The problem of fetching water in the dormitory is annoying!!

School is a place of learning, not only the knowledge of books, but also how to get along with others is also a very important part. You can be glad that you are already accumulating experience with this kind of troublesome problem, hehe.

Have you considered this issue thoroughly? The main contradiction is:"Lazy"with"Unrighteousness".What does your roommate's behavior mean?

Is it really good to make a small bargain from others? If you have the opportunity, hold a meeting, ** it, write down what you say, and make it a dormitory system. If you go it alone, maybe they think you are doing something, it's better to discuss it together, and don't you also talk about dialogue in the international community?

If there is no possibility of dialogue, you can fetch enough water for them every day, see their reactions, and discuss them at the opportunity. After 1 week, there is really no chance to dialogue, and then implement your strategy, after all, the campus is a small society, and it is always better to have more popularity. Remember, no matter how painful it is, you're accumulating experience, hehe.

If that's the case, you can have a small meeting in your dormitory, and if you go on like this, it will really hurt your friendship, and I suggest that you can bring your own water bottle, how much water you need, and deliberately fight by yourself, and do it yourself, and have enough food and clothing, and that's how our dormitory took at that time, and there has never been a quarrel over the issue of water, and I think everyone in your dormitory will approve of it.

Our dormitory is a person with a kettle, their own water, if you really need water, but your own pot has no water, and it doesn't matter if you borrow some more from others, so that there will be no contradiction when you use your own water to draw water

Actually, I think the reason why this is happening in your dormitory is that there are still some minor problems between you, otherwise this would not have happened. Once this problem is solved, the problem of estrangement between you will be solved, and similar problems will not occur in the future. In our dormitory, sometimes if two people have to fetch water, then one person goes to fetch water and the other goes to fetch food...Hope it helps.

It's also a good idea to buy your own pot.

It's a good way After you buy it, use it yourself They don't realize that they are wrong We also have that situation in our dormitory Hehe, in fact, let it go, isn't it just to carry water? Men should be more broad, just pay attention to yourself.

It is recommended for individuals to use personal.

These things are delicate in the dormitory.

I still take care of my own things in my personal life.

Spread it out, I think everyone will agree.

It's not stingy either.

Everyone has a friend who is willing to give, but he doesn't have to be in your dorm room.

You don't necessarily want to share it with him in your dorm room.

One by one, I haven't seen water! Whoever likes to drink frustrates the fire, if you don't thirst, you die, a lazy worm! Bring your own kettle.

Why don't you buy your own bottles?

Is one bottle of water enough for 2 people a day?

It's not enough for me to use 2 bottles alone, I hit my own.

If you don't have enough, you can borrow and return it, and our dormitory will be very good.

That's right, save yourself the hassle, and have fun!

Stingy! Thou shalt return the way of others.

It's not that you're alone.

Okay, support, people should be independent, so that the relationship between classmates will be ruined, but pay attention to keep your own things, explain to your classmates that it is yours, and save it and use you later!

Study hard

That's right, because that's what I do

If it is a thermos for eight people.

Then adopt the duty system.

Arrange the duty schedule.

One person fetches water for one day, and the next day he replaces.

In order to make the sum of their waiting time the least, they should be picked up first by the person who has the least time to receive water, that is, in the order of C, B, and A, this slippery round sample C took 1 minute, B took 1 + 3 = 4 minutes, A used a beam to make Tong 1 + 3 + 8 = 12 minutes, a total of 17 minutes with a rubber tank.

Let's assume that everyone's time cost is the same, then the calculation minimizes the total waiting time.

Arrange the container capacity of n people from small to large to C1T0. Certification.

There is already survival of the fittest, you have to be even more cruel.

I think this problem is also very strange, you can't call the library function sort() directly, but you can write a quick sort function from scratch:

void quicksort(int low,int high)}if(lowi)quicksort(i,high);

In fact, the ideas are very simple, greedy algorithms, and each time you choose the smallest r to fetch water.

for(i=1;i<=n;i++)

cin>>a[i];

This kind of similar assignment statement in the program is wrong, what about the assignment of a[0]???

Irrationality. The water supply time is short and the number of people is large. It's crowded. Extend the water supply time, increase the capacity, and expand the space.

This problem has to be learned and practiced in mathematics.

N people queue up to get water from R taps}

varn,r,i,j,k,p,q:integer;

t:array[1..200] of integer;

tt:array[0..50,0..100] of integer;

s,sum:longint;

f:text;

beginassign(f,'Queue up to fetch water. in');

reset(f);

readln(f,n,r);

for i:=1 to n do read(f,t[i]);

close(f);

for i:=1 to n-1 do for j:=i+1 to n do

if t[i]>t[j] then begin k:=t[i];t[i]:=t[j];t[j]:=k; end;

for p:=0 to 50 do for q:=0 to 100 do tt[p,q]:=0;

The following turns a one-dimensional array into a two-dimensional array}

for i:=1 to n do begin

p:=(i-1) mod r;

q:=(i-1) div r;

tt[p,q]:=t[i];

end;The following faucet corresponds to a queue, a total of r queues, and the time taken by each person in the queue is calculated}

for p:=0 to r-1 do for q:=1 to (n-1) div r do

if tt[p,q]<>0 then tt[p,q]:=tt[p,q]+tt[p,q-1];

The total time spent for each queue and its sum are calculated below

sum:=0;

for p:=0 to r-1 do begin

s:=0;for q:=0 to (n-1) div r do

if tt[p,q]<>0 then s:=s+tt[p,q];

sum:=sum+s;

end;writeln(sum);

end.

Thigh force The thighs drive the calves The legs are close together The feet are straight Try not to bend the knee joint The frequency of the leg is high The amplitude is small The body is flat Control the leg splash is not too big.