Format of 6th Grade Math Research Report!! Hurry, hurry, hurry!! Come on! Good Samaritans help! 20

You look up the format of the research report this, and the first one that will appear will appear "The format of the research report knows".

It seems to be yes, I don't know, you can try it.

It should work.

Look.

Mathematics Thematic Research Report Format.

Cover part: Mathematics special research report.

Subject: Mathematics.

Grade: Year 1.

Class: Class.

Score: No.

Name:Name of work:

Key words: , up to three).

Textual part: 1. Motivation for research.

II. Purpose of the Study.

3. Research equipment and equipment.

4. Research process or methodology.

5. Findings.

6. Discussion.

VII. Conclusions.

8. References and Others.

Writing instructions: 1 All research reports should be typed and printed on A4 size paper from left to right.

2 The content uses numbers (headings) in the order of one, (one, (1).

Chinese is arranged according to the number of strokes; Western languages are listed in alphabetical order;

If Chinese and Western are juxtaposed, Chinese followed by Western.

References, if any.

a.Periodicals**, which can be written in the following order:

1) Author: (2) Year of publication, (3) Title, (4) Name of journal, (5) Volume, (6) Number of pages.

b.Books can be written in the following order:

1) Author: (2) Title: (3) Edition: (4) Place of Publication: (5) Publishing House: (6) Number of Pages: (7) Year of Publication.

Remarks:1One assignment should be submitted on October 29 and December 31 and included in the semester grade.

2.Please write a research report (not a book report).

Question 1: cubic centimeters).

Question 2: The glass area of the cube fish tank: 5 5 6 = 150 (square decimeters).

The glass area of the cuboid fish tank: 6 4 + (6 5 + 4 5) 2 = 124 (square decimeters).

Cube fish tank can hold water: 5 5 5 = 125 (cubic decimeter) = 125 (liters) Cube fish tank can hold water: 6 4 5 = 120 (cubic decimeter) = 120 (liters) Cube fish tank can hold more water. More 125-120 = 5 (liters).

1. s=1 cubic centimeter.

2. S cube fish tank 5x5x5 = 125 square decimeters S rectangular fish tank 6x4 + (6x5 + 4x5) x2 = 24 + 100 = 124 square decimeters.

This is the formula for the cone: v=1 3( r 2 * h)r is the radius of the base, h is the height of the cone, r 2 is r squared, * is multiplied in simple terms: 1 3 * base area * height.

Area formula: If the radius is r, then the area is s= r 2

The base area is: is pi, which means then infinite loop, generally taken.

2.……I forgot about this, but I can't even ...... elementary school questions as a junior high school studentDirectly copied:

S cube fish tank 5x5x5 = 125 square decimeters.

S cuboid fish tank 6x4 + (6x5 + 4x5) x2 = 24 + 100 = 124 square decimeters.

Square: Area: 5 * 5 * 5 = 125 square decimeters.

Volume: 5 3 = 125 cubic decimeters (liters).

Rectangle: Area: 6 * 4 + 6 * 5 * 2 + 4 * 5 * 2 = 124 square decimeters Volume: 4 * 5 * 6 = 120 cubic decimeters (liters).

The cube holds a lot of water, which is 125 liters.

/3*9*4*4*π=48π

2. Square: area: 5 * 5 * 5 = 125 square decimeters Volume: 5 3 = 125 cubic decimeters (liters).

Rectangle: Area: 6 * 4 + 6 * 5 * 2 + 4 * 5 * 2 = 124 square decimeters Volume: 4 * 5 * 6 = 120 cubic decimeters (liters).

The cube holds a lot of water, which is 125 liters.

1.Cone volume = base area * height 3 = *4 * 4 * 9 3 = 48 2Square surface area = 5 * 5 * 5 = 125

Rectangular surface area = 4 * 5 * 2 + 6 * 5 * 2 + 6 * 4 = 40 + 60 + 24 = 124

So the square holds a lot of water.

The volume of the cone = the base area * height 3, then the volume of the cone is 9 * 16 3 = 48 cubic centimeters.

5*5*5=125 square decimeters of glass for cuboid fish tanks, (6*5+4*5)*2+6*4=124 square decimeters of glass for cuboid fish tanks.

The cube fish tank holds 5 * 5 * 5 = 125 cubic decimeters, the rectangular fish tank holds 6 * 4 * 5 = 120 cubic decimeters, and the cube fish tank holds more water, 5 liters more.

（8÷2）² 9×1/3×

Square glass: 5 5 5 = 125 (cm) Is there a requirement for rectangular glass?

Square water: 5 5 5 = 125 (cm).

The first problem is to find the radius first, and then the volume.

The second question, even if the area and volume, don't you?

1;This length is the circumference of the semicircle, let the diameter be d, so there is the circumference of the circle, and the semicircle is divided by 2 plus the diameter d, that is: d + from this is obtained, d = 4Then the radius r=2 and the area of the semicircle s= square meters.

2.If the reciprocal of two prime numbers is added up, and the numerator of the sum is 25, then the sum of the two prime numbers is 25. It is known to be 23 and 2

3.The least common multiple is 630, the greatest common divisor is 18, and the two numbers are not divisible by each other. These 2 numbers are multiples of 18 and divisors of 630.

And the two numbers are not divisible by each other, and 630 is 35 times the relationship of 18, one is 5 times and the other is 7 times, so it is 126 and 90 (think about it).

4.Set the whole factory as a unit of 1, the male worker in the apprentice is x, the apprentice is x The master is 1-x, the master male worker (1-x, the male worker of the master + apprentice: x + (1-x, find x =, the master is the apprentice, the ratio is 1:4

5.Let the small rectangle be wide x and long y, and look at the figure as: 2y=3x, (2y+y+x)*2=44 Find: x= 4, y=6

The length of the large figure is 12 and the width is 12.

Good luck and good luck!

1。Enclose a semicircle with a meter of rope, and the area of this semicircle is ( ).

Solution: Let the radius of this semicircle be r meters, then:

Solution: r=2m

The area of this semicircle is:

sq.m.2. Add the reciprocal of two prime numbers, and the numerator of the sum is 25 and the denominator is (46).

Solution: Let the two prime numbers be a and b respectively, then: 1 a+1 b=(b+a) ab=25 ab

Then: ab=2*23=46

r=2s=square meters.

x+y=25

x,y are prime numbers.

So it's 2+23, so the denominator is 2*23=46

3.Greatest common divisor * least common multiple = product of two numbers = 630 * 18 = 2 * 2 * 5 * 63 * 9 = 2 * 2 * 3 * 3 * 3 * 3 * 5 * 7 = 18 * 5 * 18 * 7

So one is 18*5=90 and one is 18*7=1264Set apprentice x, master y, get y x=1 4

5.Let a small rectangle rectangle a

44=4a+5/3*2a=（22/3）a

So a = 6s = 2a * (a + 2 3a) = 10 3a 2 = 120 square centimeters.

1。Enclose a semicircle with a meter of rope, and the area of this semicircle is ( ).

Let the radius be x2x+(2x

If x=2, then the area of the circle = 2 2, so the area of the semicircle is.

2。Add the reciprocal of two prime numbers, and the numerator of the sum is 25 and the denominator is (46).

The reciprocal addition and the numerator of sum is 25, that is, the addition of these two numbers gives 25, only 23+2

So 1 23 + 1 2 = 25 46

3。Two natural numbers, the least common multiple is 630, the greatest common divisor is 18, and the two numbers are not divisible from each other, these two numbers are ( ).

4。In a factory, 80% of the apprentices are men, 90% are men, and 82% are men, so the ratio of the number of masters and apprentices is (1 4).

There are x masters and y apprentices.

90% x+80% y) (x+y)=82%, and the solution is x y=1 4

5。Graphical questions (below).

The figure below is to use 5 rectangles to form a large rectangle, the circumference of the large rectangle is 44 cm, and the area of the large rectangle is found.

As can be seen from the figure, the width of a small rectangle is 2 3 long

Let the length of the small rectangle be x, and the width of the small rectangle will be 2 3 x

(2x+x+2 3x)=44

If x=12, then the area of the large rectangle = (12+12) (12+2 3 12)=480cm

(The circumference of the semicircle is half the circumference of the circle + the diameter of a strip).

The two prime numbers are 2,3

and 90:4

2.Because the two numbers add up to 25, one number is 2 and the other is 233Let the two numbers be a and b

So a=18*5=90, b=18*7=126 set apprentice x person, master y person, so x = 4y

5.The area is 120

Let the length of the small rectangle be a and the width be b

2a=3b,(2a+a+b)*2=44

a=6,b=4 The area of the large rectangle is 120

It's too much, and I don't have to do it. Hehe.

10×=18+26+

[Coincidentally, we also have this homework, I'm pretty sure].

The water fee for 10 square meters is 18 yuan, the second 10 square meters are 26 yuan, and 18<<18+26, so the water is used in 10 20 square meters.

So it took 16 squares.

(10 If you don't count, you're doing the math yourself.)

The cross-section is square, and there are 2 equal squares and 4 equal rectangles.

The base area is 10 square centimeters, then 4*10=40 (square centimeters) the area of a square; (48-40) 2 = 4 (square centimeters) height: (2) * (2) = 4

Volume: 10*2=20 (cubic centimeters).

The least common multiple of 12 and 15 is 60, 60 + 1 = 61 students, so at least 61 students are required.

The least common multiple is 60

A minimum of 60 students should be selected to participate in the grade cohort.

The least common multiple of 12 and 15 is 60 plus 1 leader.

A minimum of 61 students are selected to participate in the grade cohort.

Least common multiple of twelve and fifteen, 60. Plus the leader 1, 60 plus 1 equals 61 people.

12 = 3 * 4, 15 = 3 * 5 3 * 4 * 5 = 60 people, plus 1 team leader is 61 people, please adopt.

(x -y +1) 2 is greater than (x -2y +1) 3 can be arbitrarily set how much x is and what y is.

I set it to x=3 y=2

9-4+1) divided by 2=3

9-8+1) divided by 3=2 3

So (x -y +1) 2 is greater than (x -2y +1) 3

Solution: Let x be 1 and y be 2.

Then bring the numbers into the equation and compare the size of the results.

Multiply the first one by 12, and multiply the second by 9 to compare.