Primary 6 Mathematics Olympiad. Please point with your high fingers! Thank you

Updated on educate 2024-02-09
4 answers
  1. Anonymous users2024-02-06

    1. Dad's 4 km time is 8 minutes less than Xiao Ming's 4 km time;

    Dad's 8+4 km takes the same time as Xiao Ming's 8-4 minutes.

    Therefore, the time taken by Dad is Xiao Ming's (8+4) (8-4)=1 3 Xiao Ming's time for 4 kilometers: 8 (1-1 3)=12 (minutes) Xiao Ming's time for 8 kilometers: 12 2=24 (minutes) At this time, it is 8:32.

    2. Add 2 machines at the specified time to complete: 1 (7 8) = 8 7 total machines: 2 (8 7-1) = 14 (sets).

    One machine is required to complete this project: 2 3 (1 12-1 14) = 56 (hours).

  2. Anonymous users2024-02-05

    Solution: Dad's speed is several times that of Xiao Ming: (4+8) 4=3 (times) The time required for Dad to walk 4 kilometers: 8 (3-1)=4 (minutes) Dad's speed: 4 4=1 (kilometers min).

    A: It was 8:32 a.m

    Number of original units: 2 (8 7-1) = 14 units.

    14-2=12 units.

    The present is the original time: 14 12 = 7 6

    It takes 14 4 = 56 hours to complete the project by one machine.

  3. Anonymous users2024-02-04

    The answer to the first question is 8:40

    Let Xiao Ming walk x kilometers every minute, and Dad will walk y kilometers every minute. Then 4 x - 4 y = 8 8 x - 12 y = 8, and the solution is x= y=

    8 x = 32 minutes 8:08 after 32 minutes is equal to 8:40 Question 2: If there are expected x machines and the time used is y, then x*y=(x+2)*(7y 8)=(x-2)*(2 3 +y).

    x=14 y=4 14*4=56, the answer is 56 hours.

  4. Anonymous users2024-02-03

    There will be 20 people who subscribe to C magazines.

    The number of people who order all three copies is x, x = 64 - those who order only one book - those who order only two copies .........1) And because: 10 + x + people who only subscribe to A magazine = 28

    12 + x + people who only subscribe to b magazine = 41

    12 + x + people who only subscribe to C magazine = 20

    So: 3x+ (only A magazine + B only + C only) = 55, i.e.: 3x+ people who only subscribe to one magazine = 55 .........2) And because: x+ people who only subscribe to two kinds of magazines AB = 10

    x + people who subscribe to only two types of BC magazines = 12

    X + people who subscribe to only AC two magazines = 12

    So 3x+ (only two magazines for ab + two magazines for bc + two magazines for ac) = 34

    i.e.: 3x + people who subscribe to only two magazines = 34 .........3) Substituting Eq. (2) and (3) into Eq. (1) obtains.

    x=64-(55-3x)-(34-3x)

    Get x = 5 Question 2 75 + 60 = 135

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