Help me write 45 equations for chemical reactions

2h2+o2 === 2h2o

c + o2 === co2

c + co2 === 2co

2c + o2 === 2co

2co + o2 === 2co2

cao + co2 === caco3

fe + o2 === feo

4fe + 2o2 === 3fe2o3

4feo + o2 === 2fe2o3

2zn + o2 === 2zno

Example 10 is enough... 45 is too much. Anyway, there are a lot of similar ones.

1.Reaction of carbon with oxygen (insufficient)2c+o2===2co reaction of carbon with oxygen (sufficient) c+o2===CO2 2Reaction of carbon monoxide with oxygen 2CO+O2===2CO2 3

Reaction of carbon dioxide with carbon CO2 + C = = = 2CO4Reaction of sodium bicarbonate with hydrochloric acid NaHCO3 + HCl = = = NaCl + H2O + CO2

5.Reaction of sodium carbonate with hydrochloric acid Na2CO3+

2hcl===

2nacl+

h2o+co2↑

6.The reaction of calcium carbonate with hydrochloric acid CaCO3+2HCl===CaCl2+

h2o+co2↑

7.Reaction of sodium bicarbonate with sodium hydroxide NaHCO3+NaOH===Na2CO3

h2o8.Reaction of sodium carbonate with calcium hydroxide Na2CO3 + Ca(OH)2===CaCO3+

2naoh9.Reaction of sodium bicarbonate (small amount) with calcium hydroxide NaHCO3+Ca(OH)2===

caco3↓+naoh+

Reaction of H2O sodium bicarbonate (excess) with calcium hydroxide 2NaHCO3 + Ca(OH)2===

caco3↓+na2co3+2h2o

10.Sodium bicarbonate heating reaction 2NaHCO3===Na2CO3+

h2o+co2↑

a+b===c+d or a+b===c, e.g. 2h2

O2 = Ignition = 2H2O

Note: Only the answer indicates the reaction conditions, Li He, with the direction of the first mountain, Chi Ping and the arrow.

ab==c,, as in 2h2

O2 = Ignition = 2H2O

Take care to indicate the reaction conditions and trim.

Give me your email address, I have a junior high school chemistry equation here, send it to you.

ch2=ch2 + br2 --ch2brch2br

C6H6 + CH 3CH --Urge grip agent) --C6H5-CH=CH2

c6h6 + br2 --febr3)--c6h5br + hbr

C6H6 + Ho-NO2 -- concentrated sulfuric acid, heated) -- C6H5-NO2 + H2O

2C2H5OH + 2NA -- Take the pants 2C2H5ONA + H2 (Simplified Chinese).

2C2H5OH + O2 --Cu, heated) --2CH3CHO + 2H2O

CH3COOH + C2H5OH <-concentrated sulfuric acid, heated) --CH3Cooch2CH3 + H2O

1. Na2CO3 + BaCl2 = BaCO3 + 2NaCl2, Na2CO3 + BA (OH) 2 = BaCO3 + 2NaOH3, NaOH + CO2 = NaHCO3 (a small amount of sodium hydroxide) 2NaOH + CO2 = Na2CO3 + H2O (sodium hydroxide excess).

Na2CO3 + BaCl2 == BaCO3 precipitation + 2NaCl1, if the ratio of NaOH to CO2 is 5:9, then the excess CO2 can be judged, which can be directly expressed by this equation:

naoh + co2=nahco3

2. If the ratio of CO2 to NAOH is 5:9

Then the reaction can be seen as a two-step process.

Step 1: NaOH + CO2 = NaHCO3 reacts with remaining NaOH (9-5 = 4 parts).

Then the reaction occurs: NaHCO3 + NAOH=Na2CO3 + H2O reacts 4 parts of NaHCO3, and the remaining (5-4=1 part) NaHCO3 has two final products, NaHCO3 and Na2CO3, their ratio is 1:4 can also be written as a general equation:

9NaOH+5CO2=4Na2CO3+NaHCO3+4H2O is a metathesis reaction that produces BaCO3 insoluble species, so the chemical equation of the reaction is:

The Na2CO3 + Ba(OH)2==BaCO3 +2NaOH ion equation is:

The CO32- +Ba2+ == BaCO3 ion equation is a better reflection of the nature of the reaction.