Do you have any math problems? Problems with math?

is f(2-x)+f(x-2)=2, because the condition given in the question is f(x)+f(-x)=2, and if 2-x is regarded as x by commutation, then -x=x-2. Therefore, the first way to write it is correct.

This is the problem of abstract functions, just use a simple substitution method, know f(x)+f(-x)=2, so that x=x-2 gives f(x-2)+f(-x+2)=2, that is, f(2-x)+f(x-2)=2 and this obtains.

The first one. The first one. The first one. The first one.

Simple calculations can be performed with the allocation rate. 1. Make up the decimal number into an integer, so that the value obtained is also an integer.

2. Remember to add more (or) numbers after rounding, and reduce or (increase) in the question.

3. Calculate the results separately with the distribution rate.

4. Finally, remember to check the calculation to ensure that the operation is accurate.

First of all, if this number is a multiple of 5, the number on the single digit can only be 5 and 0, and because this number is an even number, then the number on the single digit of this number can only be 0, and because the number of the hundred digit is 2, and the sum of the digits on each digit is 7, then the number on the ten digit is: 7-2-0=5, so this number is 250

If the number is an even number and at the same time a multiple of 5, the single digit of this three-digit number can only be 0Then this number is 250, because the sum of the digits on each digit of this three-digit number is 7

The calculator calculates the results below.

If the root number 2 is not approximated, the result is correct.

What's the topic? Where are the points b and f? Where is it? Where is the rectangular pgbf?

The last calculation [80-60*( 2 2)] 2=1, the original calculation is not wrong, but this calculation in junior high school generally retains the root number instead of approximating the value, otherwise points will be deducted.

By calculator: s moment = (80 30 2).

Rounded: = 1412 m

What, when the time comes, it's too big for math alone.

If you are parallel, you may wish to make the straight line 3x-4y+a=0

(-2,3).

Substitution and output a=18

So it's 3x-4y+18=0

Vertical. So it can be set to 4x+3y+b=0

(-2,3).

So find b=-1

So it's 4x+3y-1=0

Let x-100=m and 99-x=n

Then: m+n=(x-100)+(99-x)=-1=> m+n) =1) =1

m Equilibration +2mn+n =1

It is known that m or front + n = 25, and the shirt is cleared into the above formula: 25 + 2mn = 1 = > 2mn = -24

mn=-12

i.e.: (x-100)(99-x)=-12

So, (x-100)(x-99)=12

Let a=x-100, b=x-99

Then the title hall can be turned into a +b =25, find ab=? Dress up and disperse.

a-b=(x-100)-(x-99)=1

a-b)²=a²+b²-2ab=25-2ab=12ab=24

ab = 12 i.e. (x-100) (x-99) = 12