Physics experts help me!! Physics Masters help!

Personally, I don't think it's realistic to use a pressure cooker, one is that this pressure cooker requires a lot of pressure, and the other is that it's too dangerous.

If it can be driven, it is obvious that this pressure cooker is not an ordinary pressure cooker, an ordinary pressure cooker can only hold up a small hammer with a mass of less than a kilogram, and here it is to be used as a powerful power device. Then it needs to be very hot, and the vent must be large enough, because f=ps, s can increase f, of course, if you want to change the appearance, the estimated shape can not be called a pressure cooker. If you burn it with coal or wood, you don't know how big the fuel tank will be if you want to keep the bike going.

There is also the "circulatory system" mentioned by a friend above is also the key to the problem, this is not enough to achieve the above equipment, how to achieve it, I don't learn this, I don't understand.

As for the specifications of the screwdriver in the back, in fact, the power problem in the front should also be taken into account, if it can generate a large enough driving force, then the specification of the screwdriver should not be a problem.

This can be started but does not work continuously.

Because the pressure cooker pneumatic screwdriver system is structurally different from the steam engine, i.e., there is thermal convection, but there is no circulation system, and the compressor and chiller are missing, and the steam will continue to leak until it is not enough to maintain power.

The specific force is not very clear, but it is obvious that the screwdriver is slightly overcompressed, and the friction coefficient of the bicycle should be about the same, just measure the wheel.

How do you get the pressure cooker to steam?

Your method is not viable.

The powertrain is theoretically fine, but it's too dangerous, and the air pressure may not be up to the mark, and even if it does, your pressure cooker will become a bomb.

Your drivetrain has the most serious problems, and it is estimated that your screwdriver root cannot directly withstand that much torque. Only a connecting rod device can be used to solve the torsion problem.

The pressure cooker felt a little smaller, so I didn't count it.

1 All 1, the current is numerically equal to the voltage passing through the cross-section of the conductor in 1s.

2. The voltage between the positive and negative poles of the power supply can make the positive charge in the circuit flow from the positive electrode to the negative electrode or make the negative charge in the circuit flow from the negative electrode to the positive electrode, so that a current is formed in the circuit.

1. Number of electrons; 2. Positive and negative poles, negative poles of power supply, positive poles of power supply, current circuit.

(1) Pay attention to the sentence "quickly lengthen 20cm", indicating that the rope tension has been removed, the ball does centrifugal motion, the ball will move to B at a uniform speed along the tangential AB direction, in the right-angled triangle OAB, r =, then d = (r' -r )=, so the transition time t is t = d v =

2) As can be seen from the figure, the instantaneous velocity of the ball just moving to point B v=1m s, along the AB direction, at this moment, the string is suddenly tensioned along the ob direction, and the minute velocity along the ob direction suddenly disappears, and the ball will move in a uniform circular motion with tangential velocity, which can be obtained from the similar triangles in the figure.

v1=3v/5=，ω=v1/r1=

3) After the radius increases, the external pull force on the rope provides the centripetal force of the ball, f=m r1=2kg (satisfied.

p·v=p‘·v’

p=19mpa v= p'= v' 76l should be discharged as v' v equal to divide by 54 minutes of time taken.

Gotta calculus. The pressure of the gas emitted varies from moment to moment.

And, in fact, when the pressure of the cylinder is high, it is obviously necessary to deflate quickly, unless the expert specially designs this exhaust valve.

Take 20MPa

20mpa=200atm

pv=nrt

t should not take into account the effect of gas work, i.e. constant, room temperature.

There are two states:

Filled: 200*

End: 1 * Synthesis: n1 = 200n2

That is, 199 volumes of oxygen were discharged.

v=199*, fast read.

t=v/v=

The calculation of the maximum and minimum values is the same as above, but the data is different.

p*v is a fixed value, so the volume of oxygen in this bottle at atmospheric pressure is: , so the time to put it out is about 80.