Ducks and rabbits have 45 heads and 146 feet in the same cage, and there are many ducks and rabbits

This question gives a total of 45 ducks and rabbits. If we assume that all 45 of these are rabbits, there should be 180 legs. And this question only tells us that there are 146 feet, and I calculated that 180 feet are 34 feet more than the actual one.

That's because 1 duck has 2 legs, and we count it as 4 legs. If 1 duck is exchanged for 1 rabbit, we have to lose 2 legs, then, how many 2 legs are contained in 34 feet, that is, how many ducks we take as rabbits, obviously, 34 2 17 (only). So there are 17 ducks and 28 rabbits.

Suppose x ducks, then rabbits are 45-x. So, the number of their legs is: 2x+(45-x)*4=146, and the solution is x=17, that is, if there are 17 ducks, then there are 45-17=28 rabbits. Complete.

If the cage is full of rabbits, there should be 180 legs, but the actual number is only 146, the difference is 34,34 (4-2) = 17 ducks and 28 rabbits.

Let the ducks be x and the rabbits y x+y=45 2x+4y=146 x=45-y bring x=17 y=28 ducks and 28 rabbits.

A rabbit has 112 feet out of 28, and a duck has 17 feet with 34 legs. 28*4 Rabbit + 17*2 Duck = 146 legs.

The duck has 2 legs and the rabbit has 4 legs.

If they are all ducks, then there are 16 2 = 32 feet, which is actually 46 feet, and there are 46-32 = 14 feet more, and the extra is the extra rabbit, so the rabbit is 14 2 = 7, and the duck is 16-7 = 9.

46-16x2) (4-2).

46-32) 2

7 (only) 16-7 9 (only).

A: There are 9 ducks and 7 rabbits.

Set x duck y rabbit x + y 162x + 4y = 46 to solve this equation.

y=7x=9

7 rabbits, 9 ducks.

Ducks have only 2 legs each, and rabbits have 4 legs, with a difference of 2 feet each.

16 are ducks, then 32 feet, 46 32, so much difference, then every 2 is a rabbit. Rabbit:

Summary. Hello, glad to answer for you. The duck has 2 legs and the rabbit has 4 legs.

If they are all ducks, there are 16 2 = 32 feet, in fact, 46 feet, 46-32 = 14 feet, the extra is the extra rabbit, so the rabbit is 14 2 = 7, the duck 16-7 = 9 only hope that the small can help you, thank you for your support and questions, I wish you a happy life!

Ducks and rabbits have a total of 16 heads and 40 legs, how many ducks and rabbits are there.

You regret it, and I'm happy to answer for you. Duck 2 feet, rabbit 4 feet If they are all ducks, then there are 16 2 = 32 feet, in fact, 46 feet are fierce, 46-32 = 14 feet to change the front bridge, the extra is the rabbit more, so the rabbit is 14 2 = 7, the duck 16-7 = 9 only hope that the small degree can help you, thank you for your support and questions, I wish you a happy life! Thank you.

There are 18 heads and 50 legs in total for ducks and rabbits, so how many rabbits and ducks there are.

Hello, glad to answer for you. Rabbits (50-18x2) (4-2) = 7 (chickens) 18-7 = 11 (chickens).

The rabbit is 4 legs, the chickens and ducks are two legs, the square imitation grip Cheng 1 x + y + z = 30 equation 2 x + 2y + 4z = 72 square preparation infiltration Qingcheng three x = 3y solution shout type chicken 12 ducks, 4 rabbits 14.

Summary. Let the number of chickens be x, the number of ducks be y, and the number of rabbits be z. According to the question, the following two equations can be obtained:

x + y + z = 35 (the total number of chickens, ducks and rabbits is 35) 2x + 2y + 4z = 98 (the total number of feet of chickens, ducks and rabbits is 98, where the number of chickens' feet is 2x, the number of duck's feet is 2y, and the number of rabbit's feet is 4z) Simplify the first equation to z = 35 - x - y, and substitute it into the second equation, yielding: 2x + 2y + 4(35 - x - y) =982x + 2y + 140 - 4x - 4y = 98-2x - 2y = 42x + y = 21 will x + y = 21 is substituted into the first equation and we get: 21 + z = 35z = 14 Therefore, the number of chickens is x = 8, the number of ducks is y = 13, and the number of rabbits is z = 14.

There are chickens, ducks and rabbits in a cage with a total of 35 heads and 98 legs, and the chickens are twice as large as the ducks, and the chickens, ducks and rabbits are the same number.

Let the number of chickens be x, the number of ducks be y, and the number of rabbits be z. According to the problem, we can get the following two equations: x + y + z = 35 (the total number of chickens, ducks and rabbits is 35) 2x + 2y + 4z = 98 (the total number of feet of chickens, ducks and rabbits is 98, where the number of chicken's feet is 2x, the number of duck's feet is 2y, and the number of rabbit's feet is 4z) The first equation is reduced to z = 35 - x - y, and the second equation is substituted into this equation to obtain:

2x + 2y + 4(35 - x - y) = 982x + 2y + 140 - 4x - 4y = 98-2x - 2y = 42x + y = 21 Substituting x + y = 21 into the first equation gives the following results: 21 + z = 35z = 14 Therefore, the number of chickens is x = 8, the number of ducks is y = 13, and the number of rabbits is z = 14. Good.

Summary. Ducks, rabbits.

Ducks and rabbits have a total of 22 heads and 55 legs, how many ducks and rabbits are there?

Hello to you, I am the co-teacher of the question, Mr. Xiao Kai Potato Gao, who is good at junior high school and college education, and has been engaged in the education industry for 10 years, and I am very happy to serve you. Please wait patiently, about 5 minutes.

Ducks, rabbits.

Ducks and rabbits have a total of 22 trillion heads, 55 legs, please ask how many ducks and how many rabbits to solve the problem set ducks x, then rabbits 22-x 2x+4(22-x)=552x+88-4x=5588-2x=552x=33x=rabbits.

There is a problem with the question, please check the question.

Suppose there are x ducks and rabbits have y, then the equation x+y=12, a duck has 2 feet, a rabbit has 4 feet, and you can guess the object with 2x+4y=40, according to these two equations, the solution is: x=4, y=8, therefore, there are 4 ducks, there are 8 rabbits, and the rabbit's feet are 8 4=32.

Before doing this, it is important to know that there is a hidden condition: each duck has 2 legs, and each rabbit has 4 legs.

Method 1Ducks and rabbits each subtract half of the feet, the rest of the total 11 feet, the remaining duck one head and one foot, rabbit one head and two feet, the number of feet minus the number of heads, that is, the number of rabbit heads, 11-7 = 4, there are 4 rabbits, then there are 3 ducks.

Method 2Solution: If there are x ducks, then rabbits have (7-x) 2x+4(7-x)=22

2x+28-4x=22

2x-4x=22-28

2x=-6x=3 (only).

A: There are 3 ducks and 4 rabbits.