Elementary School Mathematics Olympiad Itinerary Questions Please help 5

1. Pursuit problem Time * Speed difference = difference distance.

Because I didn't catch up, I missed 4 kilometers, so the difference was (64-4).

64-4) = (25 - 15) * time.

Time = 6 minutes plus half a minute of battle, so that's a total of 6 and a half minutes.

2. It is also a matter of pursuit.

Because the motorcycle was repaired for 1 hour, which is equivalent to the motorcycle leaving 1 hour later, the distance difference is (70 + 20 * 60)Note: I think you wrote the wrong time unit of speed, 20 kilometers per minute? Is it a bicycle? Isn't it all per hour?

I'm going to calculate the speed in terms of hours.

70 + 20 * 1) = (50 - 20) * time.

Time = 3 hours.

So, the distance traveled by a motorcycle is 3 * 50 = 150 km, and the distance traveled by a bicycle is (3+1)*20 = 80 km.

3. Counting from the time they met, B catches up with A 20 minutes later, indicating that A walked 80 minutes before + 20 minutes after the first meeting, that is, A walked 100 minutes, B walked for 20 minutes, and explained that the speed ratio of 2 people is A: B = 1:5, you may wish to let A walk 1 meter in minutes B walks 5 meters per minute, then the distance between A and B can be solved This problem can be solved.

4. You made a mistake again How can you catch up with the PLA 60 km h and the communicator 36 km h? Take a closer look at the question, no, draw a picture, think about it more.

1. Solution: 64-4=60 (km).

25-15=10 (km).

60 10 = 6 (points).

6+ points) A: There are minutes during this period.

2. Solution: (70+20) (50-20)=3 (hours) 3+1=4 (hours).

50*(4-1)=150 (km).

20*4=80 (km).

A: The motorcycle walked 150 kilometers and the bicycle traveled 80 kilometers.

3. Solution: Let the total length be 1600 meters.

1600 80 = 20 (mm).

20 80 * 1600 = 400 (m).

1600-400) 400 = 3 (times).

A: Caught up with A 3 times.

Kilometers chasing 60 kilometers per hour? Can't catch up, you say.

Is it the other way around? The other way around, it is.

36*10 (60-36)=15 (hours).

A: 15 hours to catch up with the team.

1) (64-4) (25-15) + points).

Pursuit distance, speed difference, enemy annihilation time.

2) (70 + 20) (50-20) = 3 (min) Is it an hour?? Total distance (1 hour more on your own) Difference in speed.

3x50=150(km) 3x20=60(km)3) The proposal is not clear?? Did you say it 1 time in the question??

4) 36 and 60 reversed? If yes:

36x10 (60-36) = 15 (hours).

It's simple, it's a third or fourth grade???

2.Find the time of the encounter first, and set the time to x (the unit seems to be problematic).

50(x-1)+20x=70

After solving x, you can calculate 50 (x-1) and 20x, respectively.

Question 1: 64-4 = 60 km 25-15 = 10 km 60 10 = 6 minutes 6 minutes + half minutes = 6 and a half minutes Answer: It takes 6 and a half minutes.