5th Grade Olympiad Problems Itinerary Problems

Updated on educate 2024-02-10
11 answers
  1. Anonymous users2024-02-06

    100รท1=100s

    4 x 10 3 x 10

    So, 40+100=140s

    Convert to minutes: 140 60 = infinite decimal number).

  2. Anonymous users2024-02-05

    Solution: Run 4 meters per second every day, run 100 meters and rest for 10 seconds, actual time = 100 4 + 10 = 35 seconds.

    Actual velocity = 100 35 m s, in the same way, cloud velocity = 100 30 m sec.

    Yunyun catches up with the daily time 100 (100 30-100 35) = 210 seconds Thank you very much for the friends downstairs, is it so that the least common multiple of 30 and 35 is 210, then the two people are resting together in the last 10 seconds, so it needs to be corrected, minus the 10 seconds of the rest wind, it is 200 seconds, at this time 6 times a day, 60 seconds, travel = 4x150 = 600 meters, cloud travel = 5x140 = 700 meters, Yunyun is just 100 meters more, catch up with every day. Thank you downstairs!

  3. Anonymous users2024-02-04

    Suppose Yunyun catches up in the xth second after resting n times.

    I took n+1 breaks every day.

    Yunyun took one less break, ran 10 seconds more, which is 25 meters, and the remaining 75 meters, it took two people to run for 75 seconds at the same time, and Yunyun had to rest three times for 30 seconds, for a total of 105 seconds.

  4. Anonymous users2024-02-03

    78101557 is wrong, because running + resting is not the same as running at a constant pace.

    210 seconds means that Yunyun rested 7 times, 6 times a day, and it was the time that he had just rested, so the time to catch up should be 200 seconds, and then he rested together for 10 seconds.

  5. Anonymous users2024-02-02

    1. Jingjing walks to school every morning, and if she walks 60 meters per minute, she will be 5 minutes late; If you walk 75 meters per minute, you can arrive at school 2 minutes early. Ask for Jingjing's journey to school.

    2. A, B, and C walk in three people, A walks 60 meters per minute, B walks meters per minute, and C walks 75 meters per minute. A and B went from East Town to West Town, and C went from West Town to East Town, and the three of them set off at the same time, and after C and B met, they met A after 2 minutes. How many meters is the distance between the east and west towns?

    3. A and B two cars at the same time from the two stations of A and B are opposite each other, the two cars meet for the first time at 32 kilometers away from station A, and the two cars continue to drive after meeting, and after arriving at the two stations of B and A, they immediately return along the same road, and meet at 64 kilometers away from station A for the second time. How many kilometers are there between stations A and B?

    4. On the circular runway with a circumference of 400 meters, there are two points of A and B that are 100 meters apart, A and B run away from each other at the same time from A and B, and after the two meet, B turns around and runs in the same direction as A, and when A runs to A, B happens to run to B. If the speed and direction of A and B run the same in the future, how many meters did A run (from the time of departure) when catching up with B?

    5. Lao Wang rode a bicycle from City A to City B to run errands, riding 15 kilometers per hour, and when he came back, he changed to riding a motorcycle, riding 33 kilometers per hour, and riding a motorcycle was less than riding a bicycle for hours. Find the distance between cities A and B.

    6. The speed is fast, medium and slow three cars start from the same place at the same time, along the same highway to catch up with a cyclist in front, these three cars respectively use 6 minutes, 10 minutes, 12 minutes to catch up with the cyclist, now know that the fast car travels 24 kilometers per hour, the car travels 20 kilometers per hour, so how many kilometers does the slow car travel per hour?

    7. On the circular runway, when both of them run in a clockwise direction, they meet once every 12 minutes when the car is missing. If the speed of the two people remains the same, one of them will run in a counterclockwise direction and meet every 4 minutes. Q: How many minutes does it take for two people to run a lap each?

  6. Anonymous users2024-02-01

    Classic distance problem.

    Draw a line diagram and take a look.

    The first time they met, A and B traveled a total of 1 whole course.

    Among them, A traveled 90 kilometers.

    The second encounter, A and B traveled a total of 3 whole courses.

    Among them, A traveled 2 whole journeys minus 50 kilometers.

    A and B traveled a total of 3 whole journeys, and the time taken was 3 times that of a total of 1 full journey, and A should have traveled 90 3 = 270 kilometers.

    That is, 2 full journeys minus 50 km equals 270 km.

    AB distance is: (270+50) 2=160 km.

  7. Anonymous users2024-01-31

    430 4-(90 2)=40 (kmh). B speed is 40 km/h.

    2: 2 encounters and a total of 2 full journeys of Yuanqing, with a distance difference of 1 km. The first encounter is a total of 1 full course. The distance difference is 1 2 = km. Speed difference = 1 km.

    Speed sum = 8 km/h when the small orange wheel is held.

    Xiao Ming = (16 + 1) 2 = kilometers Hours... Tong blind. Velocity.

  8. Anonymous users2024-01-30

    According to the title, Wang Ming and his sister both travel at a speed of 50 meters per minute, and they are walking in opposite directions. When Wang Ming and his sister were 10 meters apart, the total distance they covered was 300-10=290 meters, and the time it took was 290 (50+50)=minutes. In this process, the puppy has been running back and forth between them at a speed of 200 meters per minute, and the puppy has run a total of 200* meters in the process.

  9. Anonymous users2024-01-29

    When they were 10 meters apart, they ran a total of 300-10=290 meters, which is their total distance.

    Their total speed is 50 + 50 = 100 m min.

    That is, when 10 meters apart, a total of 290 100 points were used.

    During this time, the puppy has been running at a speed of 200 meters per minute, which is 200 * (290 100) = 580 meters.

  10. Anonymous users2024-01-28

    Wang Ming and his sister walked a total of 290 meters.

    It takes them to walk 290: 290 (50 2) = minutes.

    During this minute, the puppy does not stop running, he keeps moving, so the distance traveled by the puppy is time speed = meters.

  11. Anonymous users2024-01-27

    On the way, car A stopped for 4 hours, and car A arrived at the destination 1 hour later than car B, which means that car A traveled 4-1=3 hours less than car B.

    So A did 9*3 (12-9) = 9 hours.

    The distance between the two places is 12*9=108 kilometers.

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