Solve equations in the sixth grade of primary school, and solve equations in the sixth grade

1. The gymnastics team queues up, if you add a line, each row is 40 people, and the reduced line is 50 people per line, ask how many lines are there?

2. There is a fish, the weight of the fish tail is 4kg, the weight of the fish head = the weight of the fish tail + half of the weight of the fish body, the weight of the fish body.

Fish tail weight + fish head weight, ask how much does the fish head weigh?

A soccer ball ** = 5 volleyballs **, buy 3 volleyballs and 2 soccer balls for a total of 156 yuan, ask how much is each?

4. Dad's age is times that of Xiao Ming, mother's age is twice that of Xiao Ming, Dad is 9 years older than Mom, how old is Xiao Ming?

A prime number and an unknown number together are equations.

(x-3):6=2：3===》x-3=4===>x=7

Five and one-fifth x two-fifths x four-fifteenths.

26/5x=2/5x+4/15===>24/5x=4/15====>x=4/15*5/24=1/18

The first question is 2x6=3 (x-3) (the preceding cross is a multiplier sign) from the original formula, that is, 12=3x-9, x=7;

The second question is to combine the same kind of terms, i.e., 26x 5-2x 5=4 15, 24x 5=4 15, x=1 18

(x-3): 3/4 = 5/6.

Then x-one-third = five-sixths three-quarters.

So x - one-third = 5/8

So x = 5/8 + 1/3

So x = 23/24

1.(6x-200):(5x-125)=8:7 Unary Linear Equation Continue to calculate as 42x-1400=40x-1000 x=200 So there are two schools, A has 1200 people, and B has 1000 people.

2.The salt mass is x then (x+10): 15x=1:9 and continues to calculate as 9x+90=15xx=15, then the salt water mass is now 16x+10=250g

3.(5x-10): 6x=2:3 Continue to calculate 15x-30=12x x=10 So it turns out that there are 5x=50 science and technology books.

4.x volleyball, 3x football. x 4 is the number of times the volleyball is borrowed, and the soccer ball is borrowed x 4 3. So 3x=x 4 3+63 x=28 So it turns out that there are 28 in volleyball and 84 in football.

Continue to calculate x=40

1. Let the number of students in school A be x, and the number of students in school B will be, (x-200) (y-125)=8 7, and the solution is: x=240, y=200

2. Let the salt be x, the water is, (x+10) y=1 9, and the solution is: x=15, y=225

3. Let the number of science and technology books be x, the number of literature and art books is, (x-10) y=2 3, and the solution is: x=50, y=60, and 50 science and technology books.

4. There are x footballs and y volleyballs. x=3y,(x-63) 3=y 4, the solution is: x=84, y=28

5. There are x books on the upper bookshelf and Y books on the lower shelf. x y=3, x-40=y+40, j solution: x=120, y=40, there are 120 books in the upper layer, and 40 books in the lower layer.

1. There are x,y people in each school, and x:y=6:5....x-200):(y-125)=8:7...Solution: x=1200, y=1000

2. The salt in the current brine is x, the water is y, there is (x-10) y=1 15, x y=1 9 solution: x=25, y=225

The following methods are the same, set the binary, solve two linear equations, and the result can be obtained...

1. A x, B y

x：y=6:5

x-200）：（y-125）=8：7

2. Salt x, water y

x:y=1:15

x+10）：y=1:9

3. Branch X, Wen Y

x：y=5:6

x-10）：y=2:3

4. Foot x, row y

x=3yx-63) divided by 3=y divided by 4

5. Up x, down y

x=3yx-40=y=40

Steps to solve the equation.

1) If there are parentheses, remove them first.

2) Move terms: move the terms with unknowns to the left, and the constant terms to the other right (3) Merge similar terms: deform the equation into a monomial.

4) Divide the coefficients of the unknowns on both sides of the equation at the same time to obtain the value of the unknowns, for example: 3+x=18

x =18-3

x = 15 x = 15 is the solution of the equation.

4x+2（79-x）=192

4x+158-2x=192

4x-2x+158=192

2x+158=192

2x=192-158

2x=34x=17

x=17 is the solution of the equation.