the order of metalysis and hydrolysis, and option C is hydrolysis first and then metathesis before there will be precipitation residence time.

So choose A.

The choice of D acetic acid is a weak acid, so A is wrong.

Acetic acid is soluble in water and ethanol, so B is wrong.

Acetic acid is a monobasic acid, so c is wrong.

A is C6H5-CH(-CoOH)-CH2OH

The hydroxyl group can be the oxide aldehyde group, and the hydroxyl group will collapse at the end.

The polycondensation product of a is -[-o=)c-ch(c6h5)-ch2-o-]n-

Carbon-carbon double bonds, carbon-carbon triple bonds and aldehyde groups can both fade bromine water and potassium permanganate, which is not in line with the topic, high school learning can make potassium permanganate fade and not fade bromine water is toluene and its derivatives, potassium permanganate can oxidize the methyl group in toluene to carboxyl group, C7H8 can only be toluene, so after the first hydrogen reduction, toluene will become methylcyclohexane, at this time there are only four chlorinated substances, which are chlorine on methyl group, chlorine in methyl critical, meta and para, answer a

It contains a phenolic hydroxyl group, which can undergo a chromogenic reaction with FeCl3.

c.Contains phenolic hydroxyl groups and can undergo esterification reactions.

A phenolic hydroxyl group is 1mol, and 1 ester group will be hydrolyzed to form 1mol phenolic hydroxyl group and 1mol carboxyl group, so it is 3mol.